TSTP Solution File: SWW400-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SWW400-1 : TPTP v8.1.0. Released v5.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:22:30 EDT 2022

% Result   : Unsatisfiable 1.95s 2.12s
% Output   : Refutation 1.95s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   16 (  11 unt;   1 nHn;  14 RR)
%            Number of literals    :   23 (   4 equ;  10 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   4 con; 0-2 aty)
%            Number of variables   :   25 (   8 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ heap(sep(next(nil,A),B)),
    file('SWW400-1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ heap(sep(lseg(nil,A),B))
    | A = nil ),
    file('SWW400-1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ heap(sep(next(A,B),sep(lseg(B,C),D)))
    | A = B
    | heap(sep(lseg(A,C),D)) ),
    file('SWW400-1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ heap(sep(lseg(A,B),sep(lseg(B,nil),C)))
    | heap(sep(lseg(A,nil),C)) ),
    file('SWW400-1.p',unknown),
    [] ).

cnf(14,axiom,
    ~ heap(sep(lseg(x1,nil),emp)),
    file('SWW400-1.p',unknown),
    [] ).

cnf(17,axiom,
    sep(A,sep(B,C)) = sep(B,sep(A,C)),
    file('SWW400-1.p',unknown),
    [] ).

cnf(19,axiom,
    sep(lseg(A,A),B) = B,
    file('SWW400-1.p',unknown),
    [] ).

cnf(20,axiom,
    heap(sep(next(x2,nil),sep(lseg(x1,x2),emp))),
    file('SWW400-1.p',unknown),
    [] ).

cnf(92,plain,
    ~ heap(sep(lseg(nil,x2),A)),
    inference(unit_del,[status(thm)],[inference(para_into,[status(thm),theory(equality)],[20,2]),1]),
    [iquote('para_into,20.1.1.1.1,2.2.1,unit_del,1')] ).

cnf(202,plain,
    ~ heap(sep(A,sep(lseg(nil,x2),B))),
    inference(para_into,[status(thm),theory(equality)],[92,17]),
    [iquote('para_into,92.1.1,17.1.1')] ).

cnf(246,plain,
    ( ~ heap(sep(A,sep(lseg(nil,B),C)))
    | ~ heap(sep(next(x2,B),sep(lseg(B,D),E)))
    | heap(sep(lseg(x2,D),E)) ),
    inference(para_into,[status(thm),theory(equality)],[202,6]),
    [iquote('para_into,202.1.1.2.1.2,6.2.1')] ).

cnf(273,plain,
    ( ~ heap(sep(next(x2,nil),A))
    | heap(sep(lseg(x2,nil),A)) ),
    inference(demod,[status(thm),theory(equality)],[inference(factor,[status(thm)],[246]),19]),
    [iquote('factor,246.1.2,demod,19')] ).

cnf(785,plain,
    heap(sep(lseg(x2,nil),sep(lseg(x1,x2),emp))),
    inference(hyper,[status(thm)],[273,20]),
    [iquote('hyper,273,20')] ).

cnf(786,plain,
    heap(sep(lseg(x1,x2),sep(lseg(x2,nil),emp))),
    inference(para_into,[status(thm),theory(equality)],[785,17]),
    [iquote('para_into,785.1.1,17.1.1')] ).

cnf(787,plain,
    heap(sep(lseg(x1,nil),emp)),
    inference(hyper,[status(thm)],[786,7]),
    [iquote('hyper,786,7')] ).

cnf(788,plain,
    $false,
    inference(binary,[status(thm)],[787,14]),
    [iquote('binary,787.1,14.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SWW400-1 : TPTP v8.1.0. Released v5.2.0.
% 0.03/0.13  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n024.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 03:00:25 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.95/2.12  ----- Otter 3.3f, August 2004 -----
% 1.95/2.12  The process was started by sandbox2 on n024.cluster.edu,
% 1.95/2.12  Wed Jul 27 03:00:25 2022
% 1.95/2.12  The command was "./otter".  The process ID is 5732.
% 1.95/2.12  
% 1.95/2.12  set(prolog_style_variables).
% 1.95/2.12  set(auto).
% 1.95/2.12     dependent: set(auto1).
% 1.95/2.12     dependent: set(process_input).
% 1.95/2.12     dependent: clear(print_kept).
% 1.95/2.12     dependent: clear(print_new_demod).
% 1.95/2.12     dependent: clear(print_back_demod).
% 1.95/2.12     dependent: clear(print_back_sub).
% 1.95/2.12     dependent: set(control_memory).
% 1.95/2.12     dependent: assign(max_mem, 12000).
% 1.95/2.12     dependent: assign(pick_given_ratio, 4).
% 1.95/2.12     dependent: assign(stats_level, 1).
% 1.95/2.12     dependent: assign(max_seconds, 10800).
% 1.95/2.12  clear(print_given).
% 1.95/2.12  
% 1.95/2.12  list(usable).
% 1.95/2.12  0 [] A=A.
% 1.95/2.12  0 [] sep(S,sep(T,Sigma))=sep(T,sep(S,Sigma)).
% 1.95/2.12  0 [] sep(lseg(X,X),Sigma)=Sigma.
% 1.95/2.12  0 [] -heap(sep(next(nil,Y),Sigma)).
% 1.95/2.12  0 [] -heap(sep(lseg(nil,Y),Sigma))|Y=nil.
% 1.95/2.12  0 [] -heap(sep(next(X,Y),sep(next(X,Z),Sigma))).
% 1.95/2.12  0 [] -heap(sep(next(X,Y),sep(lseg(X,Z),Sigma)))|X=Z.
% 1.95/2.12  0 [] -heap(sep(lseg(X,Y),sep(lseg(X,Z),Sigma)))|X=Y|X=Z.
% 1.95/2.12  0 [] -heap(sep(next(X,Y),sep(lseg(Y,Z),Sigma)))|X=Y|heap(sep(lseg(X,Z),Sigma)).
% 1.95/2.12  0 [] -heap(sep(lseg(X,Y),sep(lseg(Y,nil),Sigma)))|heap(sep(lseg(X,nil),Sigma)).
% 1.95/2.12  0 [] -heap(sep(lseg(X,Y),sep(lseg(Y,Z),sep(next(Z,W),Sigma))))|heap(sep(lseg(X,Z),sep(next(Z,W),Sigma))).
% 1.95/2.12  0 [] -heap(sep(lseg(X,Y),sep(lseg(Y,Z),sep(lseg(Z,W),Sigma))))|Z=W|heap(sep(lseg(X,Z),sep(lseg(Z,W),Sigma))).
% 1.95/2.12  0 [] nil!=x1.
% 1.95/2.12  0 [] nil!=x2.
% 1.95/2.12  0 [] heap(sep(next(x2,nil),sep(lseg(x1,x2),emp))).
% 1.95/2.12  0 [] -heap(sep(lseg(x1,nil),emp)).
% 1.95/2.12  end_of_list.
% 1.95/2.12  
% 1.95/2.12  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 1.95/2.12  
% 1.95/2.12  This ia a non-Horn set with equality.  The strategy will be
% 1.95/2.12  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.95/2.12  deletion, with positive clauses in sos and nonpositive
% 1.95/2.12  clauses in usable.
% 1.95/2.12  
% 1.95/2.12     dependent: set(knuth_bendix).
% 1.95/2.12     dependent: set(anl_eq).
% 1.95/2.12     dependent: set(para_from).
% 1.95/2.12     dependent: set(para_into).
% 1.95/2.12     dependent: clear(para_from_right).
% 1.95/2.12     dependent: clear(para_into_right).
% 1.95/2.12     dependent: set(para_from_vars).
% 1.95/2.12     dependent: set(eq_units_both_ways).
% 1.95/2.12     dependent: set(dynamic_demod_all).
% 1.95/2.12     dependent: set(dynamic_demod).
% 1.95/2.12     dependent: set(order_eq).
% 1.95/2.12     dependent: set(back_demod).
% 1.95/2.12     dependent: set(lrpo).
% 1.95/2.12     dependent: set(hyper_res).
% 1.95/2.12     dependent: set(unit_deletion).
% 1.95/2.12     dependent: set(factor).
% 1.95/2.12  
% 1.95/2.12  ------------> process usable:
% 1.95/2.12  ** KEPT (pick-wt=6): 1 [] -heap(sep(next(nil,A),B)).
% 1.95/2.12  ** KEPT (pick-wt=9): 2 [] -heap(sep(lseg(nil,A),B))|A=nil.
% 1.95/2.12  ** KEPT (pick-wt=10): 3 [] -heap(sep(next(A,B),sep(next(A,C),D))).
% 1.95/2.12  ** KEPT (pick-wt=13): 4 [] -heap(sep(next(A,B),sep(lseg(A,C),D)))|A=C.
% 1.95/2.12  ** KEPT (pick-wt=16): 5 [] -heap(sep(lseg(A,B),sep(lseg(A,C),D)))|A=B|A=C.
% 1.95/2.12  ** KEPT (pick-wt=19): 6 [] -heap(sep(next(A,B),sep(lseg(B,C),D)))|A=B|heap(sep(lseg(A,C),D)).
% 1.95/2.12  ** KEPT (pick-wt=16): 7 [] -heap(sep(lseg(A,B),sep(lseg(B,nil),C)))|heap(sep(lseg(A,nil),C)).
% 1.95/2.12  ** KEPT (pick-wt=24): 8 [] -heap(sep(lseg(A,B),sep(lseg(B,C),sep(next(C,D),E))))|heap(sep(lseg(A,C),sep(next(C,D),E))).
% 1.95/2.12  ** KEPT (pick-wt=27): 9 [] -heap(sep(lseg(A,B),sep(lseg(B,C),sep(lseg(C,D),E))))|C=D|heap(sep(lseg(A,C),sep(lseg(C,D),E))).
% 1.95/2.12  ** KEPT (pick-wt=3): 11 [copy,10,flip.1] x1!=nil.
% 1.95/2.12  ** KEPT (pick-wt=3): 13 [copy,12,flip.1] x2!=nil.
% 1.95/2.12  ** KEPT (pick-wt=6): 14 [] -heap(sep(lseg(x1,nil),emp)).
% 1.95/2.12  
% 1.95/2.12  ------------> process sos:
% 1.95/2.12  ** KEPT (pick-wt=3): 16 [] A=A.
% 1.95/2.12  ** KEPT (pick-wt=11): 17 [] sep(A,sep(B,C))=sep(B,sep(A,C)).
% 1.95/2.12  ** KEPT (pick-wt=7): 18 [] sep(lseg(A,A),B)=B.
% 1.95/2.12  ---> New Demodulator: 19 [new_demod,18] sep(lseg(A,A),B)=B.
% 1.95/2.12  ** KEPT (pick-wt=10): 20 [] heap(sep(next(x2,nil),sep(lseg(x1,x2),emp))).
% 1.95/2.12    Following clause subsumed by 16 during input processing: 0 [copy,16,flip.1] A=A.
% 1.95/2.12    Following clause subsumed by 17 during input processing: 0 [copy,17,flip.1] sep(A,sep(B,C))=sep(B,sep(A,C)).
% 1.95/2.12  >>>> Starting back demodulation with 19.
% 1.95/2.12  
% 1.95/2.12  ======= end of input processing =======
% 1.95/2.12  
% 1.95/2.12  =========== start of search ===========
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 14.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 14.
% 1.95/2.12  
% 1.95/2.12  sos_size=721
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 13.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 13.
% 1.95/2.12  
% 1.95/2.12  sos_size=722
% 1.95/2.12  
% 1.95/2.12  -------- PROOF -------- 
% 1.95/2.12  
% 1.95/2.12  ----> UNIT CONFLICT at   0.24 sec ----> 788 [binary,787.1,14.1] $F.
% 1.95/2.12  
% 1.95/2.12  Length of proof is 7.  Level of proof is 7.
% 1.95/2.12  
% 1.95/2.12  ---------------- PROOF ----------------
% 1.95/2.12  % SZS status Unsatisfiable
% 1.95/2.12  % SZS output start Refutation
% See solution above
% 1.95/2.12  ------------ end of proof -------------
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  ============ end of search ============
% 1.95/2.12  
% 1.95/2.12  -------------- statistics -------------
% 1.95/2.12  clauses given                 52
% 1.95/2.12  clauses generated           5034
% 1.95/2.12  clauses kept                 784
% 1.95/2.12  clauses forward subsumed     441
% 1.95/2.12  clauses back subsumed          3
% 1.95/2.12  Kbytes malloced             5859
% 1.95/2.12  
% 1.95/2.12  ----------- times (seconds) -----------
% 1.95/2.12  user CPU time          0.24          (0 hr, 0 min, 0 sec)
% 1.95/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.95/2.12  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.95/2.12  
% 1.95/2.12  That finishes the proof of the theorem.
% 1.95/2.12  
% 1.95/2.12  Process 5732 finished Wed Jul 27 03:00:27 2022
% 1.95/2.12  Otter interrupted
% 1.95/2.12  PROOF FOUND
%------------------------------------------------------------------------------