TSTP Solution File: SWW196+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SWW196+1 : TPTP v8.1.2. Released v5.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 00:25:36 EDT 2023

% Result   : Theorem 3.83s 4.03s
% Output   : Proof 3.83s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14  % Problem    : SWW196+1 : TPTP v8.1.2. Released v5.2.0.
% 0.00/0.15  % Command    : duper %s
% 0.17/0.36  % Computer : n022.cluster.edu
% 0.17/0.36  % Model    : x86_64 x86_64
% 0.17/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.17/0.36  % Memory   : 8042.1875MB
% 0.17/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.17/0.36  % CPULimit   : 300
% 0.17/0.36  % WCLimit    : 300
% 0.17/0.36  % DateTime   : Sun Aug 27 22:08:24 EDT 2023
% 0.17/0.36  % CPUTime    : 
% 3.83/4.03  SZS status Theorem for theBenchmark.p
% 3.83/4.03  SZS output start Proof for theBenchmark.p
% 3.83/4.03  Clause #0 (by assumption #[]): Eq
% 3.83/4.03    (Exists fun B_m =>
% 3.83/4.03      Eq v_na____
% 3.83/4.03        (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03          (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) B_m))
% 3.83/4.03    True
% 3.83/4.03  Clause #1142 (by assumption #[]): Eq
% 3.83/4.03    ((Exists fun B_m =>
% 3.83/4.03        Eq v_na____
% 3.83/4.03          (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03            (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) B_m)) →
% 3.83/4.03      v_thesis____)
% 3.83/4.03    True
% 3.83/4.03  Clause #1143 (by assumption #[]): Eq (Not v_thesis____) True
% 3.83/4.03  Clause #1144 (by clausification #[1143]): Eq v_thesis____ False
% 3.83/4.03  Clause #1145 (by clausification #[1142]): Or
% 3.83/4.03    (Eq
% 3.83/4.03      (Exists fun B_m =>
% 3.83/4.03        Eq v_na____
% 3.83/4.03          (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03            (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) B_m))
% 3.83/4.03      False)
% 3.83/4.03    (Eq v_thesis____ True)
% 3.83/4.03  Clause #1146 (by clausification #[1145]): ∀ (a : Iota),
% 3.83/4.03    Or (Eq v_thesis____ True)
% 3.83/4.03      (Eq
% 3.83/4.03        (Eq v_na____
% 3.83/4.03          (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03            (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) a))
% 3.83/4.03        False)
% 3.83/4.03  Clause #1147 (by clausification #[1146]): ∀ (a : Iota),
% 3.83/4.03    Or (Eq v_thesis____ True)
% 3.83/4.03      (Ne v_na____
% 3.83/4.03        (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03          (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) a))
% 3.83/4.03  Clause #1148 (by forward demodulation #[1147, 1144]): ∀ (a : Iota),
% 3.83/4.03    Or (Eq False True)
% 3.83/4.03      (Ne v_na____
% 3.83/4.03        (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03          (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) a))
% 3.83/4.03  Clause #1149 (by clausification #[1148]): ∀ (a : Iota),
% 3.83/4.03    Ne v_na____
% 3.83/4.03      (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03        (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) a)
% 3.83/4.03  Clause #1150 (by clausification #[0]): ∀ (a : Iota),
% 3.83/4.03    Eq
% 3.83/4.03      (Eq v_na____
% 3.83/4.03        (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03          (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) (skS.0 0 a)))
% 3.83/4.03      True
% 3.83/4.03  Clause #1151 (by clausification #[1150]): ∀ (a : Iota),
% 3.83/4.03    Eq v_na____
% 3.83/4.03      (c_Groups_Otimes__class_Otimes tc_Nat_Onat
% 3.83/4.03        (c_Int_Onumber__class_Onumber__of tc_Nat_Onat (c_Int_OBit0 (c_Int_OBit1 c_Int_OPls))) (skS.0 0 a))
% 3.83/4.03  Clause #1152 (by forward contextual literal cutting #[1151, 1149]): False
% 3.83/4.03  SZS output end Proof for theBenchmark.p
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