TSTP Solution File: SWV400+1 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : SWV400+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Wed Jul 20 21:38:20 EDT 2022
% Result : Theorem 0.20s 0.38s
% Output : Refutation 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13 % Problem : SWV400+1 : TPTP v8.1.0. Released v3.3.0.
% 0.13/0.14 % Command : sos-script %s
% 0.14/0.35 % Computer : n016.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.20/0.36 % CPULimit : 300
% 0.20/0.36 % WCLimit : 600
% 0.20/0.36 % DateTime : Wed Jun 15 11:12:32 EDT 2022
% 0.20/0.36 % CPUTime :
% 0.20/0.38
% 0.20/0.38 -------- PROOF --------
% 0.20/0.38 % SZS status Unsatisfiable
% 0.20/0.38 % SZS output start Refutation
% 0.20/0.38 ----- Otter 3.2, August 2001 -----
% 0.20/0.38 The process was started by sandbox2 on n016.cluster.edu,
% 0.20/0.38 Wed Jun 15 11:12:32 2022
% 0.20/0.38 The command was "./sos". The process ID is 4940.
% 0.20/0.38
% 0.20/0.38 set(prolog_style_variables).
% 0.20/0.38 set(auto).
% 0.20/0.38 dependent: set(auto1).
% 0.20/0.38 dependent: set(process_input).
% 0.20/0.38 dependent: clear(print_kept).
% 0.20/0.38 dependent: clear(print_new_demod).
% 0.20/0.38 dependent: clear(print_back_demod).
% 0.20/0.38 dependent: clear(print_back_sub).
% 0.20/0.38 dependent: set(control_memory).
% 0.20/0.38 dependent: assign(max_mem, 12000).
% 0.20/0.38 dependent: assign(pick_given_ratio, 4).
% 0.20/0.38 dependent: assign(stats_level, 1).
% 0.20/0.38 dependent: assign(pick_semantic_ratio, 3).
% 0.20/0.38 dependent: assign(sos_limit, 5000).
% 0.20/0.38 dependent: assign(max_weight, 60).
% 0.20/0.38 clear(print_given).
% 0.20/0.38
% 0.20/0.38 formula_list(usable).
% 0.20/0.38
% 0.20/0.38 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 0.20/0.38
% 0.20/0.38 This ia a non-Horn set with equality. The strategy will be
% 0.20/0.38 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.20/0.38 unit deletion, with positive clauses in sos and nonpositive
% 0.20/0.38 clauses in usable.
% 0.20/0.38
% 0.20/0.38 dependent: set(knuth_bendix).
% 0.20/0.38 dependent: set(para_from).
% 0.20/0.38 dependent: set(para_into).
% 0.20/0.38 dependent: clear(para_from_right).
% 0.20/0.38 dependent: clear(para_into_right).
% 0.20/0.38 dependent: set(para_from_vars).
% 0.20/0.38 dependent: set(eq_units_both_ways).
% 0.20/0.38 dependent: set(dynamic_demod_all).
% 0.20/0.38 dependent: set(dynamic_demod).
% 0.20/0.38 dependent: set(order_eq).
% 0.20/0.38 dependent: set(back_demod).
% 0.20/0.38 dependent: set(lrpo).
% 0.20/0.38 dependent: set(hyper_res).
% 0.20/0.38 dependent: set(unit_deletion).
% 0.20/0.38 dependent: set(factor).
% 0.20/0.38
% 0.20/0.38 ------------> process usable:
% 0.20/0.38
% 0.20/0.38 ------------> process sos:
% 0.20/0.38
% 0.20/0.38 ----> UNIT CONFLICT at 0.00 sec ----> 32 [binary,31.1,10.1] {-} $F.
% 0.20/0.38
% 0.20/0.38 Length of proof is 0. Level of proof is 0.
% 0.20/0.38
% 0.20/0.38 ---------------- PROOF ----------------
% 0.20/0.38 % SZS status Theorem
% 0.20/0.38 % SZS output start Refutation
% 0.20/0.38
% 0.20/0.38 10 [] {-} -pair_in_list(create_slb,A,B).
% 0.20/0.38 31 [] {-} pair_in_list(create_slb,$c3,$c2).
% 0.20/0.38 32 [binary,31.1,10.1] {-} $F.
% 0.20/0.38
% 0.20/0.38 % SZS output end Refutation
% 0.20/0.38 ------------ end of proof -------------
% 0.20/0.38
% 0.20/0.38
% 0.20/0.38 Search stopped by max_proofs option.
% 0.20/0.38
% 0.20/0.38
% 0.20/0.38 Search stopped by max_proofs option.
% 0.20/0.38
% 0.20/0.38 ============ end of search ============
% 0.20/0.38
% 0.20/0.38 That finishes the proof of the theorem.
% 0.20/0.38
% 0.20/0.38 Process 4940 finished Wed Jun 15 11:12:32 2022
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