TSTP Solution File: SWV397+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SWV397+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Wed Jul 20 21:38:19 EDT 2022

% Result   : Theorem 0.20s 0.50s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SWV397+1 : TPTP v8.1.0. Released v3.3.0.
% 0.07/0.12  % Command  : sos-script %s
% 0.11/0.33  % Computer : n008.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit : 300
% 0.11/0.33  % WCLimit  : 600
% 0.11/0.33  % DateTime : Wed Jun 15 18:51:22 EDT 2022
% 0.11/0.34  % CPUTime  : 
% 0.11/0.36  ----- Otter 3.2, August 2001 -----
% 0.11/0.36  The process was started by sandbox2 on n008.cluster.edu,
% 0.11/0.36  Wed Jun 15 18:51:22 2022
% 0.11/0.36  The command was "./sos".  The process ID is 13727.
% 0.11/0.36  
% 0.11/0.36  set(prolog_style_variables).
% 0.11/0.36  set(auto).
% 0.11/0.36     dependent: set(auto1).
% 0.11/0.36     dependent: set(process_input).
% 0.11/0.36     dependent: clear(print_kept).
% 0.11/0.36     dependent: clear(print_new_demod).
% 0.11/0.36     dependent: clear(print_back_demod).
% 0.11/0.36     dependent: clear(print_back_sub).
% 0.11/0.36     dependent: set(control_memory).
% 0.11/0.36     dependent: assign(max_mem, 12000).
% 0.11/0.36     dependent: assign(pick_given_ratio, 4).
% 0.11/0.36     dependent: assign(stats_level, 1).
% 0.11/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.11/0.36     dependent: assign(sos_limit, 5000).
% 0.11/0.36     dependent: assign(max_weight, 60).
% 0.11/0.36  clear(print_given).
% 0.11/0.36  
% 0.11/0.36  formula_list(usable).
% 0.11/0.36  
% 0.11/0.36  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 0.11/0.36  
% 0.11/0.36  This ia a non-Horn set with equality.  The strategy will be
% 0.11/0.36  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.11/0.36  unit deletion, with positive clauses in sos and nonpositive
% 0.11/0.36  clauses in usable.
% 0.11/0.36  
% 0.11/0.36     dependent: set(knuth_bendix).
% 0.11/0.36     dependent: set(para_from).
% 0.11/0.36     dependent: set(para_into).
% 0.11/0.36     dependent: clear(para_from_right).
% 0.11/0.36     dependent: clear(para_into_right).
% 0.11/0.36     dependent: set(para_from_vars).
% 0.11/0.36     dependent: set(eq_units_both_ways).
% 0.11/0.36     dependent: set(dynamic_demod_all).
% 0.11/0.36     dependent: set(dynamic_demod).
% 0.11/0.36     dependent: set(order_eq).
% 0.11/0.36     dependent: set(back_demod).
% 0.11/0.36     dependent: set(lrpo).
% 0.11/0.36     dependent: set(hyper_res).
% 0.11/0.36     dependent: set(unit_deletion).
% 0.11/0.36     dependent: set(factor).
% 0.11/0.36  
% 0.11/0.36  ------------> process usable:
% 0.11/0.36  
% 0.11/0.36  ------------> process sos:
% 0.11/0.36    Following clause subsumed by 63 during input processing: 0 [copy,63,flip.1] {-} A=A.
% 0.11/0.36    Following clause subsumed by 50 during input processing: 0 [copy,64,flip.1] {-} insert_cpq(triple(A,B,C),D)=triple(insert_pqp(A,D),insert_slb(B,pair(D,bottom)),C).
% 0.11/0.36  
% 0.11/0.36  ======= end of input processing =======
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  Failed to model usable list: disabling FINDER
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  -------------- Softie stats --------------
% 0.20/0.49  
% 0.20/0.49  UPDATE_STOP: 300
% 0.20/0.49  SFINDER_TIME_LIMIT: 2
% 0.20/0.49  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.49  number of clauses in intial UL: 33
% 0.20/0.49  number of clauses initially in problem: 62
% 0.20/0.49  percentage of clauses intially in UL: 53
% 0.20/0.49  percentage of distinct symbols occuring in initial UL: 78
% 0.20/0.49  percent of all initial clauses that are short: 100
% 0.20/0.49  absolute distinct symbol count: 32
% 0.20/0.49     distinct predicate count: 10
% 0.20/0.49     distinct function count: 15
% 0.20/0.49     distinct constant count: 7
% 0.20/0.49  
% 0.20/0.49  ---------- no more Softie stats ----------
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  =========== start of search ===========
% 0.20/0.50  
% 0.20/0.50  -------- PROOF -------- 
% 0.20/0.50  % SZS status Theorem
% 0.20/0.50  % SZS output start Refutation
% 0.20/0.50  
% 0.20/0.50  ----> UNIT CONFLICT at   0.12 sec ----> 653 [binary,652.1,30.1] {-} $F.
% 0.20/0.50  
% 0.20/0.50  Length of proof is 3.  Level of proof is 2.
% 0.20/0.50  
% 0.20/0.50  ---------------- PROOF ----------------
% 0.20/0.50  % SZS status Theorem
% 0.20/0.50  % SZS output start Refutation
% 0.20/0.50  
% 0.20/0.50  29 [] {-} -ok(triple(A,B,bad))|$F.
% 0.20/0.50  30 [copy,29,propositional] {+} -ok(triple(A,B,bad)).
% 0.20/0.50  35 [] {+} -contains_slb($c3,$c1).
% 0.20/0.50  51 [] {-} contains_slb(A,B)|remove_cpq(triple(C,A,D),B)=triple(C,A,bad).
% 0.20/0.50  62 [] {-} ok(remove_cpq(triple($c4,$c3,$c2),$c1)).
% 0.20/0.50  616,615 [hyper,51,35] {-} remove_cpq(triple(A,$c3,B),$c1)=triple(A,$c3,bad).
% 0.20/0.50  652 [back_demod,62,demod,616] {-} ok(triple($c4,$c3,bad)).
% 0.20/0.50  653 [binary,652.1,30.1] {-} $F.
% 0.20/0.50  
% 0.20/0.50  % SZS output end Refutation
% 0.20/0.50  ------------ end of proof -------------
% 0.20/0.50  
% 0.20/0.50  
% 0.20/0.50  Search stopped by max_proofs option.
% 0.20/0.50  
% 0.20/0.50  
% 0.20/0.50  Search stopped by max_proofs option.
% 0.20/0.50  
% 0.20/0.50  ============ end of search ============
% 0.20/0.50  
% 0.20/0.50  That finishes the proof of the theorem.
% 0.20/0.50  
% 0.20/0.50  Process 13727 finished Wed Jun 15 18:51:22 2022
%------------------------------------------------------------------------------