TSTP Solution File: SWV387+1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : SWV387+1 : TPTP v8.1.2. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 23:04:03 EDT 2023

% Result   : Theorem 0.21s 0.46s
% Output   : Proof 0.21s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SWV387+1 : TPTP v8.1.2. Released v3.3.0.
% 0.07/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.34  % Computer : n016.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 300
% 0.14/0.34  % DateTime : Tue Aug 29 03:37:15 EDT 2023
% 0.14/0.35  % CPUTime  : 
% 0.21/0.46  Command-line arguments: --set-join --lhs-weight 1 --no-flatten-goal --complete-subsets --goal-heuristic
% 0.21/0.46  
% 0.21/0.46  % SZS status Theorem
% 0.21/0.46  
% 0.21/0.46  % SZS output start Proof
% 0.21/0.46  Take the following subset of the input axioms:
% 0.21/0.46    fof(l23_co, conjecture, ![U, V, W]: (~check_cpq(triple(U, V, W)) => ![X]: (~check_cpq(remove_cpq(triple(U, V, W), X)) | ~ok(remove_cpq(triple(U, V, W), X))))).
% 0.21/0.46    fof(l23_l027, lemma, ![U2, V2, W2, X2]: ((check_cpq(remove_cpq(triple(U2, V2, W2), X2)) & ok(remove_cpq(triple(U2, V2, W2), X2))) => check_cpq(triple(U2, V2, W2)))).
% 0.21/0.46  
% 0.21/0.46  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.21/0.46  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.21/0.46  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.21/0.46    fresh(y, y, x1...xn) = u
% 0.21/0.46    C => fresh(s, t, x1...xn) = v
% 0.21/0.46  where fresh is a fresh function symbol and x1..xn are the free
% 0.21/0.46  variables of u and v.
% 0.21/0.46  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.21/0.46  input problem has no model of domain size 1).
% 0.21/0.46  
% 0.21/0.46  The encoding turns the above axioms into the following unit equations and goals:
% 0.21/0.46  
% 0.21/0.46  Axiom 1 (l23_l027): fresh4(X, X, Y, Z, W) = true2.
% 0.21/0.46  Axiom 2 (l23_l027): fresh5(X, X, Y, Z, W, V) = check_cpq(triple(Y, Z, W)).
% 0.21/0.46  Axiom 3 (l23_co_1): ok(remove_cpq(triple(u, v, w), x)) = true2.
% 0.21/0.46  Axiom 4 (l23_co): check_cpq(remove_cpq(triple(u, v, w), x)) = true2.
% 0.21/0.46  Axiom 5 (l23_l027): fresh5(ok(remove_cpq(triple(X, Y, Z), W)), true2, X, Y, Z, W) = fresh4(check_cpq(remove_cpq(triple(X, Y, Z), W)), true2, X, Y, Z).
% 0.21/0.46  
% 0.21/0.46  Goal 1 (l23_co_2): check_cpq(triple(u, v, w)) = true2.
% 0.21/0.46  Proof:
% 0.21/0.46    check_cpq(triple(u, v, w))
% 0.21/0.46  = { by axiom 2 (l23_l027) R->L }
% 0.21/0.46    fresh5(true2, true2, u, v, w, x)
% 0.21/0.46  = { by axiom 3 (l23_co_1) R->L }
% 0.21/0.46    fresh5(ok(remove_cpq(triple(u, v, w), x)), true2, u, v, w, x)
% 0.21/0.46  = { by axiom 5 (l23_l027) }
% 0.21/0.46    fresh4(check_cpq(remove_cpq(triple(u, v, w), x)), true2, u, v, w)
% 0.21/0.46  = { by axiom 4 (l23_co) }
% 0.21/0.46    fresh4(true2, true2, u, v, w)
% 0.21/0.46  = { by axiom 1 (l23_l027) }
% 0.21/0.46    true2
% 0.21/0.46  % SZS output end Proof
% 0.21/0.46  
% 0.21/0.46  RESULT: Theorem (the conjecture is true).
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