TSTP Solution File: SWV222+1 by Twee---2.4.2

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Twee---2.4.2
% Problem  : SWV222+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 23:03:03 EDT 2023

% Result   : Theorem 0.21s 0.59s
% Output   : Proof 0.21s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SWV222+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% 0.00/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.18/0.35  % Computer : n012.cluster.edu
% 0.18/0.35  % Model    : x86_64 x86_64
% 0.18/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.18/0.35  % Memory   : 8042.1875MB
% 0.18/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.18/0.35  % CPULimit : 300
% 0.18/0.35  % WCLimit  : 300
% 0.18/0.35  % DateTime : Tue Aug 29 05:42:39 EDT 2023
% 0.18/0.35  % CPUTime  : 
% 0.21/0.59  Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 0.21/0.59  
% 0.21/0.59  % SZS status Theorem
% 0.21/0.59  
% 0.21/0.61  % SZS output start Proof
% 0.21/0.61  Take the following subset of the input axioms:
% 0.21/0.64    fof(quaternion_ds1_symm_0441, conjecture, (![B, A2]: ((leq(n0, A2) & (leq(n0, B) & (leq(A2, n5) & leq(B, n5)))) => a_select3(q_ds1_filter, A2, B)=a_select3(q_ds1_filter, B, A2)) & ![C, D]: ((leq(n0, C) & (leq(n0, D) & (leq(C, n2) & leq(D, n2)))) => a_select3(r_ds1_filter, C, D)=a_select3(r_ds1_filter, D, C))) => ![E, F]: ((leq(n0, E) & (leq(n0, F) & (leq(E, n5) & leq(F, n5)))) => ((~(n0=E & n1=F) & (~(n0=E & n2=F) & (~(n0=E & n3=F) & (~(n0=E & n4=F) & (~(n0=E & n5=F) & (~(n0=F & n1=E) & (~(n0=F & n2=E) & (~(n0=F & n3=E) & (~(n0=F & n4=E) & (~(n0=F & n5=E) & (~(n1=E & n1=F) & (~(n1=E & n2=F) & (~(n1=E & n3=F) & (~(n1=E & n4=F) & (~(n1=E & n5=F) & (~(n1=F & n2=E) & (~(n1=F & n3=E) & (~(n1=F & n4=E) & (~(n1=F & n5=E) & (~(n2=E & n2=F) & (~(n2=E & n3=F) & (~(n2=E & n4=F) & (~(n2=E & n5=F) & (~(n2=F & n3=E) & (~(n2=F & n4=E) & (~(n2=F & n5=E) & (~(n3=E & n3=F) & (~(n3=E & n4=F) & (~(n3=E & n5=F) & (~(n3=F & n4=E) & (~(n3=F & n5=E) & (~(n4=E & n4=F) & (~(n4=E & n5=F) & (~(n4=F & n5=E) & (~(n5=E & n5=F) & (n0=E & (n0=F & (n1=E & n3=F)))))))))))))))))))))))))))))))))))))) => a_select2(xinit_noise, n0)=n0))).
% 0.21/0.64  
% 0.21/0.64  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.21/0.64  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.21/0.64  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.21/0.64    fresh(y, y, x1...xn) = u
% 0.21/0.64    C => fresh(s, t, x1...xn) = v
% 0.21/0.64  where fresh is a fresh function symbol and x1..xn are the free
% 0.21/0.64  variables of u and v.
% 0.21/0.64  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.21/0.64  input problem has no model of domain size 1).
% 0.21/0.64  
% 0.21/0.64  The encoding turns the above axioms into the following unit equations and goals:
% 0.21/0.64  
% 0.21/0.64  Axiom 1 (quaternion_ds1_symm_0441): n0 = f.
% 0.21/0.64  Axiom 2 (quaternion_ds1_symm_0441_1): n0 = e.
% 0.21/0.64  Axiom 3 (quaternion_ds1_symm_0441_2): n1 = e.
% 0.21/0.65  Axiom 4 (quaternion_ds1_symm_0441_3): n3 = f.
% 0.21/0.65  
% 0.21/0.65  Lemma 5: n1 = n0.
% 0.21/0.65  Proof:
% 0.21/0.65    n1
% 0.21/0.65  = { by axiom 3 (quaternion_ds1_symm_0441_2) }
% 0.21/0.65    e
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) R->L }
% 0.21/0.65    n0
% 0.21/0.65  
% 0.21/0.65  Lemma 6: n3 = n0.
% 0.21/0.65  Proof:
% 0.21/0.65    n3
% 0.21/0.65  = { by axiom 4 (quaternion_ds1_symm_0441_3) }
% 0.21/0.65    f
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) R->L }
% 0.21/0.65    n0
% 0.21/0.65  
% 0.21/0.65  Goal 1 (quaternion_ds1_symm_0441_35): tuple2(n3, n3) = tuple2(f, e).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n3, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(n0, e)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(f, e)
% 0.21/0.65  
% 0.21/0.65  Goal 2 (quaternion_ds1_symm_0441_25): tuple2(n1, n3) = tuple2(e, f).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n1, n3)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(e, n0)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(e, f)
% 0.21/0.65  
% 0.21/0.65  Goal 3 (quaternion_ds1_symm_0441_21): tuple2(n1, n3) = tuple2(f, e).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n1, n3)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(n0, e)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(f, e)
% 0.21/0.65  
% 0.21/0.65  Goal 4 (quaternion_ds1_symm_0441_19): tuple2(n1, n1) = tuple2(f, e).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n1, n1)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n1)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(n0, e)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(f, e)
% 0.21/0.65  
% 0.21/0.65  Goal 5 (quaternion_ds1_symm_0441_16): tuple2(n0, n3) = tuple2(e, f).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n0, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(e, n0)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(e, f)
% 0.21/0.65  
% 0.21/0.65  Goal 6 (quaternion_ds1_symm_0441_14): tuple2(n0, n1) = tuple2(e, f).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n0, n1)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(e, n0)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(e, f)
% 0.21/0.65  
% 0.21/0.65  Goal 7 (quaternion_ds1_symm_0441_11): tuple2(n0, n3) = tuple2(f, e).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n0, n3)
% 0.21/0.65  = { by lemma 6 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(n0, e)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(f, e)
% 0.21/0.65  
% 0.21/0.65  Goal 8 (quaternion_ds1_symm_0441_9): tuple2(n0, n1) = tuple2(f, e).
% 0.21/0.65  Proof:
% 0.21/0.65    tuple2(n0, n1)
% 0.21/0.65  = { by lemma 5 }
% 0.21/0.65    tuple2(n0, n0)
% 0.21/0.65  = { by axiom 2 (quaternion_ds1_symm_0441_1) }
% 0.21/0.65    tuple2(n0, e)
% 0.21/0.65  = { by axiom 1 (quaternion_ds1_symm_0441) }
% 0.21/0.65    tuple2(f, e)
% 0.21/0.65  % SZS output end Proof
% 0.21/0.65  
% 0.21/0.65  RESULT: Theorem (the conjecture is true).
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