%------------------------------------------------------------------------------
% File     : Twee---2.4.2
% Problem  : SWV082+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 23:02:30 EDT 2023

% Result   : Theorem 0.20s 0.57s
% Output   : Proof 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13  % Problem  : SWV082+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% 0.12/0.14  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.35  % Computer : n011.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 300
% 0.14/0.35  % DateTime : Tue Aug 29 10:39:11 EDT 2023
% 0.14/0.35  % CPUTime  : 
% 0.20/0.57  Command-line arguments: --flip-ordering --lhs-weight 1 --depth-weight 60 --distributivity-heuristic
% 0.20/0.57  
% 0.20/0.57  % SZS status Theorem
% 0.20/0.57  
% 0.20/0.57  % SZS output start Proof
% 0.20/0.57  Take the following subset of the input axioms:
% 0.20/0.58    fof(cl5_nebula_array_0023, conjecture, (leq(n0, pv58) & leq(pv58, minus(n5, n1))) => (leq(n0, pv58) & leq(pv58, minus(n5, n1)))).
% 0.20/0.58  
% 0.20/0.58  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.20/0.58  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.20/0.58  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.20/0.58    fresh(y, y, x1...xn) = u
% 0.20/0.58    C => fresh(s, t, x1...xn) = v
% 0.20/0.58  where fresh is a fresh function symbol and x1..xn are the free
% 0.20/0.58  variables of u and v.
% 0.20/0.58  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.20/0.58  input problem has no model of domain size 1).
% 0.20/0.58  
% 0.20/0.58  The encoding turns the above axioms into the following unit equations and goals:
% 0.20/0.58  
% 0.20/0.58  Axiom 1 (cl5_nebula_array_0023): leq(n0, pv58) = true3.
% 0.20/0.58  Axiom 2 (cl5_nebula_array_0023_1): leq(pv58, minus(n5, n1)) = true3.
% 0.20/0.58  
% 0.20/0.58  Goal 1 (cl5_nebula_array_0023_2): tuple(leq(n0, pv58), leq(pv58, minus(n5, n1))) = tuple(true3, true3).
% 0.20/0.58  Proof:
% 0.20/0.58    tuple(leq(n0, pv58), leq(pv58, minus(n5, n1)))
% 0.20/0.58  = { by axiom 1 (cl5_nebula_array_0023) }
% 0.20/0.58    tuple(true3, leq(pv58, minus(n5, n1)))
% 0.20/0.58  = { by axiom 2 (cl5_nebula_array_0023_1) }
% 0.20/0.58    tuple(true3, true3)
% 0.20/0.58  % SZS output end Proof
% 0.20/0.58  
% 0.20/0.58  RESULT: Theorem (the conjecture is true).
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