TSTP Solution File: SWV059+1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : SWV059+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 23:02:23 EDT 2023

% Result   : Theorem 1.61s 0.60s
% Output   : Proof 1.61s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.14  % Problem  : SWV059+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% 0.07/0.14  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.15/0.36  % Computer : n006.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit : 300
% 0.15/0.36  % WCLimit  : 300
% 0.15/0.36  % DateTime : Tue Aug 29 04:01:06 EDT 2023
% 0.15/0.36  % CPUTime  : 
% 1.61/0.60  Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 1.61/0.60  
% 1.61/0.60  % SZS status Theorem
% 1.61/0.60  
% 1.61/0.60  % SZS output start Proof
% 1.61/0.60  Take the following subset of the input axioms:
% 1.61/0.60    fof(cl5_nebula_norm_0049, conjecture, geq(pv72, tptp_float_0_001) => ((~gt(plus(n1, loopcounter), n1) => true) & (gt(plus(n1, loopcounter), n1) => true))).
% 1.61/0.60    fof(ttrue, axiom, true).
% 1.61/0.60  
% 1.61/0.60  Now clausify the problem and encode Horn clauses using encoding 3 of
% 1.61/0.60  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 1.61/0.60  We repeatedly replace C & s=t => u=v by the two clauses:
% 1.61/0.60    fresh(y, y, x1...xn) = u
% 1.61/0.60    C => fresh(s, t, x1...xn) = v
% 1.61/0.60  where fresh is a fresh function symbol and x1..xn are the free
% 1.61/0.60  variables of u and v.
% 1.61/0.60  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 1.61/0.60  input problem has no model of domain size 1).
% 1.61/0.60  
% 1.61/0.60  The encoding turns the above axioms into the following unit equations and goals:
% 1.61/0.60  
% 1.61/0.60  Axiom 1 (ttrue): true = true3.
% 1.61/0.60  Axiom 2 (cl5_nebula_norm_0049_3): fresh40(X, X) = true3.
% 1.61/0.60  Axiom 3 (cl5_nebula_norm_0049_3): fresh40(true, true3) = gt(plus(n1, loopcounter), n1).
% 1.61/0.60  
% 1.61/0.60  Goal 1 (cl5_nebula_norm_0049_2): true = true3.
% 1.61/0.60  Proof:
% 1.61/0.60    true
% 1.61/0.60  = { by axiom 1 (ttrue) }
% 1.61/0.60    true3
% 1.61/0.60  
% 1.61/0.60  Goal 2 (cl5_nebula_norm_0049_1): tuple(gt(plus(n1, loopcounter), n1), true) = tuple(true3, true3).
% 1.61/0.60  Proof:
% 1.61/0.60    tuple(gt(plus(n1, loopcounter), n1), true)
% 1.61/0.60  = { by axiom 3 (cl5_nebula_norm_0049_3) R->L }
% 1.61/0.60    tuple(fresh40(true, true3), true)
% 1.61/0.60  = { by axiom 1 (ttrue) }
% 1.61/0.60    tuple(fresh40(true3, true3), true)
% 1.61/0.60  = { by axiom 2 (cl5_nebula_norm_0049_3) }
% 1.61/0.60    tuple(true3, true)
% 1.61/0.60  = { by axiom 1 (ttrue) }
% 1.61/0.60    tuple(true3, true3)
% 1.61/0.60  % SZS output end Proof
% 1.61/0.60  
% 1.61/0.60  RESULT: Theorem (the conjecture is true).
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