%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SWC358-1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 22:03:32 EDT 2022

% Result   : Unsatisfiable 0.20s 0.48s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   15 (   9 unt;   4 nHn;  15 RR)
%            Number of literals    :   21 (   0 equ;   4 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   6 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ssList(sk1),
    file('SWC358-1.p',unknown),
    [] ).

cnf(5,axiom,
    equal(sk4,sk2),
    file('SWC358-1.p',unknown),
    [] ).

cnf(6,axiom,
    equal(sk3,sk1),
    file('SWC358-1.p',unknown),
    [] ).

cnf(8,axiom,
    ~ segmentP(sk2,sk1),
    file('SWC358-1.p',unknown),
    [] ).

cnf(10,axiom,
    ( equal(nil,sk4)
    | segmentP(sk4,sk3) ),
    file('SWC358-1.p',unknown),
    [] ).

cnf(12,axiom,
    ( equal(nil,sk3)
    | segmentP(sk4,sk3) ),
    file('SWC358-1.p',unknown),
    [] ).

cnf(68,axiom,
    ( ~ ssList(u)
    | segmentP(u,nil) ),
    file('SWC358-1.p',unknown),
    [] ).

cnf(200,plain,
    ( equal(nil,sk1)
    | segmentP(sk2,sk1) ),
    inference(rew,[status(thm),theory(equality)],[5,12,6]),
    [iquote('0:Rew:5.0,12.1,6.0,12.1,6.0,12.0')] ).

cnf(201,plain,
    equal(nil,sk1),
    inference(mrr,[status(thm)],[200,8]),
    [iquote('0:MRR:200.1,8.0')] ).

cnf(214,plain,
    ( ~ ssList(u)
    | segmentP(u,sk1) ),
    inference(rew,[status(thm),theory(equality)],[201,68]),
    [iquote('0:Rew:201.0,68.1')] ).

cnf(216,plain,
    ( equal(sk2,sk1)
    | segmentP(sk2,sk1) ),
    inference(rew,[status(thm),theory(equality)],[5,10,6,201]),
    [iquote('0:Rew:5.0,10.1,6.0,10.1,201.0,10.0,5.0,10.0')] ).

cnf(217,plain,
    equal(sk2,sk1),
    inference(mrr,[status(thm)],[216,8]),
    [iquote('0:MRR:216.1,8.0')] ).

cnf(220,plain,
    ~ segmentP(sk1,sk1),
    inference(rew,[status(thm),theory(equality)],[217,8]),
    [iquote('0:Rew:217.0,8.0')] ).

cnf(349,plain,
    segmentP(sk1,sk1),
    inference(res,[status(thm),theory(equality)],[1,214]),
    [iquote('0:Res:1.0,214.0')] ).

cnf(464,plain,
    $false,
    inference(mrr,[status(thm)],[349,220]),
    [iquote('0:MRR:349.0,220.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SWC358-1 : TPTP v8.1.0. Released v2.4.0.
% 0.04/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n028.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sun Jun 12 01:12:50 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.48  
% 0.20/0.48  SPASS V 3.9 
% 0.20/0.48  SPASS beiseite: Proof found.
% 0.20/0.48  % SZS status Theorem
% 0.20/0.48  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.48  SPASS derived 216 clauses, backtracked 0 clauses, performed 0 splits and kept 208 clauses.
% 0.20/0.48  SPASS allocated 76176 KBytes.
% 0.20/0.48  SPASS spent	0:00:00.12 on the problem.
% 0.20/0.48  		0:00:00.04 for the input.
% 0.20/0.48  		0:00:00.00 for the FLOTTER CNF translation.
% 0.20/0.48  		0:00:00.00 for inferences.
% 0.20/0.48  		0:00:00.00 for the backtracking.
% 0.20/0.48  		0:00:00.03 for the reduction.
% 0.20/0.48  
% 0.20/0.48  
% 0.20/0.48  Here is a proof with depth 1, length 15 :
% 0.20/0.48  % SZS output start Refutation
% See solution above
% 0.20/0.48  Formulae used in the proof : co1_1 co1_5 co1_6 co1_8 co1_10 co1_12 clause56
% 0.20/0.48  
%------------------------------------------------------------------------------