TSTP Solution File: SWC279+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SWC279+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n023.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 22:03:01 EDT 2022
% Result : Theorem 5.23s 5.38s
% Output : Refutation 5.23s
% Verified :
% SZS Type : Refutation
% Derivation depth : 9
% Number of leaves : 11
% Syntax : Number of clauses : 29 ( 15 unt; 1 nHn; 29 RR)
% Number of literals : 73 ( 0 equ; 47 neg)
% Maximal clause size : 7 ( 2 avg)
% Maximal term depth : 4 ( 1 avg)
% Number of predicates : 7 ( 6 usr; 1 prp; 0-3 aty)
% Number of functors : 12 ( 12 usr; 10 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
ssItem(skc13),
file('SWC279+1.p',unknown),
[] ).
cnf(2,axiom,
ssList(skc12),
file('SWC279+1.p',unknown),
[] ).
cnf(3,axiom,
ssList(skc11),
file('SWC279+1.p',unknown),
[] ).
cnf(4,axiom,
ssItem(skc10),
file('SWC279+1.p',unknown),
[] ).
cnf(70,axiom,
( memberP(u,v)
| skP0(w,v,u) ),
file('SWC279+1.p',unknown),
[] ).
cnf(80,axiom,
( ~ skP0(skc10,skc13,skc11)
| memberP(skc12,skc13) ),
file('SWC279+1.p',unknown),
[] ).
cnf(81,axiom,
( ~ leq(u,v)
| skP0(v,u,w) ),
file('SWC279+1.p',unknown),
[] ).
cnf(84,axiom,
equal(app(app(skc11,cons(skc10,nil)),skc12),skc8),
file('SWC279+1.p',unknown),
[] ).
cnf(85,axiom,
( ~ leq(skc10,skc13)
| ~ skP0(skc10,skc13,skc11) ),
file('SWC279+1.p',unknown),
[] ).
cnf(191,axiom,
( ~ ssItem(u)
| ~ ssList(v)
| ~ ssList(w)
| ~ ssItem(x)
| ~ memberP(w,u)
| ~ equal(app(app(w,cons(x,nil)),v),skc8)
| leq(u,x) ),
file('SWC279+1.p',unknown),
[] ).
cnf(192,axiom,
( ~ ssItem(u)
| ~ ssList(v)
| ~ ssList(w)
| ~ ssItem(x)
| ~ memberP(v,u)
| ~ equal(app(app(w,cons(x,nil)),v),skc8)
| leq(x,u) ),
file('SWC279+1.p',unknown),
[] ).
cnf(6829,plain,
~ skP0(skc10,skc13,skc11),
inference(spt,[spt(split,[position(s1)])],[80]),
[iquote('1:Spt:80.0')] ).
cnf(6830,plain,
memberP(skc11,skc13),
inference(res,[status(thm),theory(equality)],[70,6829]),
[iquote('1:Res:70.1,6829.0')] ).
cnf(6831,plain,
~ leq(skc13,skc10),
inference(res,[status(thm),theory(equality)],[81,6829]),
[iquote('1:Res:81.1,6829.0')] ).
cnf(11109,plain,
( ~ ssItem(u)
| ~ ssList(skc12)
| ~ ssList(skc11)
| ~ ssItem(skc10)
| ~ memberP(skc11,u)
| ~ equal(skc8,skc8)
| leq(u,skc10) ),
inference(spl,[status(thm),theory(equality)],[84,191]),
[iquote('0:SpL:84.0,191.5')] ).
cnf(11111,plain,
( ~ ssItem(u)
| ~ ssList(skc12)
| ~ ssList(skc11)
| ~ ssItem(skc10)
| ~ memberP(skc11,u)
| leq(u,skc10) ),
inference(obv,[status(thm),theory(equality)],[11109]),
[iquote('0:Obv:11109.5')] ).
cnf(11112,plain,
( ~ ssItem(u)
| ~ memberP(skc11,u)
| leq(u,skc10) ),
inference(ssi,[status(thm)],[11111,4,3,2]),
[iquote('0:SSi:11111.3,11111.2,11111.1,4.0,3.0,2.0')] ).
cnf(11149,plain,
( ~ ssItem(u)
| ~ ssList(skc12)
| ~ ssList(skc11)
| ~ ssItem(skc10)
| ~ memberP(skc12,u)
| ~ equal(skc8,skc8)
| leq(skc10,u) ),
inference(spl,[status(thm),theory(equality)],[84,192]),
[iquote('0:SpL:84.0,192.5')] ).
cnf(11151,plain,
( ~ ssItem(u)
| ~ ssList(skc12)
| ~ ssList(skc11)
| ~ ssItem(skc10)
| ~ memberP(skc12,u)
| leq(skc10,u) ),
inference(obv,[status(thm),theory(equality)],[11149]),
[iquote('0:Obv:11149.5')] ).
cnf(11152,plain,
( ~ ssItem(u)
| ~ memberP(skc12,u)
| leq(skc10,u) ),
inference(ssi,[status(thm)],[11151,4,3,2]),
[iquote('0:SSi:11151.3,11151.2,11151.1,4.0,3.0,2.0')] ).
cnf(11987,plain,
( ~ ssItem(skc13)
| leq(skc13,skc10) ),
inference(res,[status(thm),theory(equality)],[6830,11112]),
[iquote('1:Res:6830.0,11112.1')] ).
cnf(11988,plain,
leq(skc13,skc10),
inference(ssi,[status(thm)],[11987,1]),
[iquote('1:SSi:11987.0,1.0')] ).
cnf(11989,plain,
$false,
inference(mrr,[status(thm)],[11988,6831]),
[iquote('1:MRR:11988.0,6831.0')] ).
cnf(11990,plain,
skP0(skc10,skc13,skc11),
inference(spt,[spt(split,[position(sa)])],[11989,6829]),
[iquote('1:Spt:11989.0,80.0,6829.0')] ).
cnf(11991,plain,
memberP(skc12,skc13),
inference(spt,[spt(split,[position(s2)])],[80]),
[iquote('1:Spt:11989.0,80.1')] ).
cnf(11992,plain,
~ leq(skc10,skc13),
inference(mrr,[status(thm)],[85,11990]),
[iquote('1:MRR:85.1,11990.0')] ).
cnf(12541,plain,
( ~ ssItem(skc13)
| leq(skc10,skc13) ),
inference(res,[status(thm),theory(equality)],[11991,11152]),
[iquote('1:Res:11991.0,11152.1')] ).
cnf(12542,plain,
leq(skc10,skc13),
inference(ssi,[status(thm)],[12541,1]),
[iquote('1:SSi:12541.0,1.0')] ).
cnf(12543,plain,
$false,
inference(mrr,[status(thm)],[12542,11992]),
[iquote('1:MRR:12542.0,11992.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SWC279+1 : TPTP v8.1.0. Released v2.4.0.
% 0.03/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n023.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Sat Jun 11 22:06:36 EDT 2022
% 0.12/0.33 % CPUTime :
% 5.23/5.38
% 5.23/5.38 SPASS V 3.9
% 5.23/5.38 SPASS beiseite: Proof found.
% 5.23/5.38 % SZS status Theorem
% 5.23/5.38 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 5.23/5.38 SPASS derived 8662 clauses, backtracked 2121 clauses, performed 70 splits and kept 6304 clauses.
% 5.23/5.38 SPASS allocated 107655 KBytes.
% 5.23/5.38 SPASS spent 0:00:04.71 on the problem.
% 5.23/5.38 0:00:00.04 for the input.
% 5.23/5.38 0:00:00.06 for the FLOTTER CNF translation.
% 5.23/5.38 0:00:00.08 for inferences.
% 5.23/5.38 0:00:00.08 for the backtracking.
% 5.23/5.38 0:00:04.25 for the reduction.
% 5.23/5.38
% 5.23/5.38
% 5.23/5.38 Here is a proof with depth 3, length 29 :
% 5.23/5.38 % SZS output start Refutation
% See solution above
% 5.23/5.38 Formulae used in the proof : co1
% 5.23/5.38
%------------------------------------------------------------------------------