TSTP Solution File: SWC269+1 by Etableau---0.67
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SWC269+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 20:30:44 EDT 2022
% Result : Theorem 0.20s 0.39s
% Output : CNFRefutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 1
% Syntax : Number of formulae : 8 ( 5 unt; 0 def)
% Number of atoms : 47 ( 7 equ)
% Maximal formula atoms : 14 ( 5 avg)
% Number of connectives : 56 ( 17 ~; 14 |; 17 &)
% ( 0 <=>; 8 =>; 0 <=; 0 <~>)
% Maximal formula depth : 20 ( 8 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 7 ( 5 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 4 con; 0-0 aty)
% Number of variables : 11 ( 0 sgn 9 !; 2 ?)
% Comments :
%------------------------------------------------------------------------------
fof(co1,conjecture,
! [X1] :
( ssList(X1)
=> ! [X2] :
( ssList(X2)
=> ! [X3] :
( ssList(X3)
=> ! [X4] :
( ssList(X4)
=> ( X2 != X4
| X1 != X3
| ~ frontsegP(X4,X3)
| ~ totalorderedP(X3)
| ? [X5] :
( ssList(X5)
& neq(X3,X5)
& frontsegP(X4,X5)
& segmentP(X5,X3)
& totalorderedP(X5) )
| totalorderedP(X1) ) ) ) ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',co1) ).
fof(c_0_1,negated_conjecture,
~ ! [X1] :
( ssList(X1)
=> ! [X2] :
( ssList(X2)
=> ! [X3] :
( ssList(X3)
=> ! [X4] :
( ssList(X4)
=> ( X2 != X4
| X1 != X3
| ~ frontsegP(X4,X3)
| ~ totalorderedP(X3)
| ? [X5] :
( ssList(X5)
& neq(X3,X5)
& frontsegP(X4,X5)
& segmentP(X5,X3)
& totalorderedP(X5) )
| totalorderedP(X1) ) ) ) ) ),
inference(assume_negation,[status(cth)],[co1]) ).
fof(c_0_2,negated_conjecture,
! [X255] :
( ssList(esk48_0)
& ssList(esk49_0)
& ssList(esk50_0)
& ssList(esk51_0)
& esk49_0 = esk51_0
& esk48_0 = esk50_0
& frontsegP(esk51_0,esk50_0)
& totalorderedP(esk50_0)
& ( ~ ssList(X255)
| ~ neq(esk50_0,X255)
| ~ frontsegP(esk51_0,X255)
| ~ segmentP(X255,esk50_0)
| ~ totalorderedP(X255) )
& ~ totalorderedP(esk48_0) ),
inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[inference(fof_simplification,[status(thm)],[c_0_1])])])])]) ).
cnf(c_0_3,negated_conjecture,
~ totalorderedP(esk48_0),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_4,negated_conjecture,
esk48_0 = esk50_0,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_5,negated_conjecture,
totalorderedP(esk50_0),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_6,negated_conjecture,
~ totalorderedP(esk50_0),
inference(rw,[status(thm)],[c_0_3,c_0_4]) ).
cnf(c_0_7,negated_conjecture,
$false,
inference(sr,[status(thm)],[c_0_5,c_0_6]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13 % Problem : SWC269+1 : TPTP v8.1.0. Released v2.4.0.
% 0.07/0.13 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.35 % Computer : n025.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 600
% 0.13/0.35 % DateTime : Sun Jun 12 03:54:07 EDT 2022
% 0.13/0.35 % CPUTime :
% 0.20/0.39 # No SInE strategy applied
% 0.20/0.39 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S4c
% 0.20/0.39 # and selection function SelectCQPrecWNTNp.
% 0.20/0.39 #
% 0.20/0.39 # Presaturation interreduction done
% 0.20/0.39
% 0.20/0.39 # Proof found!
% 0.20/0.39 # SZS status Theorem
% 0.20/0.39 # SZS output start CNFRefutation
% See solution above
% 0.20/0.39 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------