%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SWC102-1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 22:01:44 EDT 2022

% Result   : Unsatisfiable 0.18s 0.46s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (  11 unt;   0 nHn;  14 RR)
%            Number of literals    :   17 (   0 equ;   6 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   6 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ssList(sk1),
    file('SWC102-1.p',unknown),
    [] ).

cnf(5,axiom,
    equal(sk4,sk2),
    file('SWC102-1.p',unknown),
    [] ).

cnf(6,axiom,
    equal(sk3,sk1),
    file('SWC102-1.p',unknown),
    [] ).

cnf(7,axiom,
    equal(sk4,sk3),
    file('SWC102-1.p',unknown),
    [] ).

cnf(8,axiom,
    neq(sk2,nil),
    file('SWC102-1.p',unknown),
    [] ).

cnf(9,axiom,
    ( ~ neq(sk1,nil)
    | ~ frontsegP(sk2,sk1) ),
    file('SWC102-1.p',unknown),
    [] ).

cnf(70,axiom,
    ( ~ ssList(u)
    | frontsegP(u,u) ),
    file('SWC102-1.p',unknown),
    [] ).

cnf(197,plain,
    equal(sk4,sk1),
    inference(rew,[status(thm),theory(equality)],[6,7]),
    [iquote('0:Rew:6.0,7.0')] ).

cnf(198,plain,
    equal(sk2,sk1),
    inference(rew,[status(thm),theory(equality)],[5,197]),
    [iquote('0:Rew:5.0,197.0')] ).

cnf(200,plain,
    neq(sk1,nil),
    inference(rew,[status(thm),theory(equality)],[198,8]),
    [iquote('0:Rew:198.0,8.0')] ).

cnf(202,plain,
    ( ~ neq(sk1,nil)
    | ~ frontsegP(sk1,sk1) ),
    inference(rew,[status(thm),theory(equality)],[198,9]),
    [iquote('0:Rew:198.0,9.1')] ).

cnf(203,plain,
    ~ frontsegP(sk1,sk1),
    inference(mrr,[status(thm)],[202,200]),
    [iquote('0:MRR:202.0,200.0')] ).

cnf(295,plain,
    frontsegP(sk1,sk1),
    inference(res,[status(thm),theory(equality)],[1,70]),
    [iquote('0:Res:1.0,70.0')] ).

cnf(399,plain,
    $false,
    inference(mrr,[status(thm)],[295,203]),
    [iquote('0:MRR:295.0,203.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11  % Problem  : SWC102-1 : TPTP v8.1.0. Released v2.4.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n012.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 11 20:34:56 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.46  
% 0.18/0.46  SPASS V 3.9 
% 0.18/0.46  SPASS beiseite: Proof found.
% 0.18/0.46  % SZS status Theorem
% 0.18/0.46  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.46  SPASS derived 197 clauses, backtracked 0 clauses, performed 0 splits and kept 200 clauses.
% 0.18/0.46  SPASS allocated 76120 KBytes.
% 0.18/0.46  SPASS spent	0:00:00.11 on the problem.
% 0.18/0.46  		0:00:00.04 for the input.
% 0.18/0.46  		0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.46  		0:00:00.00 for inferences.
% 0.18/0.46  		0:00:00.00 for the backtracking.
% 0.18/0.46  		0:00:00.03 for the reduction.
% 0.18/0.46  
% 0.18/0.46  
% 0.18/0.46  Here is a proof with depth 1, length 14 :
% 0.18/0.46  % SZS output start Refutation
% See solution above
% 0.18/0.46  Formulae used in the proof : co1_1 co1_5 co1_6 co1_7 co1_8 co1_9 clause61
% 0.18/0.46  
%------------------------------------------------------------------------------