TSTP Solution File: SWC038+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SWC038+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 22:01:17 EDT 2022

% Result   : Theorem 0.39s 0.61s
% Output   : Refutation 0.39s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   14 (   8 unt;   2 nHn;  14 RR)
%            Number of literals    :   22 (   0 equ;  10 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   5 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    ssList(skc4),
    file('SWC038+1.p',unknown),
    [] ).

cnf(13,axiom,
    equal(nil,skc5),
    file('SWC038+1.p',unknown),
    [] ).

cnf(52,axiom,
    ~ equal(nil,skc4),
    file('SWC038+1.p',unknown),
    [] ).

cnf(61,axiom,
    ( equal(nil,u)
    | skP0(u,v) ),
    file('SWC038+1.p',unknown),
    [] ).

cnf(71,axiom,
    ( ~ skP0(skc4,skc5)
    | frontsegP(skc5,skc4) ),
    file('SWC038+1.p',unknown),
    [] ).

cnf(92,axiom,
    ( ~ ssList(u)
    | ~ frontsegP(nil,u)
    | equal(nil,u) ),
    file('SWC038+1.p',unknown),
    [] ).

cnf(204,plain,
    ~ equal(skc5,skc4),
    inference(rew,[status(thm),theory(equality)],[13,52]),
    [iquote('0:Rew:13.0,52.0')] ).

cnf(208,plain,
    ( skP0(u,v)
    | equal(skc5,u) ),
    inference(rew,[status(thm),theory(equality)],[13,61]),
    [iquote('0:Rew:13.0,61.0')] ).

cnf(230,plain,
    ( ~ ssList(u)
    | ~ frontsegP(skc5,u)
    | equal(skc5,u) ),
    inference(rew,[status(thm),theory(equality)],[13,92]),
    [iquote('0:Rew:13.0,92.2,13.0,92.1')] ).

cnf(323,plain,
    ( ~ frontsegP(skc5,skc4)
    | equal(skc5,skc4) ),
    inference(res,[status(thm),theory(equality)],[2,230]),
    [iquote('0:Res:2.0,230.0')] ).

cnf(600,plain,
    ~ frontsegP(skc5,skc4),
    inference(mrr,[status(thm)],[323,204]),
    [iquote('0:MRR:323.1,204.0')] ).

cnf(601,plain,
    ~ skP0(skc4,skc5),
    inference(mrr,[status(thm)],[71,600]),
    [iquote('0:MRR:71.1,600.0')] ).

cnf(686,plain,
    equal(skc5,skc4),
    inference(res,[status(thm),theory(equality)],[208,601]),
    [iquote('0:Res:208.0,601.0')] ).

cnf(687,plain,
    $false,
    inference(mrr,[status(thm)],[686,204]),
    [iquote('0:MRR:686.0,204.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SWC038+1 : TPTP v8.1.0. Released v2.4.0.
% 0.04/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n021.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sun Jun 12 03:33:10 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.39/0.61  
% 0.39/0.61  SPASS V 3.9 
% 0.39/0.61  SPASS beiseite: Proof found.
% 0.39/0.61  % SZS status Theorem
% 0.39/0.61  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.39/0.61  SPASS derived 368 clauses, backtracked 0 clauses, performed 5 splits and kept 450 clauses.
% 0.39/0.61  SPASS allocated 98456 KBytes.
% 0.39/0.61  SPASS spent	0:00:00.26 on the problem.
% 0.39/0.61  		0:00:00.04 for the input.
% 0.39/0.61  		0:00:00.07 for the FLOTTER CNF translation.
% 0.39/0.61  		0:00:00.00 for inferences.
% 0.39/0.61  		0:00:00.00 for the backtracking.
% 0.39/0.61  		0:00:00.03 for the reduction.
% 0.39/0.61  
% 0.39/0.61  
% 0.39/0.61  Here is a proof with depth 1, length 14 :
% 0.39/0.61  % SZS output start Refutation
% See solution above
% 0.39/0.61  Formulae used in the proof : co1 ax46
% 0.39/0.61  
%------------------------------------------------------------------------------