%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SWC026-1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 22:01:11 EDT 2022

% Result   : Unsatisfiable 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   14 (   6 unt;   2 nHn;  14 RR)
%            Number of literals    :   22 (   0 equ;   8 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   5 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(5,axiom,
    equal(sk2,sk4),
    file('SWC026-1.p',unknown),
    [] ).

cnf(6,axiom,
    equal(sk1,sk3),
    file('SWC026-1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ equal(nil,sk3)
    | equal(nil,sk4) ),
    file('SWC026-1.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ equal(nil,sk4)
    | equal(nil,sk3) ),
    file('SWC026-1.p',unknown),
    [] ).

cnf(9,axiom,
    ( equal(nil,sk2)
    | equal(nil,sk1) ),
    file('SWC026-1.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ equal(nil,sk1)
    | ~ equal(nil,sk2) ),
    file('SWC026-1.p',unknown),
    [] ).

cnf(200,plain,
    ( equal(nil,sk4)
    | equal(nil,sk3) ),
    inference(rew,[status(thm),theory(equality)],[6,9,5]),
    [iquote('0:Rew:6.0,9.1,5.0,9.0')] ).

cnf(201,plain,
    ( ~ equal(sk4,sk4)
    | equal(nil,sk3) ),
    inference(rew,[status(thm),theory(equality)],[200,8]),
    [iquote('0:Rew:200.0,8.0')] ).

cnf(202,plain,
    equal(nil,sk3),
    inference(obv,[status(thm),theory(equality)],[201]),
    [iquote('0:Obv:201.0')] ).

cnf(223,plain,
    ( ~ equal(sk3,sk3)
    | equal(sk4,sk3) ),
    inference(rew,[status(thm),theory(equality)],[202,7]),
    [iquote('0:Rew:202.0,7.1,202.0,7.0')] ).

cnf(224,plain,
    equal(sk4,sk3),
    inference(obv,[status(thm),theory(equality)],[223]),
    [iquote('0:Obv:223.0')] ).

cnf(226,plain,
    equal(sk2,sk3),
    inference(rew,[status(thm),theory(equality)],[224,5]),
    [iquote('0:Rew:224.0,5.0')] ).

cnf(229,plain,
    ( ~ equal(sk3,sk3)
    | ~ equal(sk3,sk3) ),
    inference(rew,[status(thm),theory(equality)],[202,12,226,6]),
    [iquote('0:Rew:202.0,12.1,226.0,12.1,202.0,12.0,6.0,12.0')] ).

cnf(230,plain,
    $false,
    inference(obv,[status(thm),theory(equality)],[229]),
    [iquote('0:Obv:229.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.13  % Problem  : SWC026-1 : TPTP v8.1.0. Released v2.4.0.
% 0.11/0.14  % Command  : run_spass %d %s
% 0.13/0.35  % Computer : n019.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Sun Jun 12 16:38:10 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 24 clauses, backtracked 0 clauses, performed 0 splits and kept 104 clauses.
% 0.20/0.45  SPASS allocated 75868 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.08 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.00 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.01 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 0, length 14 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : co1_5 co1_6 co1_7 co1_8 co1_9 co1_12
% 0.20/0.45  
%------------------------------------------------------------------------------