TSTP Solution File: SEV259^5 by Duper---1.0

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEV259^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:37 EDT 2023

% Result   : Theorem 3.77s 4.00s
% Output   : Proof 3.86s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEV259^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n014.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Thu Aug 24 02:24:19 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.77/4.00  SZS status Theorem for theBenchmark.p
% 3.77/4.00  SZS output start Proof for theBenchmark.p
% 3.77/4.00  Clause #0 (by assumption #[]): Eq
% 3.77/4.00    (Not
% 3.77/4.00      (∀ (S : (b → Prop) → Prop),
% 3.77/4.00        And
% 3.77/4.00            (And
% 3.77/4.00              (And (∀ (R : b → Prop), (Eq R fun Xx => False) → S R) (∀ (R : b → Prop), (Eq R fun Xx => Not False) → S R))
% 3.77/4.00              (∀ (K : (b → Prop) → Prop) (R : b → Prop),
% 3.77/4.00                And (∀ (Xx : b → Prop), K Xx → S Xx) (Eq R fun Xx => Exists fun S0 => And (K S0) (S0 Xx)) → S R))
% 3.77/4.00            (∀ (Y Z S0 : b → Prop), And (And (S Y) (S Z)) (Eq S0 fun Xx => And (Y Xx) (Z Xx)) → S S0) →
% 3.77/4.00          ∀ (W : b → Prop) (Xx : b),
% 3.77/4.00            W Xx →
% 3.77/4.00              ∀ (S0 : b → Prop),
% 3.77/4.00                And (∀ (Xx0 : b), W Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → S R) → S0 Xx))
% 3.77/4.00    True
% 3.77/4.00  Clause #1 (by clausification #[0]): Eq
% 3.77/4.00    (∀ (S : (b → Prop) → Prop),
% 3.77/4.00      And
% 3.77/4.00          (And (And (∀ (R : b → Prop), (Eq R fun Xx => False) → S R) (∀ (R : b → Prop), (Eq R fun Xx => Not False) → S R))
% 3.77/4.00            (∀ (K : (b → Prop) → Prop) (R : b → Prop),
% 3.77/4.00              And (∀ (Xx : b → Prop), K Xx → S Xx) (Eq R fun Xx => Exists fun S0 => And (K S0) (S0 Xx)) → S R))
% 3.77/4.00          (∀ (Y Z S0 : b → Prop), And (And (S Y) (S Z)) (Eq S0 fun Xx => And (Y Xx) (Z Xx)) → S S0) →
% 3.77/4.00        ∀ (W : b → Prop) (Xx : b),
% 3.77/4.00          W Xx →
% 3.77/4.00            ∀ (S0 : b → Prop),
% 3.77/4.00              And (∀ (Xx0 : b), W Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → S R) → S0 Xx)
% 3.77/4.00    False
% 3.77/4.00  Clause #2 (by clausification #[1]): ∀ (a : (b → Prop) → Prop),
% 3.77/4.00    Eq
% 3.77/4.00      (Not
% 3.77/4.00        (And
% 3.77/4.00            (And
% 3.77/4.00              (And (∀ (R : b → Prop), (Eq R fun Xx => False) → skS.0 0 a R)
% 3.77/4.00                (∀ (R : b → Prop), (Eq R fun Xx => Not False) → skS.0 0 a R))
% 3.77/4.00              (∀ (K : (b → Prop) → Prop) (R : b → Prop),
% 3.77/4.00                And (∀ (Xx : b → Prop), K Xx → skS.0 0 a Xx) (Eq R fun Xx => Exists fun S0 => And (K S0) (S0 Xx)) →
% 3.77/4.00                  skS.0 0 a R))
% 3.77/4.00            (∀ (Y Z S0 : b → Prop),
% 3.77/4.00              And (And (skS.0 0 a Y) (skS.0 0 a Z)) (Eq S0 fun Xx => And (Y Xx) (Z Xx)) → skS.0 0 a S0) →
% 3.77/4.00          ∀ (W : b → Prop) (Xx : b),
% 3.77/4.00            W Xx →
% 3.77/4.00              ∀ (S0 : b → Prop),
% 3.77/4.00                And (∀ (Xx0 : b), W Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.77/4.00                  S0 Xx))
% 3.77/4.00      True
% 3.77/4.00  Clause #3 (by clausification #[2]): ∀ (a : (b → Prop) → Prop),
% 3.77/4.00    Eq
% 3.77/4.00      (And
% 3.77/4.00          (And
% 3.77/4.00            (And (∀ (R : b → Prop), (Eq R fun Xx => False) → skS.0 0 a R)
% 3.77/4.00              (∀ (R : b → Prop), (Eq R fun Xx => Not False) → skS.0 0 a R))
% 3.77/4.00            (∀ (K : (b → Prop) → Prop) (R : b → Prop),
% 3.77/4.00              And (∀ (Xx : b → Prop), K Xx → skS.0 0 a Xx) (Eq R fun Xx => Exists fun S0 => And (K S0) (S0 Xx)) →
% 3.77/4.00                skS.0 0 a R))
% 3.77/4.00          (∀ (Y Z S0 : b → Prop),
% 3.77/4.00            And (And (skS.0 0 a Y) (skS.0 0 a Z)) (Eq S0 fun Xx => And (Y Xx) (Z Xx)) → skS.0 0 a S0) →
% 3.77/4.00        ∀ (W : b → Prop) (Xx : b),
% 3.77/4.00          W Xx →
% 3.77/4.00            ∀ (S0 : b → Prop),
% 3.77/4.00              And (∀ (Xx0 : b), W Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) → S0 Xx)
% 3.77/4.00      False
% 3.77/4.00  Clause #5 (by clausification #[3]): ∀ (a : (b → Prop) → Prop),
% 3.77/4.00    Eq
% 3.77/4.00      (∀ (W : b → Prop) (Xx : b),
% 3.77/4.00        W Xx →
% 3.77/4.00          ∀ (S0 : b → Prop),
% 3.77/4.00            And (∀ (Xx0 : b), W Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) → S0 Xx)
% 3.77/4.00      False
% 3.77/4.00  Clause #15 (by clausification #[5]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop),
% 3.77/4.00    Eq
% 3.77/4.00      (Not
% 3.77/4.00        (∀ (Xx : b),
% 3.77/4.00          skS.0 1 a a_1 Xx →
% 3.77/4.00            ∀ (S0 : b → Prop),
% 3.77/4.00              And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → S0 Xx0)
% 3.77/4.00                  (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.77/4.00                S0 Xx))
% 3.77/4.00      True
% 3.77/4.00  Clause #16 (by clausification #[15]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop),
% 3.77/4.00    Eq
% 3.77/4.00      (∀ (Xx : b),
% 3.77/4.00        skS.0 1 a a_1 Xx →
% 3.77/4.00          ∀ (S0 : b → Prop),
% 3.86/4.03            And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → S0 Xx0)
% 3.86/4.03                (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.86/4.03              S0 Xx)
% 3.86/4.03      False
% 3.86/4.03  Clause #17 (by clausification #[16]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b),
% 3.86/4.03    Eq
% 3.86/4.03      (Not
% 3.86/4.03        (skS.0 1 a a_1 (skS.0 2 a a_1 a_2) →
% 3.86/4.03          ∀ (S0 : b → Prop),
% 3.86/4.03            And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → S0 Xx0)
% 3.86/4.03                (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.86/4.03              S0 (skS.0 2 a a_1 a_2)))
% 3.86/4.03      True
% 3.86/4.03  Clause #18 (by clausification #[17]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b),
% 3.86/4.03    Eq
% 3.86/4.03      (skS.0 1 a a_1 (skS.0 2 a a_1 a_2) →
% 3.86/4.03        ∀ (S0 : b → Prop),
% 3.86/4.03          And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.86/4.03            S0 (skS.0 2 a a_1 a_2))
% 3.86/4.03      False
% 3.86/4.03  Clause #19 (by clausification #[18]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b), Eq (skS.0 1 a a_1 (skS.0 2 a a_1 a_2)) True
% 3.86/4.03  Clause #20 (by clausification #[18]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b),
% 3.86/4.03    Eq
% 3.86/4.03      (∀ (S0 : b → Prop),
% 3.86/4.03        And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → S0 Xx0) (∀ (R : b → Prop), (Eq R fun Xx0 => Not (S0 Xx0)) → skS.0 0 a R) →
% 3.86/4.03          S0 (skS.0 2 a a_1 a_2))
% 3.86/4.03      False
% 3.86/4.03  Clause #22 (by clausification #[20]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop),
% 3.86/4.03    Eq
% 3.86/4.03      (Not
% 3.86/4.03        (And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → skS.0 3 a a_1 a_2 a_3 Xx0)
% 3.86/4.03            (∀ (R : b → Prop), (Eq R fun Xx0 => Not (skS.0 3 a a_1 a_2 a_3 Xx0)) → skS.0 0 a R) →
% 3.86/4.03          skS.0 3 a a_1 a_2 a_3 (skS.0 2 a a_1 a_2)))
% 3.86/4.03      True
% 3.86/4.03  Clause #23 (by clausification #[22]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop),
% 3.86/4.03    Eq
% 3.86/4.03      (And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → skS.0 3 a a_1 a_2 a_3 Xx0)
% 3.86/4.03          (∀ (R : b → Prop), (Eq R fun Xx0 => Not (skS.0 3 a a_1 a_2 a_3 Xx0)) → skS.0 0 a R) →
% 3.86/4.03        skS.0 3 a a_1 a_2 a_3 (skS.0 2 a a_1 a_2))
% 3.86/4.03      False
% 3.86/4.03  Clause #24 (by clausification #[23]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop),
% 3.86/4.03    Eq
% 3.86/4.03      (And (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → skS.0 3 a a_1 a_2 a_3 Xx0)
% 3.86/4.03        (∀ (R : b → Prop), (Eq R fun Xx0 => Not (skS.0 3 a a_1 a_2 a_3 Xx0)) → skS.0 0 a R))
% 3.86/4.03      True
% 3.86/4.03  Clause #25 (by clausification #[23]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop),
% 3.86/4.03    Eq (skS.0 3 a a_1 a_2 a_3 (skS.0 2 a a_1 a_2)) False
% 3.86/4.03  Clause #27 (by clausification #[24]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop),
% 3.86/4.03    Eq (∀ (Xx0 : b), skS.0 1 a a_1 Xx0 → skS.0 3 a a_1 a_2 a_3 Xx0) True
% 3.86/4.03  Clause #32 (by clausification #[27]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 a_3 : b) (a_4 : b → Prop),
% 3.86/4.03    Eq (skS.0 1 a a_1 a_2 → skS.0 3 a a_1 a_3 a_4 a_2) True
% 3.86/4.03  Clause #33 (by clausification #[32]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 a_3 : b) (a_4 : b → Prop),
% 3.86/4.03    Or (Eq (skS.0 1 a a_1 a_2) False) (Eq (skS.0 3 a a_1 a_3 a_4 a_2) True)
% 3.86/4.03  Clause #34 (by superposition #[33, 19]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop) (a_4 : b),
% 3.86/4.03    Or (Eq (skS.0 3 (fun x => a x) (fun x => a_1 x) a_2 a_3 (skS.0 2 a a_1 a_4)) True) (Eq False True)
% 3.86/4.03  Clause #97 (by betaEtaReduce #[34]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop) (a_4 : b),
% 3.86/4.03    Or (Eq (skS.0 3 a a_1 a_2 a_3 (skS.0 2 a a_1 a_4)) True) (Eq False True)
% 3.86/4.03  Clause #98 (by clausification #[97]): ∀ (a : (b → Prop) → Prop) (a_1 : b → Prop) (a_2 : b) (a_3 : b → Prop) (a_4 : b),
% 3.86/4.03    Eq (skS.0 3 a a_1 a_2 a_3 (skS.0 2 a a_1 a_4)) True
% 3.86/4.03  Clause #99 (by superposition #[98, 25]): Eq True False
% 3.86/4.03  Clause #103 (by clausification #[99]): False
% 3.86/4.03  SZS output end Proof for theBenchmark.p
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