TSTP Solution File: SEV135^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV135^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:20 EDT 2023

% Result   : Theorem 3.31s 3.50s
% Output   : Proof 3.31s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : SEV135^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.36  % Computer : n010.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit   : 300
% 0.14/0.36  % WCLimit    : 300
% 0.14/0.36  % DateTime   : Thu Aug 24 02:35:51 EDT 2023
% 0.14/0.36  % CPUTime    : 
% 3.31/3.50  SZS status Theorem for theBenchmark.p
% 3.31/3.50  SZS output start Proof for theBenchmark.p
% 3.31/3.50  Clause #0 (by assumption #[]): Eq
% 3.31/3.50    (Not
% 3.31/3.50      (∀ (Xr : a → a → Prop) (Xx Xy : a),
% 3.31/3.50        Xr Xx Xy →
% 3.31/3.50          ∀ (Xq : a → Prop), And (∀ (Xw : a), Xr Xx Xw → Xq Xw) (∀ (Xu Xv : a), And (Xq Xu) (Xr Xu Xv) → Xq Xv) → Xq Xy))
% 3.31/3.50    True
% 3.31/3.50  Clause #1 (by clausification #[0]): Eq
% 3.31/3.50    (∀ (Xr : a → a → Prop) (Xx Xy : a),
% 3.31/3.50      Xr Xx Xy →
% 3.31/3.50        ∀ (Xq : a → Prop), And (∀ (Xw : a), Xr Xx Xw → Xq Xw) (∀ (Xu Xv : a), And (Xq Xu) (Xr Xu Xv) → Xq Xv) → Xq Xy)
% 3.31/3.50    False
% 3.31/3.50  Clause #2 (by clausification #[1]): ∀ (a_1 : a → a → Prop),
% 3.31/3.50    Eq
% 3.31/3.50      (Not
% 3.31/3.50        (∀ (Xx Xy : a),
% 3.31/3.50          skS.0 0 a_1 Xx Xy →
% 3.31/3.50            ∀ (Xq : a → Prop),
% 3.31/3.50              And (∀ (Xw : a), skS.0 0 a_1 Xx Xw → Xq Xw) (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50                Xq Xy))
% 3.31/3.50      True
% 3.31/3.50  Clause #3 (by clausification #[2]): ∀ (a_1 : a → a → Prop),
% 3.31/3.50    Eq
% 3.31/3.50      (∀ (Xx Xy : a),
% 3.31/3.50        skS.0 0 a_1 Xx Xy →
% 3.31/3.50          ∀ (Xq : a → Prop),
% 3.31/3.50            And (∀ (Xw : a), skS.0 0 a_1 Xx Xw → Xq Xw) (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) → Xq Xy)
% 3.31/3.50      False
% 3.31/3.50  Clause #4 (by clausification #[3]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.31/3.50    Eq
% 3.31/3.50      (Not
% 3.31/3.50        (∀ (Xy : a),
% 3.31/3.50          skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy →
% 3.31/3.50            ∀ (Xq : a → Prop),
% 3.31/3.50              And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → Xq Xw)
% 3.31/3.50                  (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50                Xq Xy))
% 3.31/3.50      True
% 3.31/3.50  Clause #5 (by clausification #[4]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.31/3.50    Eq
% 3.31/3.50      (∀ (Xy : a),
% 3.31/3.50        skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy →
% 3.31/3.50          ∀ (Xq : a → Prop),
% 3.31/3.50            And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → Xq Xw)
% 3.31/3.50                (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50              Xq Xy)
% 3.31/3.50      False
% 3.31/3.50  Clause #6 (by clausification #[5]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.31/3.50    Eq
% 3.31/3.50      (Not
% 3.31/3.50        (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.31/3.50          ∀ (Xq : a → Prop),
% 3.31/3.50            And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → Xq Xw)
% 3.31/3.50                (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50              Xq (skS.0 2 a_1 a_2 a_3)))
% 3.31/3.50      True
% 3.31/3.50  Clause #7 (by clausification #[6]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.31/3.50    Eq
% 3.31/3.50      (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.31/3.50        ∀ (Xq : a → Prop),
% 3.31/3.50          And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → Xq Xw)
% 3.31/3.50              (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50            Xq (skS.0 2 a_1 a_2 a_3))
% 3.31/3.50      False
% 3.31/3.50  Clause #8 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True
% 3.31/3.50  Clause #9 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.31/3.50    Eq
% 3.31/3.50      (∀ (Xq : a → Prop),
% 3.31/3.50        And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → Xq Xw)
% 3.31/3.50            (∀ (Xu Xv : a), And (Xq Xu) (skS.0 0 a_1 Xu Xv) → Xq Xv) →
% 3.31/3.50          Xq (skS.0 2 a_1 a_2 a_3))
% 3.31/3.50      False
% 3.31/3.50  Clause #10 (by clausification #[9]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop),
% 3.31/3.50    Eq
% 3.31/3.50      (Not
% 3.31/3.50        (And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → skS.0 3 a_1 a_2 a_3 a_4 Xw)
% 3.31/3.50            (∀ (Xu Xv : a), And (skS.0 3 a_1 a_2 a_3 a_4 Xu) (skS.0 0 a_1 Xu Xv) → skS.0 3 a_1 a_2 a_3 a_4 Xv) →
% 3.31/3.50          skS.0 3 a_1 a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_3)))
% 3.31/3.50      True
% 3.31/3.50  Clause #11 (by clausification #[10]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop),
% 3.31/3.50    Eq
% 3.31/3.50      (And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → skS.0 3 a_1 a_2 a_3 a_4 Xw)
% 3.31/3.50          (∀ (Xu Xv : a), And (skS.0 3 a_1 a_2 a_3 a_4 Xu) (skS.0 0 a_1 Xu Xv) → skS.0 3 a_1 a_2 a_3 a_4 Xv) →
% 3.31/3.50        skS.0 3 a_1 a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_3))
% 3.31/3.50      False
% 3.31/3.50  Clause #12 (by clausification #[11]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop),
% 3.31/3.50    Eq
% 3.31/3.50      (And (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → skS.0 3 a_1 a_2 a_3 a_4 Xw)
% 3.31/3.50        (∀ (Xu Xv : a), And (skS.0 3 a_1 a_2 a_3 a_4 Xu) (skS.0 0 a_1 Xu Xv) → skS.0 3 a_1 a_2 a_3 a_4 Xv))
% 3.31/3.51      True
% 3.31/3.51  Clause #13 (by clausification #[11]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop), Eq (skS.0 3 a_1 a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_3)) False
% 3.31/3.51  Clause #15 (by clausification #[12]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop),
% 3.31/3.51    Eq (∀ (Xw : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xw → skS.0 3 a_1 a_2 a_3 a_4 Xw) True
% 3.31/3.51  Clause #20 (by clausification #[15]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a) (a_5 : a → Prop),
% 3.31/3.51    Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3 → skS.0 3 a_1 a_2 a_4 a_5 a_3) True
% 3.31/3.51  Clause #21 (by clausification #[20]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a) (a_5 : a → Prop),
% 3.31/3.51    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3) False) (Eq (skS.0 3 a_1 a_2 a_4 a_5 a_3) True)
% 3.31/3.51  Clause #22 (by superposition #[21, 8]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop) (a_5 : a),
% 3.31/3.51    Or (Eq (skS.0 3 (fun x x_1 => a_1 x x_1) a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_5)) True) (Eq False True)
% 3.31/3.51  Clause #23 (by betaEtaReduce #[22]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop) (a_5 : a),
% 3.31/3.51    Or (Eq (skS.0 3 a_1 a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_5)) True) (Eq False True)
% 3.31/3.51  Clause #24 (by clausification #[23]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a) (a_4 : a → Prop) (a_5 : a), Eq (skS.0 3 a_1 a_2 a_3 a_4 (skS.0 2 a_1 a_2 a_5)) True
% 3.31/3.51  Clause #25 (by superposition #[24, 13]): Eq True False
% 3.31/3.51  Clause #27 (by clausification #[25]): False
% 3.31/3.51  SZS output end Proof for theBenchmark.p
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