TSTP Solution File: SEV058^5 by cocATP---0.2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SEV058^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n110.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32286.75MB
% OS : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:40 EDT 2014
% Result : Unknown 0.66s
% Output : None
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem : SEV058^5 : TPTP v6.1.0. Released v4.0.0.
% % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n110.star.cs.uiowa.edu
% % Model : x86_64 x86_64
% % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory : 32286.75MB
% % OS : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 07:49:26 CDT 2014
% % CPUTime : 0.66
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> ((and ((and (forall (Xu:(fofType->Prop)) (Xv:(fofType->Prop)), (((R Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))) (forall (Xx:(fofType->Prop)), ((R Xx) Xx)))) (forall (Xx:(fofType->Prop)) (Xy:(fofType->Prop)) (Xz:(fofType->Prop)), (((and ((R Xx) Xy)) ((R Xy) Xz))->((R Xx) Xz)))))) of role conjecture named cTHM122_pme
% Conjecture to prove = ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> ((and ((and (forall (Xu:(fofType->Prop)) (Xv:(fofType->Prop)), (((R Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))) (forall (Xx:(fofType->Prop)), ((R Xx) Xx)))) (forall (Xx:(fofType->Prop)) (Xy:(fofType->Prop)) (Xz:(fofType->Prop)), (((and ((R Xx) Xy)) ((R Xy) Xz))->((R Xx) Xz)))))):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> ((and ((and (forall (Xu:(fofType->Prop)) (Xv:(fofType->Prop)), (((R Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))) (forall (Xx:(fofType->Prop)), ((R Xx) Xx)))) (forall (Xx:(fofType->Prop)) (Xy:(fofType->Prop)) (Xz:(fofType->Prop)), (((and ((R Xx) Xy)) ((R Xy) Xz))->((R Xx) Xz))))))']
% Parameter fofType:Type.
% Trying to prove ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> ((and ((and (forall (Xu:(fofType->Prop)) (Xv:(fofType->Prop)), (((R Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))) (forall (Xx:(fofType->Prop)), ((R Xx) Xx)))) (forall (Xx:(fofType->Prop)) (Xy:(fofType->Prop)) (Xz:(fofType->Prop)), (((and ((R Xx) Xy)) ((R Xy) Xz))->((R Xx) Xz))))))
% Found x0:((x Xu) Xv)
% Found x0 as proof of (forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))
% Found (fun (x0:((x Xu) Xv))=> x0) as proof of (forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))
% Found (fun (Xv:(fofType->Prop)) (x0:((x Xu) Xv))=> x0) as proof of (((x Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz))))
% Found (fun (Xu:(fofType->Prop)) (Xv:(fofType->Prop)) (x0:((x Xu) Xv))=> x0) as proof of (forall (Xv:(fofType->Prop)), (((x Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))
% Found (fun (Xu:(fofType->Prop)) (Xv:(fofType->Prop)) (x0:((x Xu) Xv))=> x0) as proof of (forall (Xu:(fofType->Prop)) (Xv:(fofType->Prop)), (((x Xu) Xv)->(forall (Xz:fofType), ((Xu Xz)->(Xv Xz)))))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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