%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV056^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n091.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:40 EDT 2014

% Result   : Unknown 0.66s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV056^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n091.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 07:48:26 CDT 2014
% % CPUTime  : 0.66 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0xa73ea8>, <kernel.Type object at 0xa73d40>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (forall (Xr:(a->(a->Prop))), ((ex (a->(a->Prop))) (fun (Xp:(a->(a->Prop)))=> ((and (forall (Xx:a) (Xy:a), (((Xr Xx) Xy)->((Xp Xx) Xy)))) (forall (Xx:a) (Xy:a) (Xz:a), (((and ((Xp Xx) Xy)) ((Xp Xy) Xz))->((Xp Xx) Xz))))))) of role conjecture named cTHM275_pme
% Conjecture to prove = (forall (Xr:(a->(a->Prop))), ((ex (a->(a->Prop))) (fun (Xp:(a->(a->Prop)))=> ((and (forall (Xx:a) (Xy:a), (((Xr Xx) Xy)->((Xp Xx) Xy)))) (forall (Xx:a) (Xy:a) (Xz:a), (((and ((Xp Xx) Xy)) ((Xp Xy) Xz))->((Xp Xx) Xz))))))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['(forall (Xr:(a->(a->Prop))), ((ex (a->(a->Prop))) (fun (Xp:(a->(a->Prop)))=> ((and (forall (Xx:a) (Xy:a), (((Xr Xx) Xy)->((Xp Xx) Xy)))) (forall (Xx:a) (Xy:a) (Xz:a), (((and ((Xp Xx) Xy)) ((Xp Xy) Xz))->((Xp Xx) Xz)))))))']
% Parameter a:Type.
% Trying to prove (forall (Xr:(a->(a->Prop))), ((ex (a->(a->Prop))) (fun (Xp:(a->(a->Prop)))=> ((and (forall (Xx:a) (Xy:a), (((Xr Xx) Xy)->((Xp Xx) Xy)))) (forall (Xx:a) (Xy:a) (Xz:a), (((and ((Xp Xx) Xy)) ((Xp Xy) Xz))->((Xp Xx) Xz)))))))
% Found x0:((Xr Xx) Xy)
% Instantiate: x:=Xr:(a->(a->Prop))
% Found (fun (x0:((Xr Xx) Xy))=> x0) as proof of ((x Xx) Xy)
% Found (fun (Xy:a) (x0:((Xr Xx) Xy))=> x0) as proof of (((Xr Xx) Xy)->((x Xx) Xy))
% Found (fun (Xx:a) (Xy:a) (x0:((Xr Xx) Xy))=> x0) as proof of (forall (Xy:a), (((Xr Xx) Xy)->((x Xx) Xy)))
% Found (fun (Xx:a) (Xy:a) (x0:((Xr Xx) Xy))=> x0) as proof of (forall (Xx:a) (Xy:a), (((Xr Xx) Xy)->((x Xx) Xy)))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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