TSTP Solution File: SEU963^5 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SEU963^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n107.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32286.75MB
% OS : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:26 EDT 2014
% Result : Unknown 1.84s
% Output : None
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem : SEU963^5 : TPTP v6.1.0. Released v4.0.0.
% % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n107.star.cs.uiowa.edu
% % Model : x86_64 x86_64
% % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory : 32286.75MB
% % OS : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 11:46:36 CDT 2014
% % CPUTime : 1.84
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x140c908>, <kernel.Type object at 0x140c518>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (forall (Xf:(a->a)) (Xg:(a->a)) (Xh:(a->a)), (((and (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp (fun (Xx:a)=> (Xg (Xh Xx))))))) (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xh))))->(forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xg))))) of role conjecture named cTHM93_pme
% Conjecture to prove = (forall (Xf:(a->a)) (Xg:(a->a)) (Xh:(a->a)), (((and (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp (fun (Xx:a)=> (Xg (Xh Xx))))))) (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xh))))->(forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xg))))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['(forall (Xf:(a->a)) (Xg:(a->a)) (Xh:(a->a)), (((and (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp (fun (Xx:a)=> (Xg (Xh Xx))))))) (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xh))))->(forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xg)))))']
% Parameter a:Type.
% Trying to prove (forall (Xf:(a->a)) (Xg:(a->a)) (Xh:(a->a)), (((and (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp (fun (Xx:a)=> (Xg (Xh Xx))))))) (forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xh))))->(forall (Xp:((a->a)->Prop)), (((and (Xp (fun (Xu:a)=> Xu))) (forall (Xj:(a->a)), ((Xp Xj)->(Xp (fun (Xx:a)=> (Xf (Xj Xx)))))))->(Xp Xg)))))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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