%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEU923^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n105.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:23 EDT 2014

% Result   : Theorem 0.42s
% Output   : Proof 0.42s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEU923^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n105.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 11:42:56 CDT 2014
% % CPUTime  : 0.42 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x29ded88>, <kernel.Type object at 0x2984488>) of role type named b_type
% Using role type
% Declaring b:Type
% FOF formula (<kernel.Constant object at 0x29de248>, <kernel.Type object at 0x2984488>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x29ded88>, <kernel.DependentProduct object at 0x2984950>) of role type named cF
% Using role type
% Declaring cF:(b->a)
% FOF formula ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))) of role conjecture named cTHM54_pme
% Conjecture to prove = ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))):Prop
% Parameter b_DUMMY:b.
% Parameter a_DUMMY:a.
% We need to prove ['((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))']
% Parameter b:Type.
% Parameter a:Type.
% Parameter cF:(b->a).
% Trying to prove ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))
% Found x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))
% Found (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) as proof of (forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))
% Found (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x) as proof of ((forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy)))->(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))
% Got proof (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x)
% Time elapsed = 0.109077s
% node=1 cost=2.000000 depth=1
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (fun (x:(forall (Xx:b) (Xy:b), ((((eq a) (cF Xx)) (cF Xy))->(((eq b) Xx) Xy))))=> x)
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------