%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU917^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:44:18 EDT 2023

% Result   : Theorem 3.75s 3.96s
% Output   : Proof 3.75s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU917^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n020.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Wed Aug 23 13:30:31 EDT 2023
% 0.14/0.34  % CPUTime    : 
% 3.75/3.96  SZS status Theorem for theBenchmark.p
% 3.75/3.96  SZS output start Proof for theBenchmark.p
% 3.75/3.96  Clause #0 (by assumption #[]): Eq (Not (Exists fun F => ∀ (Xx Xy : Iota), Eq (F Xx) (F Xy) → Eq Xx Xy)) True
% 3.75/3.96  Clause #1 (by clausification #[0]): Eq (Exists fun F => ∀ (Xx Xy : Iota), Eq (F Xx) (F Xy) → Eq Xx Xy) False
% 3.75/3.96  Clause #2 (by clausification #[1]): ∀ (a : Iota → Iota), Eq (∀ (Xx Xy : Iota), Eq (a Xx) (a Xy) → Eq Xx Xy) False
% 3.75/3.96  Clause #3 (by clausification #[2]): ∀ (a : Iota → Iota) (a_1 : Iota), Eq (Not (∀ (Xy : Iota), Eq (a (skS.0 0 a a_1)) (a Xy) → Eq (skS.0 0 a a_1) Xy)) True
% 3.75/3.96  Clause #4 (by clausification #[3]): ∀ (a : Iota → Iota) (a_1 : Iota), Eq (∀ (Xy : Iota), Eq (a (skS.0 0 a a_1)) (a Xy) → Eq (skS.0 0 a a_1) Xy) False
% 3.75/3.96  Clause #5 (by clausification #[4]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota),
% 3.75/3.96    Eq (Not (Eq (a (skS.0 0 a a_1)) (a (skS.0 1 a a_1 a_2)) → Eq (skS.0 0 a a_1) (skS.0 1 a a_1 a_2))) True
% 3.75/3.96  Clause #6 (by clausification #[5]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota),
% 3.75/3.96    Eq (Eq (a (skS.0 0 a a_1)) (a (skS.0 1 a a_1 a_2)) → Eq (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)) False
% 3.75/3.96  Clause #7 (by clausification #[6]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Eq (Eq (a (skS.0 0 a a_1)) (a (skS.0 1 a a_1 a_2))) True
% 3.75/3.96  Clause #8 (by clausification #[6]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Eq (Eq (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)) False
% 3.75/3.96  Clause #9 (by clausification #[7]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Eq (a (skS.0 0 a a_1)) (a (skS.0 1 a a_1 a_2))
% 3.75/3.96  Clause #18 (by clausification #[8]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Ne (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)
% 3.75/3.96  Clause #19 (by superposition #[18, 9]): ∀ (a : Iota), Ne (skS.0 0 (fun x => x) a) (skS.0 0 (fun x => x) a)
% 3.75/3.96  Clause #20 (by eliminate resolved literals #[19]): False
% 3.75/3.96  SZS output end Proof for theBenchmark.p
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