TSTP Solution File: SEU858^5 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SEU858^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:44:09 EDT 2023
% Result : Theorem 3.23s 3.57s
% Output : Proof 3.23s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU858^5 : TPTP v8.1.2. Released v4.0.0.
% 0.14/0.13 % Command : duper %s
% 0.15/0.34 % Computer : n007.cluster.edu
% 0.15/0.34 % Model : x86_64 x86_64
% 0.15/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.34 % Memory : 8042.1875MB
% 0.15/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.34 % CPULimit : 300
% 0.15/0.34 % WCLimit : 300
% 0.15/0.34 % DateTime : Wed Aug 23 19:05:09 EDT 2023
% 0.15/0.35 % CPUTime :
% 3.23/3.57 SZS status Theorem for theBenchmark.p
% 3.23/3.57 SZS output start Proof for theBenchmark.p
% 3.23/3.57 Clause #0 (by assumption #[]): Eq
% 3.23/3.57 (Not
% 3.23/3.57 (∀ (Xw : (a → Prop) → Prop),
% 3.23/3.57 And (Xw fun Xx => False) (∀ (Xr : a → Prop) (Xx : a), Xw Xr → Xw fun Xt => Or (Xr Xt) (Eq Xt Xx)) →
% 3.23/3.57 Xw fun Xx => False))
% 3.23/3.57 True
% 3.23/3.57 Clause #1 (by clausification #[0]): Eq
% 3.23/3.57 (∀ (Xw : (a → Prop) → Prop),
% 3.23/3.57 And (Xw fun Xx => False) (∀ (Xr : a → Prop) (Xx : a), Xw Xr → Xw fun Xt => Or (Xr Xt) (Eq Xt Xx)) →
% 3.23/3.57 Xw fun Xx => False)
% 3.23/3.57 False
% 3.23/3.57 Clause #2 (by clausification #[1]): ∀ (a_1 : (a → Prop) → Prop),
% 3.23/3.57 Eq
% 3.23/3.57 (Not
% 3.23/3.57 (And (skS.0 0 a_1 fun Xx => False)
% 3.23/3.57 (∀ (Xr : a → Prop) (Xx : a), skS.0 0 a_1 Xr → skS.0 0 a_1 fun Xt => Or (Xr Xt) (Eq Xt Xx)) →
% 3.23/3.57 skS.0 0 a_1 fun Xx => False))
% 3.23/3.57 True
% 3.23/3.57 Clause #3 (by clausification #[2]): ∀ (a_1 : (a → Prop) → Prop),
% 3.23/3.57 Eq
% 3.23/3.57 (And (skS.0 0 a_1 fun Xx => False)
% 3.23/3.57 (∀ (Xr : a → Prop) (Xx : a), skS.0 0 a_1 Xr → skS.0 0 a_1 fun Xt => Or (Xr Xt) (Eq Xt Xx)) →
% 3.23/3.57 skS.0 0 a_1 fun Xx => False)
% 3.23/3.57 False
% 3.23/3.57 Clause #4 (by clausification #[3]): ∀ (a_1 : (a → Prop) → Prop),
% 3.23/3.57 Eq
% 3.23/3.57 (And (skS.0 0 a_1 fun Xx => False)
% 3.23/3.57 (∀ (Xr : a → Prop) (Xx : a), skS.0 0 a_1 Xr → skS.0 0 a_1 fun Xt => Or (Xr Xt) (Eq Xt Xx)))
% 3.23/3.57 True
% 3.23/3.57 Clause #5 (by clausification #[3]): ∀ (a_1 : (a → Prop) → Prop), Eq (skS.0 0 a_1 fun Xx => False) False
% 3.23/3.57 Clause #7 (by clausification #[4]): ∀ (a_1 : (a → Prop) → Prop), Eq (skS.0 0 a_1 fun Xx => False) True
% 3.23/3.57 Clause #11 (by superposition #[7, 5]): Eq True False
% 3.23/3.57 Clause #14 (by clausification #[11]): False
% 3.23/3.57 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------