TSTP Solution File: SEU561^2 by Vampire---4.8

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Vampire---4.8
% Problem  : SEU561^2 : TPTP v8.2.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule file --schedule_file /export/starexec/sandbox2/solver/bin/quickGreedyProduceRating_steal_pow3.txt --cores 8 -m 12000 -t %d %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue May 21 03:49:35 EDT 2024

% Result   : Theorem 0.15s 0.38s
% Output   : Refutation 0.15s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : SEU561^2 : TPTP v8.2.0. Released v3.7.0.
% 0.13/0.14  % Command    : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule file --schedule_file /export/starexec/sandbox2/solver/bin/quickGreedyProduceRating_steal_pow3.txt --cores 8 -m 12000 -t %d %s
% 0.15/0.35  % Computer : n026.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35  % CPULimit   : 300
% 0.15/0.35  % WCLimit    : 300
% 0.15/0.35  % DateTime   : Sun May 19 15:44:38 EDT 2024
% 0.15/0.35  % CPUTime    : 
% 0.15/0.35  This is a TH0_THM_EQU_NAR problem
% 0.15/0.36  Running vampire_ho --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_hol --cores 8 -m 12000 -t 300 /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.15/0.37  % (9922)lrs+1002_1:8_bd=off:fd=off:hud=10:tnu=1:i=183:si=on:rtra=on_0 on theBenchmark for (2999ds/183Mi)
% 0.15/0.37  % (9924)dis+1010_1:1_au=on:cbe=off:chr=on:fsr=off:hfsq=on:nm=64:sos=theory:sp=weighted_frequency:i=27:si=on:rtra=on_0 on theBenchmark for (2999ds/27Mi)
% 0.15/0.37  % (9925)lrs+10_1:1_au=on:inj=on:i=2:si=on:rtra=on_0 on theBenchmark for (2999ds/2Mi)
% 0.15/0.37  % (9923)lrs+10_1:1_c=on:cnfonf=conj_eager:fd=off:fe=off:kws=frequency:spb=intro:i=4:si=on:rtra=on_0 on theBenchmark for (2999ds/4Mi)
% 0.15/0.37  % (9927)lrs+1002_1:1_au=on:bd=off:e2e=on:sd=2:sos=on:ss=axioms:i=275:si=on:rtra=on_0 on theBenchmark for (2999ds/275Mi)
% 0.15/0.37  % (9926)lrs+1002_1:128_aac=none:au=on:cnfonf=lazy_not_gen_be_off:sos=all:i=2:si=on:rtra=on_0 on theBenchmark for (2999ds/2Mi)
% 0.15/0.37  % (9928)lrs+1004_1:128_cond=on:e2e=on:sp=weighted_frequency:i=18:si=on:rtra=on_0 on theBenchmark for (2999ds/18Mi)
% 0.15/0.38  % (9922)First to succeed.
% 0.15/0.38  % (9926)Instruction limit reached!
% 0.15/0.38  % (9926)------------------------------
% 0.15/0.38  % (9926)Version: Vampire 4.8 HO - Sledgehammer schedules (2023-10-19)
% 0.15/0.38  % (9926)Termination reason: Unknown
% 0.15/0.38  % (9926)Termination phase: Saturation
% 0.15/0.38  
% 0.15/0.38  % (9926)Memory used [KB]: 5373
% 0.15/0.38  % (9926)Time elapsed: 0.004 s
% 0.15/0.38  % (9926)Instructions burned: 2 (million)
% 0.15/0.38  % (9926)------------------------------
% 0.15/0.38  % (9926)------------------------------
% 0.15/0.38  % (9924)Also succeeded, but the first one will report.
% 0.15/0.38  % (9922)Refutation found. Thanks to Tanya!
% 0.15/0.38  % SZS status Theorem for theBenchmark
% 0.15/0.38  % SZS output start Proof for theBenchmark
% 0.15/0.38  thf(func_def_0, type, in: $i > $i > $o).
% 0.15/0.38  thf(func_def_1, type, subset: $i > $i > $o).
% 0.15/0.38  thf(f33,plain,(
% 0.15/0.38    $false),
% 0.15/0.38    inference(trivial_inequality_removal,[],[f32])).
% 0.15/0.38  thf(f32,plain,(
% 0.15/0.38    ($true = $false)),
% 0.15/0.38    inference(beta_eta_normalization,[],[f31])).
% 0.15/0.38  thf(f31,plain,(
% 0.15/0.38    (((^[Y0 : $i]: ($true)) @ sK3) = $false)),
% 0.15/0.38    inference(sigma_clausification,[],[f30])).
% 0.15/0.38  thf(f30,plain,(
% 0.15/0.38    ($true != (!! @ $i @ (^[Y0 : $i]: ($true))))),
% 0.15/0.38    inference(boolean_simplification,[],[f29])).
% 0.15/0.38  thf(f29,plain,(
% 0.15/0.38    ($true != (!! @ $i @ (^[Y0 : $i]: ((in @ Y0 @ sK0) => (in @ Y0 @ sK0)))))),
% 0.15/0.38    inference(beta_eta_normalization,[],[f21])).
% 0.15/0.38  thf(f21,plain,(
% 0.15/0.38    (((^[Y0 : $i]: ((^[Y1 : $i]: (!! @ $i @ (^[Y2 : $i]: ((in @ Y2 @ Y0) => (in @ Y2 @ Y1))))))) @ sK0 @ sK0) != $true)),
% 0.15/0.38    inference(definition_unfolding,[],[f18,f19,f17])).
% 0.15/0.38  thf(f17,plain,(
% 0.15/0.38    (sK1 = sK0)),
% 0.15/0.38    inference(cnf_transformation,[],[f14])).
% 0.15/0.38  thf(f14,plain,(
% 0.15/0.38    (((subset @ sK1 @ sK0) != $true) & (sK1 = sK0)) & (subsetI1 = $true)),
% 0.15/0.38    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0,sK1])],[f12,f13])).
% 0.15/0.38  thf(f13,plain,(
% 0.15/0.38    ? [X0,X1] : (((subset @ X1 @ X0) != $true) & (X0 = X1)) => (((subset @ sK1 @ sK0) != $true) & (sK1 = sK0))),
% 0.15/0.38    introduced(choice_axiom,[])).
% 0.15/0.38  thf(f12,plain,(
% 0.15/0.38    ? [X0,X1] : (((subset @ X1 @ X0) != $true) & (X0 = X1)) & (subsetI1 = $true)),
% 0.15/0.38    inference(ennf_transformation,[],[f9])).
% 0.15/0.38  thf(f9,plain,(
% 0.15/0.38    ~((subsetI1 = $true) => ! [X0,X1] : ((X0 = X1) => ((subset @ X1 @ X0) = $true)))),
% 0.15/0.38    inference(fool_elimination,[],[f8])).
% 0.15/0.38  thf(f8,plain,(
% 0.15/0.38    ~(subsetI1 => ! [X0,X1] : ((X0 = X1) => (subset @ X1 @ X0)))),
% 0.15/0.38    inference(rectify,[],[f4])).
% 0.15/0.38  thf(f4,negated_conjecture,(
% 0.15/0.38    ~(subsetI1 => ! [X1,X0] : ((X0 = X1) => (subset @ X0 @ X1)))),
% 0.15/0.38    inference(negated_conjecture,[],[f3])).
% 0.15/0.38  thf(f3,conjecture,(
% 0.15/0.38    subsetI1 => ! [X1,X0] : ((X0 = X1) => (subset @ X0 @ X1))),
% 0.15/0.38    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',eqimpsubset1)).
% 0.15/0.38  thf(f19,plain,(
% 0.15/0.38    (subset = (^[Y0 : $i]: ((^[Y1 : $i]: (!! @ $i @ (^[Y2 : $i]: ((in @ Y2 @ Y0) => (in @ Y2 @ Y1))))))))),
% 0.15/0.38    inference(cnf_transformation,[],[f7])).
% 0.15/0.38  thf(f7,plain,(
% 0.15/0.38    (subset = (^[Y0 : $i]: ((^[Y1 : $i]: (!! @ $i @ (^[Y2 : $i]: ((in @ Y2 @ Y0) => (in @ Y2 @ Y1))))))))),
% 0.15/0.38    inference(fool_elimination,[],[f6])).
% 0.15/0.38  thf(f6,plain,(
% 0.15/0.38    (subset = (^[X0 : $i, X1 : $i] : (! [X2] : ((in @ X2 @ X0) => (in @ X2 @ X1)))))),
% 0.15/0.38    inference(rectify,[],[f1])).
% 0.15/0.38  thf(f1,axiom,(
% 0.15/0.38    (subset = (^[X0 : $i, X1 : $i] : (! [X2] : ((in @ X2 @ X0) => (in @ X2 @ X1)))))),
% 0.15/0.38    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',subset)).
% 0.15/0.38  thf(f18,plain,(
% 0.15/0.38    ((subset @ sK1 @ sK0) != $true)),
% 0.15/0.38    inference(cnf_transformation,[],[f14])).
% 0.15/0.38  % SZS output end Proof for theBenchmark
% 0.15/0.38  % (9922)------------------------------
% 0.15/0.38  % (9922)Version: Vampire 4.8 HO - Sledgehammer schedules (2023-10-19)
% 0.15/0.38  % (9922)Termination reason: Refutation
% 0.15/0.38  
% 0.15/0.38  % (9922)Memory used [KB]: 5500
% 0.15/0.38  % (9922)Time elapsed: 0.004 s
% 0.15/0.38  % (9922)Instructions burned: 2 (million)
% 0.15/0.38  % (9922)------------------------------
% 0.15/0.38  % (9922)------------------------------
% 0.15/0.38  % (9919)Success in time 0.007 s
% 0.15/0.38  % Vampire---4.8 exiting
%------------------------------------------------------------------------------