TSTP Solution File: SEU561^2 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU561^2 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:42:42 EDT 2023
% Result : Theorem 5.91s 6.11s
% Output : Proof 5.91s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : SEU561^2 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.12 % Command : duper %s
% 0.11/0.33 % Computer : n008.cluster.edu
% 0.11/0.33 % Model : x86_64 x86_64
% 0.11/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33 % Memory : 8042.1875MB
% 0.11/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33 % CPULimit : 300
% 0.11/0.33 % WCLimit : 300
% 0.11/0.33 % DateTime : Wed Aug 23 13:38:33 EDT 2023
% 0.11/0.33 % CPUTime :
% 5.91/6.11 SZS status Theorem for theBenchmark.p
% 5.91/6.11 SZS output start Proof for theBenchmark.p
% 5.91/6.11 Clause #1 (by assumption #[]): Eq (Eq subsetI1 (∀ (A B : Iota), (∀ (Xx : Iota), in Xx A → in Xx B) → subset A B)) True
% 5.91/6.11 Clause #2 (by assumption #[]): Eq (Not (subsetI1 → ∀ (A B : Iota), Eq A B → subset A B)) True
% 5.91/6.11 Clause #3 (by clausification #[2]): Eq (subsetI1 → ∀ (A B : Iota), Eq A B → subset A B) False
% 5.91/6.11 Clause #4 (by clausification #[3]): Eq subsetI1 True
% 5.91/6.11 Clause #5 (by clausification #[3]): Eq (∀ (A B : Iota), Eq A B → subset A B) False
% 5.91/6.11 Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Eq (skS.0 0 a) B → subset (skS.0 0 a) B)) True
% 5.91/6.11 Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (∀ (B : Iota), Eq (skS.0 0 a) B → subset (skS.0 0 a) B) False
% 5.91/6.11 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (Not (Eq (skS.0 0 a) (skS.0 1 a a_1) → subset (skS.0 0 a) (skS.0 1 a a_1))) True
% 5.91/6.11 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1) → subset (skS.0 0 a) (skS.0 1 a a_1)) False
% 5.91/6.11 Clause #10 (by clausification #[9]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) True
% 5.91/6.11 Clause #11 (by clausification #[9]): ∀ (a a_1 : Iota), Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) False
% 5.91/6.11 Clause #12 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (skS.0 0 a) (skS.0 1 a a_1)
% 5.91/6.11 Clause #13 (by clausification #[1]): Eq subsetI1 (∀ (A B : Iota), (∀ (Xx : Iota), in Xx A → in Xx B) → subset A B)
% 5.91/6.11 Clause #14 (by forward demodulation #[13, 4]): Eq True (∀ (A B : Iota), (∀ (Xx : Iota), in Xx A → in Xx B) → subset A B)
% 5.91/6.11 Clause #15 (by clausification #[14]): ∀ (a : Iota), Eq (∀ (B : Iota), (∀ (Xx : Iota), in Xx a → in Xx B) → subset a B) True
% 5.91/6.11 Clause #16 (by clausification #[15]): ∀ (a a_1 : Iota), Eq ((∀ (Xx : Iota), in Xx a → in Xx a_1) → subset a a_1) True
% 5.91/6.11 Clause #17 (by clausification #[16]): ∀ (a a_1 : Iota), Or (Eq (∀ (Xx : Iota), in Xx a → in Xx a_1) False) (Eq (subset a a_1) True)
% 5.91/6.11 Clause #18 (by clausification #[17]): ∀ (a a_1 a_2 : Iota),
% 5.91/6.11 Or (Eq (subset a a_1) True) (Eq (Not (in (skS.0 2 a a_1 a_2) a → in (skS.0 2 a a_1 a_2) a_1)) True)
% 5.91/6.11 Clause #19 (by clausification #[18]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 2 a a_1 a_2) a → in (skS.0 2 a a_1 a_2) a_1) False)
% 5.91/6.11 Clause #20 (by clausification #[19]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 2 a a_1 a_2) a) True)
% 5.91/6.11 Clause #21 (by clausification #[19]): ∀ (a a_1 a_2 : Iota), Or (Eq (subset a a_1) True) (Eq (in (skS.0 2 a a_1 a_2) a_1) False)
% 5.91/6.11 Clause #28 (by forward demodulation #[11, 12]): ∀ (a : Iota), Eq (subset (skS.0 0 a) (skS.0 0 a)) False
% 5.91/6.11 Clause #45 (by superposition #[21, 20]): ∀ (a : Iota), Or (Eq (subset a a) True) (Or (Eq (subset a a) True) (Eq False True))
% 5.91/6.11 Clause #47 (by clausification #[45]): ∀ (a : Iota), Or (Eq (subset a a) True) (Eq (subset a a) True)
% 5.91/6.11 Clause #48 (by eliminate duplicate literals #[47]): ∀ (a : Iota), Eq (subset a a) True
% 5.91/6.11 Clause #49 (by superposition #[48, 28]): Eq True False
% 5.91/6.11 Clause #51 (by clausification #[49]): False
% 5.91/6.11 SZS output end Proof for theBenchmark.p
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