TSTP Solution File: SEU553^2 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SEU553^2 : TPTP v8.1.2. Bugfixed v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:42:40 EDT 2023
% Result : Theorem 3.49s 3.70s
% Output : Proof 3.49s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SEU553^2 : TPTP v8.1.2. Bugfixed v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.15/0.35 % Computer : n031.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.35 % WCLimit : 300
% 0.15/0.35 % DateTime : Wed Aug 23 21:31:05 EDT 2023
% 0.15/0.35 % CPUTime :
% 3.49/3.70 SZS status Theorem for theBenchmark.p
% 3.49/3.70 SZS output start Proof for theBenchmark.p
% 3.49/3.70 Clause #0 (by assumption #[]): Eq (Not (∀ (A B : Iota), Eq A B → Eq (powerset A) (powerset B))) True
% 3.49/3.70 Clause #1 (by clausification #[0]): Eq (∀ (A B : Iota), Eq A B → Eq (powerset A) (powerset B)) False
% 3.49/3.70 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Eq (skS.0 0 a) B → Eq (powerset (skS.0 0 a)) (powerset B))) True
% 3.49/3.70 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (B : Iota), Eq (skS.0 0 a) B → Eq (powerset (skS.0 0 a)) (powerset B)) False
% 3.49/3.70 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Not (Eq (skS.0 0 a) (skS.0 1 a a_1) → Eq (powerset (skS.0 0 a)) (powerset (skS.0 1 a a_1)))) True
% 3.49/3.70 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1) → Eq (powerset (skS.0 0 a)) (powerset (skS.0 1 a a_1))) False
% 3.49/3.70 Clause #6 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.49/3.70 Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (Eq (powerset (skS.0 0 a)) (powerset (skS.0 1 a a_1))) False
% 3.49/3.70 Clause #8 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (skS.0 0 a) (skS.0 1 a a_1)
% 3.49/3.70 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Ne (powerset (skS.0 0 a)) (powerset (skS.0 1 a a_1))
% 3.49/3.70 Clause #10 (by forward demodulation #[9, 8]): ∀ (a : Iota), Ne (powerset (skS.0 0 a)) (powerset (skS.0 0 a))
% 3.49/3.70 Clause #11 (by eliminate resolved literals #[10]): False
% 3.49/3.70 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------