TSTP Solution File: SEU523^2 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEU523^2 : TPTP v6.1.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n095.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:32:22 EDT 2014

% Result   : Unknown 0.39s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEU523^2 : TPTP v6.1.0. Released v3.7.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n095.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 10:30:31 CDT 2014
% % CPUTime  : 0.39 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0xab7f38>, <kernel.DependentProduct object at 0xab79e0>) of role type named in_type
% Using role type
% Declaring in:(fofType->(fofType->Prop))
% FOF formula (<kernel.Constant object at 0xe8f1b8>, <kernel.DependentProduct object at 0xab7488>) of role type named setunion_type
% Using role type
% Declaring setunion:(fofType->fofType)
% FOF formula (<kernel.Constant object at 0xab7830>, <kernel.Sort object at 0x998a70>) of role type named setunionAx_type
% Using role type
% Declaring setunionAx:Prop
% FOF formula (((eq Prop) setunionAx) (forall (A:fofType) (Xx:fofType), ((iff ((in Xx) (setunion A))) ((ex fofType) (fun (B:fofType)=> ((and ((in Xx) B)) ((in B) A))))))) of role definition named setunionAx
% A new definition: (((eq Prop) setunionAx) (forall (A:fofType) (Xx:fofType), ((iff ((in Xx) (setunion A))) ((ex fofType) (fun (B:fofType)=> ((and ((in Xx) B)) ((in B) A)))))))
% Defined: setunionAx:=(forall (A:fofType) (Xx:fofType), ((iff ((in Xx) (setunion A))) ((ex fofType) (fun (B:fofType)=> ((and ((in Xx) B)) ((in B) A))))))
% FOF formula (setunionAx->(forall (A:fofType) (Xx:fofType), (((in Xx) (setunion A))->(forall (Xphi:Prop), ((forall (B:fofType), (((in Xx) B)->(((in B) A)->Xphi)))->Xphi))))) of role conjecture named setunionE
% Conjecture to prove = (setunionAx->(forall (A:fofType) (Xx:fofType), (((in Xx) (setunion A))->(forall (Xphi:Prop), ((forall (B:fofType), (((in Xx) B)->(((in B) A)->Xphi)))->Xphi))))):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['(setunionAx->(forall (A:fofType) (Xx:fofType), (((in Xx) (setunion A))->(forall (Xphi:Prop), ((forall (B:fofType), (((in Xx) B)->(((in B) A)->Xphi)))->Xphi)))))']
% Parameter fofType:Type.
% Parameter in:(fofType->(fofType->Prop)).
% Parameter setunion:(fofType->fofType).
% Definition setunionAx:=(forall (A:fofType) (Xx:fofType), ((iff ((in Xx) (setunion A))) ((ex fofType) (fun (B:fofType)=> ((and ((in Xx) B)) ((in B) A)))))):Prop.
% Trying to prove (setunionAx->(forall (A:fofType) (Xx:fofType), (((in Xx) (setunion A))->(forall (Xphi:Prop), ((forall (B:fofType), (((in Xx) B)->(((in B) A)->Xphi)))->Xphi)))))
% Found x0:((in Xx) (setunion A))
% Found x0 as proof of ((in Xx) (setunion A))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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