TSTP Solution File: SEU435+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SEU435+1 : TPTP v8.1.0. Released v3.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:29:53 EDT 2022

% Result   : Theorem 1.82s 2.03s
% Output   : Refutation 1.82s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : SEU435+1 : TPTP v8.1.0. Released v3.4.0.
% 0.06/0.13  % Command  : sos-script %s
% 0.13/0.33  % Computer : n023.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Sun Jun 19 22:09:03 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.13/0.35  ----- Otter 3.2, August 2001 -----
% 0.13/0.35  The process was started by sandbox2 on n023.cluster.edu,
% 0.13/0.35  Sun Jun 19 22:09:03 2022
% 0.13/0.35  The command was "./sos".  The process ID is 6483.
% 0.13/0.35  
% 0.13/0.35  set(prolog_style_variables).
% 0.13/0.35  set(auto).
% 0.13/0.35     dependent: set(auto1).
% 0.13/0.35     dependent: set(process_input).
% 0.13/0.35     dependent: clear(print_kept).
% 0.13/0.35     dependent: clear(print_new_demod).
% 0.13/0.35     dependent: clear(print_back_demod).
% 0.13/0.35     dependent: clear(print_back_sub).
% 0.13/0.35     dependent: set(control_memory).
% 0.13/0.35     dependent: assign(max_mem, 12000).
% 0.13/0.35     dependent: assign(pick_given_ratio, 4).
% 0.13/0.35     dependent: assign(stats_level, 1).
% 0.13/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.35     dependent: assign(sos_limit, 5000).
% 0.13/0.35     dependent: assign(max_weight, 60).
% 0.13/0.35  clear(print_given).
% 0.13/0.35  
% 0.13/0.35  formula_list(usable).
% 0.13/0.35  
% 0.13/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=6.
% 0.13/0.35  
% 0.13/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.35  clauses in usable.
% 0.13/0.35  
% 0.13/0.35     dependent: set(knuth_bendix).
% 0.13/0.35     dependent: set(para_from).
% 0.13/0.35     dependent: set(para_into).
% 0.13/0.35     dependent: clear(para_from_right).
% 0.13/0.35     dependent: clear(para_into_right).
% 0.13/0.35     dependent: set(para_from_vars).
% 0.13/0.35     dependent: set(eq_units_both_ways).
% 0.13/0.35     dependent: set(dynamic_demod_all).
% 0.13/0.35     dependent: set(dynamic_demod).
% 0.13/0.35     dependent: set(order_eq).
% 0.13/0.35     dependent: set(back_demod).
% 0.13/0.35     dependent: set(lrpo).
% 0.13/0.35     dependent: set(hyper_res).
% 0.13/0.35     dependent: set(unit_deletion).
% 0.13/0.35     dependent: set(factor).
% 0.13/0.35  
% 0.13/0.35  ------------> process usable:
% 0.13/0.35  
% 0.13/0.35  ------------> process sos:
% 0.13/0.35    Following clause subsumed by 58 during input processing: 0 [] {-} v1_xboole_0(k1_xboole_0).
% 0.13/0.35    Following clause subsumed by 59 during input processing: 0 [] {-} v1_relat_1(k1_xboole_0).
% 0.13/0.35    Following clause subsumed by 75 during input processing: 0 [copy,75,flip.1] {-} A=A.
% 0.13/0.35  75 back subsumes 50.
% 0.13/0.35  75 back subsumes 49.
% 0.13/0.35  
% 0.13/0.35  ======= end of input processing =======
% 1.82/2.03  
% 1.82/2.03  Stopped by limit on insertions
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  Failed to model usable list: disabling FINDER
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  -------------- Softie stats --------------
% 1.82/2.03  
% 1.82/2.03  UPDATE_STOP: 300
% 1.82/2.03  SFINDER_TIME_LIMIT: 2
% 1.82/2.03  SHORT_CLAUSE_CUTOFF: 4
% 1.82/2.03  number of clauses in intial UL: 46
% 1.82/2.03  number of clauses initially in problem: 71
% 1.82/2.03  percentage of clauses intially in UL: 64
% 1.82/2.03  percentage of distinct symbols occuring in initial UL: 78
% 1.82/2.03  percent of all initial clauses that are short: 98
% 1.82/2.03  absolute distinct symbol count: 42
% 1.82/2.03     distinct predicate count: 12
% 1.82/2.03     distinct function count: 20
% 1.82/2.03     distinct constant count: 10
% 1.82/2.03  
% 1.82/2.03  ---------- no more Softie stats ----------
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  =========== start of search ===========
% 1.82/2.03  
% 1.82/2.03  -------- PROOF -------- 
% 1.82/2.03  % SZS status Theorem
% 1.82/2.03  % SZS output start Refutation
% 1.82/2.03  
% 1.82/2.03  ----> UNIT CONFLICT at   1.65 sec ----> 116 [binary,115.1,1.1] {-} $F.
% 1.82/2.03  
% 1.82/2.03  Length of proof is 1.  Level of proof is 1.
% 1.82/2.03  
% 1.82/2.03  ---------------- PROOF ----------------
% 1.82/2.03  % SZS status Theorem
% 1.82/2.03  % SZS output start Refutation
% 1.82/2.03  
% 1.82/2.03  1 [] {+} -m1_subset_1(a_6_0_relset_2($c6,$c5,$c4,$c3,$c2,$c1),k1_zfmisc_1(k1_zfmisc_1($c2))).
% 1.82/2.03  31 [] {+} -m1_subset_1(A,k1_zfmisc_1(k1_zfmisc_1(k2_zfmisc_1(B,C))))| -m1_subset_1(D,k1_zfmisc_1(E))|m1_subset_1(a_6_0_relset_2(B,C,A,E,F,D),k1_zfmisc_1(k1_zfmisc_1(F))).
% 1.82/2.03  51 [] {-} m1_subset_1($c4,k1_zfmisc_1(k1_zfmisc_1(k2_zfmisc_1($c6,$c5)))).
% 1.82/2.03  52 [] {-} m1_subset_1($c1,k1_zfmisc_1($c3)).
% 1.82/2.03  115 [hyper,52,31,51] {-} m1_subset_1(a_6_0_relset_2($c6,$c5,$c4,$c3,A,$c1),k1_zfmisc_1(k1_zfmisc_1(A))).
% 1.82/2.03  116 [binary,115.1,1.1] {-} $F.
% 1.82/2.03  
% 1.82/2.03  % SZS output end Refutation
% 1.82/2.03  ------------ end of proof -------------
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  Search stopped by max_proofs option.
% 1.82/2.03  
% 1.82/2.03  
% 1.82/2.03  Search stopped by max_proofs option.
% 1.82/2.03  
% 1.82/2.03  ============ end of search ============
% 1.82/2.03  
% 1.82/2.03  That finishes the proof of the theorem.
% 1.82/2.03  
% 1.82/2.03  Process 6483 finished Sun Jun 19 22:09:05 2022
%------------------------------------------------------------------------------