TSTP Solution File: SEU382+2 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SEU382+2 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 09:26:22 EDT 2022
% Result : Theorem 0.39s 0.57s
% Output : CNFRefutation 0.39s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 3
% Syntax : Number of formulae : 12 ( 10 unt; 0 def)
% Number of atoms : 14 ( 13 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 6 ( 4 ~; 0 |; 2 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 3 ( 2 avg)
% Maximal term depth : 4 ( 2 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 1 con; 0-1 aty)
% Number of variables : 8 ( 0 sgn 6 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(t4_waybel_7,conjecture,
! [X1] : the_carrier(boole_POSet(X1)) = powerset(X1),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',t4_waybel_7) ).
fof(t4_yellow_1,lemma,
! [X1] : boole_POSet(X1) = incl_POSet(powerset(X1)),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',t4_yellow_1) ).
fof(t1_yellow_1,lemma,
! [X1] :
( the_carrier(incl_POSet(X1)) = X1
& the_InternalRel(incl_POSet(X1)) = inclusion_order(X1) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',t1_yellow_1) ).
fof(c_0_3,negated_conjecture,
~ ! [X1] : the_carrier(boole_POSet(X1)) = powerset(X1),
inference(assume_negation,[status(cth)],[t4_waybel_7]) ).
fof(c_0_4,negated_conjecture,
the_carrier(boole_POSet(esk522_0)) != powerset(esk522_0),
inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_3])])]) ).
fof(c_0_5,lemma,
! [X2450] : boole_POSet(X2450) = incl_POSet(powerset(X2450)),
inference(variable_rename,[status(thm)],[t4_yellow_1]) ).
cnf(c_0_6,negated_conjecture,
the_carrier(boole_POSet(esk522_0)) != powerset(esk522_0),
inference(split_conjunct,[status(thm)],[c_0_4]) ).
cnf(c_0_7,lemma,
boole_POSet(X1) = incl_POSet(powerset(X1)),
inference(split_conjunct,[status(thm)],[c_0_5]) ).
fof(c_0_8,lemma,
! [X2161] :
( the_carrier(incl_POSet(X2161)) = X2161
& the_InternalRel(incl_POSet(X2161)) = inclusion_order(X2161) ),
inference(variable_rename,[status(thm)],[t1_yellow_1]) ).
cnf(c_0_9,negated_conjecture,
the_carrier(incl_POSet(powerset(esk522_0))) != powerset(esk522_0),
inference(rw,[status(thm)],[c_0_6,c_0_7]) ).
cnf(c_0_10,lemma,
the_carrier(incl_POSet(X1)) = X1,
inference(split_conjunct,[status(thm)],[c_0_8]) ).
cnf(c_0_11,negated_conjecture,
$false,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_9,c_0_10])]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : SEU382+2 : TPTP v8.1.0. Released v3.3.0.
% 0.06/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.33 % Computer : n016.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jun 20 08:42:25 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.39/0.57 # No SInE strategy applied
% 0.39/0.57 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S2g
% 0.39/0.57 # and selection function SelectCQArNpEqFirst.
% 0.39/0.57 #
% 0.39/0.57 # Presaturation interreduction done
% 0.39/0.57
% 0.39/0.57 # Proof found!
% 0.39/0.57 # SZS status Theorem
% 0.39/0.57 # SZS output start CNFRefutation
% See solution above
% 0.39/0.57 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------