TSTP Solution File: SEU275+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SEU275+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 14:35:45 EDT 2022
% Result : Theorem 0.19s 0.43s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 2
% Number of leaves : 9
% Syntax : Number of clauses : 13 ( 9 unt; 0 nHn; 13 RR)
% Number of literals : 26 ( 0 equ; 15 neg)
% Maximal clause size : 7 ( 2 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 9 ( 8 usr; 1 prp; 0-1 aty)
% Number of functors : 3 ( 3 usr; 2 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
ordinal(skc2),
file('SEU275+1.p',unknown),
[] ).
cnf(5,axiom,
relation(inclusion_relation(u)),
file('SEU275+1.p',unknown),
[] ).
cnf(6,axiom,
reflexive(inclusion_relation(u)),
file('SEU275+1.p',unknown),
[] ).
cnf(7,axiom,
transitive(inclusion_relation(u)),
file('SEU275+1.p',unknown),
[] ).
cnf(8,axiom,
antisymmetric(inclusion_relation(u)),
file('SEU275+1.p',unknown),
[] ).
cnf(9,axiom,
~ well_ordering(inclusion_relation(skc2)),
file('SEU275+1.p',unknown),
[] ).
cnf(12,axiom,
( ~ ordinal(u)
| connected(inclusion_relation(u)) ),
file('SEU275+1.p',unknown),
[] ).
cnf(13,axiom,
( ~ ordinal(u)
| well_founded_relation(inclusion_relation(u)) ),
file('SEU275+1.p',unknown),
[] ).
cnf(20,axiom,
( ~ relation(u)
| ~ well_founded_relation(u)
| ~ connected(u)
| ~ antisymmetric(u)
| ~ transitive(u)
| ~ reflexive(u)
| well_ordering(u) ),
file('SEU275+1.p',unknown),
[] ).
cnf(21,plain,
connected(inclusion_relation(skc2)),
inference(res,[status(thm),theory(equality)],[1,12]),
[iquote('0:Res:1.0,12.0')] ).
cnf(22,plain,
well_founded_relation(inclusion_relation(skc2)),
inference(res,[status(thm),theory(equality)],[1,13]),
[iquote('0:Res:1.0,13.0')] ).
cnf(25,plain,
( ~ reflexive(inclusion_relation(skc2))
| ~ transitive(inclusion_relation(skc2))
| ~ antisymmetric(inclusion_relation(skc2))
| ~ connected(inclusion_relation(skc2))
| ~ well_founded_relation(inclusion_relation(skc2))
| ~ relation(inclusion_relation(skc2)) ),
inference(res,[status(thm),theory(equality)],[20,9]),
[iquote('0:Res:20.6,9.0')] ).
cnf(26,plain,
$false,
inference(mrr,[status(thm)],[25,6,7,8,21,22,5]),
[iquote('0:MRR:25.0,25.1,25.2,25.3,25.4,25.5,6.0,7.0,8.0,21.0,22.0,5.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU275+1 : TPTP v8.1.0. Released v3.3.0.
% 0.11/0.13 % Command : run_spass %d %s
% 0.13/0.33 % Computer : n029.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Sun Jun 19 03:19:59 EDT 2022
% 0.19/0.34 % CPUTime :
% 0.19/0.43
% 0.19/0.43 SPASS V 3.9
% 0.19/0.43 SPASS beiseite: Proof found.
% 0.19/0.43 % SZS status Theorem
% 0.19/0.43 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.43 SPASS derived 5 clauses, backtracked 0 clauses, performed 0 splits and kept 25 clauses.
% 0.19/0.43 SPASS allocated 97678 KBytes.
% 0.19/0.43 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.43 0:00:00.03 for the input.
% 0.19/0.43 0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.43 0:00:00.00 for inferences.
% 0.19/0.43 0:00:00.00 for the backtracking.
% 0.19/0.43 0:00:00.00 for the reduction.
% 0.19/0.43
% 0.19/0.43
% 0.19/0.43 Here is a proof with depth 1, length 13 :
% 0.19/0.43 % SZS output start Refutation
% See solution above
% 0.19/0.43 Formulae used in the proof : t7_wellord2 dt_k1_wellord2 t2_wellord2 t3_wellord2 t5_wellord2 t4_wellord2 t6_wellord2 d4_wellord1
% 0.19/0.43
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