TSTP Solution File: SEU223+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SEU223+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 14:35:12 EDT 2022
% Result : Theorem 0.19s 0.45s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 7
% Syntax : Number of clauses : 13 ( 8 unt; 0 nHn; 13 RR)
% Number of literals : 28 ( 0 equ; 18 neg)
% Maximal clause size : 7 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 10 ( 10 usr; 7 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
relation(skc11),
file('SEU223+1.p',unknown),
[] ).
cnf(2,axiom,
function(skc11),
file('SEU223+1.p',unknown),
[] ).
cnf(30,axiom,
in(skc12,relation_dom(relation_dom_restriction(skc11,skc13))),
file('SEU223+1.p',unknown),
[] ).
cnf(35,axiom,
( ~ relation(u)
| relation(relation_dom_restriction(u,v)) ),
file('SEU223+1.p',unknown),
[] ).
cnf(42,axiom,
~ equal(apply(relation_dom_restriction(skc11,skc13),skc12),apply(skc11,skc12)),
file('SEU223+1.p',unknown),
[] ).
cnf(46,axiom,
( ~ relation(u)
| ~ function(u)
| function(relation_dom_restriction(u,v)) ),
file('SEU223+1.p',unknown),
[] ).
cnf(50,axiom,
( ~ relation(u)
| ~ function(u)
| ~ relation(v)
| ~ function(v)
| ~ in(w,relation_dom(u))
| ~ equal(u,relation_dom_restriction(v,x))
| equal(apply(u,w),apply(v,w)) ),
file('SEU223+1.p',unknown),
[] ).
cnf(58,plain,
( ~ relation(skc11)
| function(relation_dom_restriction(skc11,u)) ),
inference(res,[status(thm),theory(equality)],[2,46]),
[iquote('0:Res:2.0,46.0')] ).
cnf(71,plain,
relation(relation_dom_restriction(skc11,u)),
inference(res,[status(thm),theory(equality)],[1,35]),
[iquote('0:Res:1.0,35.0')] ).
cnf(83,plain,
( ~ function(skc11)
| ~ relation(skc11)
| ~ function(relation_dom_restriction(skc11,skc13))
| ~ relation(relation_dom_restriction(skc11,skc13))
| ~ in(skc12,relation_dom(relation_dom_restriction(skc11,skc13)))
| ~ equal(relation_dom_restriction(skc11,skc13),relation_dom_restriction(skc11,u)) ),
inference(res,[status(thm),theory(equality)],[50,42]),
[iquote('0:Res:50.6,42.0')] ).
cnf(86,plain,
function(relation_dom_restriction(skc11,u)),
inference(mrr,[status(thm)],[58,1]),
[iquote('0:MRR:58.0,1.0')] ).
cnf(94,plain,
~ equal(relation_dom_restriction(skc11,skc13),relation_dom_restriction(skc11,u)),
inference(mrr,[status(thm)],[83,2,1,86,71,30]),
[iquote('0:MRR:83.0,83.1,83.2,83.3,83.4,2.0,1.0,86.0,71.0,30.0')] ).
cnf(184,plain,
$false,
inference(eqr,[status(thm),theory(equality)],[94]),
[iquote('0:EqR:94.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : SEU223+1 : TPTP v8.1.0. Released v3.3.0.
% 0.11/0.13 % Command : run_spass %d %s
% 0.12/0.34 % Computer : n009.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Sun Jun 19 09:41:37 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.19/0.45
% 0.19/0.45 SPASS V 3.9
% 0.19/0.45 SPASS beiseite: Proof found.
% 0.19/0.45 % SZS status Theorem
% 0.19/0.45 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.19/0.45 SPASS derived 109 clauses, backtracked 0 clauses, performed 1 splits and kept 84 clauses.
% 0.19/0.45 SPASS allocated 97798 KBytes.
% 0.19/0.45 SPASS spent 0:00:00.10 on the problem.
% 0.19/0.45 0:00:00.03 for the input.
% 0.19/0.45 0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.45 0:00:00.00 for inferences.
% 0.19/0.45 0:00:00.00 for the backtracking.
% 0.19/0.45 0:00:00.00 for the reduction.
% 0.19/0.45
% 0.19/0.45
% 0.19/0.45 Here is a proof with depth 2, length 13 :
% 0.19/0.45 % SZS output start Refutation
% See solution above
% 0.19/0.45 Formulae used in the proof : t70_funct_1 dt_k7_relat_1 fc4_funct_1 t68_funct_1
% 0.19/0.45
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