TSTP Solution File: SEU219+2 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SEU219+2 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 14:35:09 EDT 2022
% Result : Theorem 3.23s 3.40s
% Output : Refutation 3.23s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 7
% Syntax : Number of clauses : 14 ( 7 unt; 0 nHn; 14 RR)
% Number of literals : 24 ( 0 equ; 13 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 3 ( 2 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 2 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
relation(skc9),
file('SEU219+2.p',unknown),
[] ).
cnf(2,axiom,
function(skc9),
file('SEU219+2.p',unknown),
[] ).
cnf(3,axiom,
one_to_one(skc9),
file('SEU219+2.p',unknown),
[] ).
cnf(139,axiom,
( ~ relation(u)
| equal(relation_dom(relation_inverse(u)),relation_rng(u)) ),
file('SEU219+2.p',unknown),
[] ).
cnf(140,axiom,
( ~ relation(u)
| equal(relation_rng(relation_inverse(u)),relation_dom(u)) ),
file('SEU219+2.p',unknown),
[] ).
cnf(256,axiom,
( ~ equal(relation_dom(function_inverse(skc9)),relation_rng(skc9))
| ~ equal(relation_rng(function_inverse(skc9)),relation_dom(skc9)) ),
file('SEU219+2.p',unknown),
[] ).
cnf(265,axiom,
( ~ one_to_one(u)
| ~ function(u)
| ~ relation(u)
| equal(function_inverse(u),relation_inverse(u)) ),
file('SEU219+2.p',unknown),
[] ).
cnf(458,plain,
( ~ relation(skc9)
| ~ function(skc9)
| equal(function_inverse(skc9),relation_inverse(skc9)) ),
inference(res,[status(thm),theory(equality)],[3,265]),
[iquote('0:Res:3.0,265.2')] ).
cnf(626,plain,
equal(relation_dom(relation_inverse(skc9)),relation_rng(skc9)),
inference(res,[status(thm),theory(equality)],[1,139]),
[iquote('0:Res:1.0,139.0')] ).
cnf(627,plain,
equal(relation_rng(relation_inverse(skc9)),relation_dom(skc9)),
inference(res,[status(thm),theory(equality)],[1,140]),
[iquote('0:Res:1.0,140.0')] ).
cnf(695,plain,
equal(function_inverse(skc9),relation_inverse(skc9)),
inference(mrr,[status(thm)],[458,1,2]),
[iquote('0:MRR:458.0,458.1,1.0,2.0')] ).
cnf(696,plain,
( ~ equal(relation_dom(relation_inverse(skc9)),relation_rng(skc9))
| ~ equal(relation_rng(function_inverse(skc9)),relation_dom(skc9)) ),
inference(rew,[status(thm),theory(equality)],[695,256]),
[iquote('0:Rew:695.0,256.0')] ).
cnf(703,plain,
( ~ equal(relation_rng(skc9),relation_rng(skc9))
| ~ equal(relation_dom(skc9),relation_dom(skc9)) ),
inference(rew,[status(thm),theory(equality)],[627,696,695,626]),
[iquote('0:Rew:627.0,696.1,695.0,696.1,626.0,696.0')] ).
cnf(704,plain,
$false,
inference(obv,[status(thm),theory(equality)],[703]),
[iquote('0:Obv:703.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU219+2 : TPTP v8.1.0. Released v3.3.0.
% 0.12/0.13 % Command : run_spass %d %s
% 0.12/0.34 % Computer : n017.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Sun Jun 19 19:32:43 EDT 2022
% 0.12/0.34 % CPUTime :
% 3.23/3.40
% 3.23/3.40 SPASS V 3.9
% 3.23/3.40 SPASS beiseite: Proof found.
% 3.23/3.40 % SZS status Theorem
% 3.23/3.40 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 3.23/3.40 SPASS derived 242 clauses, backtracked 0 clauses, performed 0 splits and kept 456 clauses.
% 3.23/3.40 SPASS allocated 109820 KBytes.
% 3.23/3.40 SPASS spent 0:00:03.04 on the problem.
% 3.23/3.40 0:00:00.04 for the input.
% 3.23/3.40 0:00:02.88 for the FLOTTER CNF translation.
% 3.23/3.40 0:00:00.00 for inferences.
% 3.23/3.40 0:00:00.00 for the backtracking.
% 3.23/3.40 0:00:00.05 for the reduction.
% 3.23/3.40
% 3.23/3.40
% 3.23/3.40 Here is a proof with depth 1, length 14 :
% 3.23/3.40 % SZS output start Refutation
% See solution above
% 3.23/3.40 Formulae used in the proof : t55_funct_1 t37_relat_1 d9_funct_1
% 3.23/3.40
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