TSTP Solution File: SEU162+3 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SEU162+3 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:15:00 EDT 2022

% Result   : Theorem 1.68s 1.89s
% Output   : Refutation 1.68s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   15 (   6 unt;   3 nHn;  13 RR)
%            Number of literals    :   24 (   7 equ;   7 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   11 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    ( ~ disjoint(singleton(A),B)
    | ~ in(A,B) ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ disjoint(A,B)
    | disjoint(B,A) ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(5,axiom,
    ( set_difference(dollar_c4,singleton(dollar_c3)) = dollar_c4
    | ~ in(dollar_c3,dollar_c4) ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(6,axiom,
    ( set_difference(dollar_c4,singleton(dollar_c3)) != dollar_c4
    | in(dollar_c3,dollar_c4) ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ disjoint(A,B)
    | set_difference(A,B) = A ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(8,axiom,
    ( disjoint(A,B)
    | set_difference(A,B) != A ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(10,axiom,
    A = A,
    file('SEU162+3.p',unknown),
    [] ).

cnf(11,axiom,
    ( in(A,B)
    | disjoint(singleton(A),B) ),
    file('SEU162+3.p',unknown),
    [] ).

cnf(14,plain,
    ( disjoint(singleton(dollar_c3),dollar_c4)
    | set_difference(dollar_c4,singleton(dollar_c3)) = dollar_c4 ),
    inference(hyper,[status(thm)],[11,5]),
    [iquote('hyper,11,5')] ).

cnf(23,plain,
    ( disjoint(dollar_c4,singleton(dollar_c3))
    | disjoint(singleton(dollar_c3),dollar_c4) ),
    inference(unit_del,[status(thm)],[inference(para_from,[status(thm),theory(equality)],[14,8]),10]),
    [iquote('para_from,14.2.1,8.2.1,unit_del,10')] ).

cnf(26,plain,
    disjoint(singleton(dollar_c3),dollar_c4),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[23,4])]),
    [iquote('hyper,23,4,factor_simp')] ).

cnf(28,plain,
    disjoint(dollar_c4,singleton(dollar_c3)),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[23,4])]),
    [iquote('hyper,23,4,factor_simp')] ).

cnf(33,plain,
    set_difference(dollar_c4,singleton(dollar_c3)) = dollar_c4,
    inference(hyper,[status(thm)],[28,7]),
    [iquote('hyper,28,7')] ).

cnf(34,plain,
    in(dollar_c3,dollar_c4),
    inference(unit_del,[status(thm)],[inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[6]),33]),10]),
    [iquote('back_demod,6,demod,33,unit_del,10')] ).

cnf(35,plain,
    $false,
    inference(hyper,[status(thm)],[34,2,26]),
    [iquote('hyper,34,2,26')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : SEU162+3 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n027.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 07:59:51 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.68/1.89  ----- Otter 3.3f, August 2004 -----
% 1.68/1.89  The process was started by sandbox2 on n027.cluster.edu,
% 1.68/1.89  Wed Jul 27 07:59:51 2022
% 1.68/1.89  The command was "./otter".  The process ID is 28523.
% 1.68/1.89  
% 1.68/1.89  set(prolog_style_variables).
% 1.68/1.89  set(auto).
% 1.68/1.89     dependent: set(auto1).
% 1.68/1.89     dependent: set(process_input).
% 1.68/1.89     dependent: clear(print_kept).
% 1.68/1.89     dependent: clear(print_new_demod).
% 1.68/1.89     dependent: clear(print_back_demod).
% 1.68/1.89     dependent: clear(print_back_sub).
% 1.68/1.89     dependent: set(control_memory).
% 1.68/1.89     dependent: assign(max_mem, 12000).
% 1.68/1.89     dependent: assign(pick_given_ratio, 4).
% 1.68/1.89     dependent: assign(stats_level, 1).
% 1.68/1.89     dependent: assign(max_seconds, 10800).
% 1.68/1.89  clear(print_given).
% 1.68/1.89  
% 1.68/1.89  formula_list(usable).
% 1.68/1.89  all A (A=A).
% 1.68/1.89  all A B (in(A,B)-> -in(B,A)).
% 1.68/1.89  all A B (-(disjoint(singleton(A),B)&in(A,B))).
% 1.68/1.89  all A B (-in(A,B)->disjoint(singleton(A),B)).
% 1.68/1.89  exists A empty(A).
% 1.68/1.89  exists A (-empty(A)).
% 1.68/1.89  all A B (disjoint(A,B)->disjoint(B,A)).
% 1.68/1.89  -(all A B (set_difference(A,singleton(B))=A<-> -in(B,A))).
% 1.68/1.89  all A B (disjoint(A,B)<->set_difference(A,B)=A).
% 1.68/1.89  end_of_list.
% 1.68/1.89  
% 1.68/1.89  -------> usable clausifies to:
% 1.68/1.89  
% 1.68/1.89  list(usable).
% 1.68/1.89  0 [] A=A.
% 1.68/1.89  0 [] -in(A,B)| -in(B,A).
% 1.68/1.89  0 [] -disjoint(singleton(A),B)| -in(A,B).
% 1.68/1.89  0 [] in(A,B)|disjoint(singleton(A),B).
% 1.68/1.89  0 [] empty($c1).
% 1.68/1.89  0 [] -empty($c2).
% 1.68/1.89  0 [] -disjoint(A,B)|disjoint(B,A).
% 1.68/1.89  0 [] set_difference($c4,singleton($c3))=$c4| -in($c3,$c4).
% 1.68/1.89  0 [] set_difference($c4,singleton($c3))!=$c4|in($c3,$c4).
% 1.68/1.89  0 [] -disjoint(A,B)|set_difference(A,B)=A.
% 1.68/1.89  0 [] disjoint(A,B)|set_difference(A,B)!=A.
% 1.68/1.89  end_of_list.
% 1.68/1.89  
% 1.68/1.89  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=2.
% 1.68/1.89  
% 1.68/1.89  This ia a non-Horn set with equality.  The strategy will be
% 1.68/1.89  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.68/1.89  deletion, with positive clauses in sos and nonpositive
% 1.68/1.89  clauses in usable.
% 1.68/1.89  
% 1.68/1.89     dependent: set(knuth_bendix).
% 1.68/1.89     dependent: set(anl_eq).
% 1.68/1.89     dependent: set(para_from).
% 1.68/1.89     dependent: set(para_into).
% 1.68/1.89     dependent: clear(para_from_right).
% 1.68/1.89     dependent: clear(para_into_right).
% 1.68/1.89     dependent: set(para_from_vars).
% 1.68/1.89     dependent: set(eq_units_both_ways).
% 1.68/1.89     dependent: set(dynamic_demod_all).
% 1.68/1.89     dependent: set(dynamic_demod).
% 1.68/1.89     dependent: set(order_eq).
% 1.68/1.89     dependent: set(back_demod).
% 1.68/1.89     dependent: set(lrpo).
% 1.68/1.89     dependent: set(hyper_res).
% 1.68/1.89     dependent: set(unit_deletion).
% 1.68/1.89     dependent: set(factor).
% 1.68/1.89  
% 1.68/1.89  ------------> process usable:
% 1.68/1.89  ** KEPT (pick-wt=6): 1 [] -in(A,B)| -in(B,A).
% 1.68/1.89  ** KEPT (pick-wt=7): 2 [] -disjoint(singleton(A),B)| -in(A,B).
% 1.68/1.89  ** KEPT (pick-wt=2): 3 [] -empty($c2).
% 1.68/1.89  ** KEPT (pick-wt=6): 4 [] -disjoint(A,B)|disjoint(B,A).
% 1.68/1.89  ** KEPT (pick-wt=9): 5 [] set_difference($c4,singleton($c3))=$c4| -in($c3,$c4).
% 1.68/1.89  ** KEPT (pick-wt=9): 6 [] set_difference($c4,singleton($c3))!=$c4|in($c3,$c4).
% 1.68/1.89  ** KEPT (pick-wt=8): 7 [] -disjoint(A,B)|set_difference(A,B)=A.
% 1.68/1.89  ** KEPT (pick-wt=8): 8 [] disjoint(A,B)|set_difference(A,B)!=A.
% 1.68/1.89  
% 1.68/1.89  ------------> process sos:
% 1.68/1.89  ** KEPT (pick-wt=3): 10 [] A=A.
% 1.68/1.89  ** KEPT (pick-wt=7): 11 [] in(A,B)|disjoint(singleton(A),B).
% 1.68/1.89  ** KEPT (pick-wt=2): 12 [] empty($c1).
% 1.68/1.89    Following clause subsumed by 10 during input processing: 0 [copy,10,flip.1] A=A.
% 1.68/1.89  
% 1.68/1.89  ======= end of input processing =======
% 1.68/1.89  
% 1.68/1.89  =========== start of search ===========
% 1.68/1.89  
% 1.68/1.89  -------- PROOF -------- 
% 1.68/1.89  
% 1.68/1.89  -----> EMPTY CLAUSE at   0.00 sec ----> 35 [hyper,34,2,26] $F.
% 1.68/1.89  
% 1.68/1.89  Length of proof is 6.  Level of proof is 5.
% 1.68/1.89  
% 1.68/1.89  ---------------- PROOF ----------------
% 1.68/1.89  % SZS status Theorem
% 1.68/1.89  % SZS output start Refutation
% See solution above
% 1.68/1.89  ------------ end of proof -------------
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  ============ end of search ============
% 1.68/1.89  
% 1.68/1.89  -------------- statistics -------------
% 1.68/1.89  clauses given                 14
% 1.68/1.89  clauses generated             68
% 1.68/1.89  clauses kept                  30
% 1.68/1.89  clauses forward subsumed      53
% 1.68/1.89  clauses back subsumed          4
% 1.68/1.89  Kbytes malloced              976
% 1.68/1.89  
% 1.68/1.89  ----------- times (seconds) -----------
% 1.68/1.89  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.89  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.68/1.89  
% 1.68/1.89  That finishes the proof of the theorem.
% 1.68/1.89  
% 1.68/1.89  Process 28523 finished Wed Jul 27 07:59:53 2022
% 1.68/1.89  Otter interrupted
% 1.68/1.89  PROOF FOUND
%------------------------------------------------------------------------------