TSTP Solution File: SEU161+3 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEU161+3 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:40:32 EDT 2023

% Result   : Theorem 3.63s 3.80s
% Output   : Proof 3.63s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU161+3 : TPTP v8.1.2. Released v3.2.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n008.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Wed Aug 23 17:46:02 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.63/3.80  SZS status Theorem for theBenchmark.p
% 3.63/3.80  SZS output start Proof for theBenchmark.p
% 3.63/3.80  Clause #7 (by assumption #[]): Eq (Not (∀ (A B : Iota), in A B → Eq (set_union2 (singleton A) B) B)) True
% 3.63/3.80  Clause #8 (by assumption #[]): Eq (∀ (A B : Iota), in A B → Eq (set_union2 (singleton A) B) B) True
% 3.63/3.80  Clause #34 (by clausification #[8]): ∀ (a : Iota), Eq (∀ (B : Iota), in a B → Eq (set_union2 (singleton a) B) B) True
% 3.63/3.80  Clause #35 (by clausification #[34]): ∀ (a a_1 : Iota), Eq (in a a_1 → Eq (set_union2 (singleton a) a_1) a_1) True
% 3.63/3.80  Clause #36 (by clausification #[35]): ∀ (a a_1 : Iota), Or (Eq (in a a_1) False) (Eq (Eq (set_union2 (singleton a) a_1) a_1) True)
% 3.63/3.80  Clause #37 (by clausification #[36]): ∀ (a a_1 : Iota), Or (Eq (in a a_1) False) (Eq (set_union2 (singleton a) a_1) a_1)
% 3.63/3.80  Clause #38 (by clausification #[7]): Eq (∀ (A B : Iota), in A B → Eq (set_union2 (singleton A) B) B) False
% 3.63/3.80  Clause #39 (by clausification #[38]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), in (skS.0 2 a) B → Eq (set_union2 (singleton (skS.0 2 a)) B) B)) True
% 3.63/3.80  Clause #40 (by clausification #[39]): ∀ (a : Iota), Eq (∀ (B : Iota), in (skS.0 2 a) B → Eq (set_union2 (singleton (skS.0 2 a)) B) B) False
% 3.63/3.80  Clause #41 (by clausification #[40]): ∀ (a a_1 : Iota),
% 3.63/3.80    Eq (Not (in (skS.0 2 a) (skS.0 3 a a_1) → Eq (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1)))
% 3.63/3.80      True
% 3.63/3.80  Clause #42 (by clausification #[41]): ∀ (a a_1 : Iota),
% 3.63/3.80    Eq (in (skS.0 2 a) (skS.0 3 a a_1) → Eq (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1)) False
% 3.63/3.80  Clause #43 (by clausification #[42]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True
% 3.63/3.80  Clause #44 (by clausification #[42]): ∀ (a a_1 : Iota), Eq (Eq (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1)) False
% 3.63/3.80  Clause #46 (by superposition #[43, 37]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1))
% 3.63/3.80  Clause #48 (by clausification #[44]): ∀ (a a_1 : Iota), Ne (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1)
% 3.63/3.80  Clause #49 (by clausification #[46]): ∀ (a a_1 : Iota), Eq (set_union2 (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (skS.0 3 a a_1)
% 3.63/3.80  Clause #50 (by forward contextual literal cutting #[49, 48]): False
% 3.63/3.80  SZS output end Proof for theBenchmark.p
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