TSTP Solution File: SEU160+3 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SEU160+3 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:34:31 EDT 2022

% Result   : Theorem 0.20s 0.44s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   11 (   4 unt;   3 nHn;  11 RR)
%            Number of literals    :   20 (   0 equ;   9 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(5,axiom,
    ( ~ equal(u,empty_set)
    | subset(u,singleton(v)) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ equal(skc4,empty_set)
    | ~ subset(skc4,singleton(skc5)) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ equal(u,singleton(v))
    | subset(u,singleton(v)) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ equal(singleton(skc5),skc4)
    | ~ subset(skc4,singleton(skc5)) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(9,axiom,
    ( subset(skc4,singleton(skc5))
    | equal(skc4,empty_set)
    | equal(singleton(skc5),skc4) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(10,axiom,
    ( ~ subset(u,singleton(v))
    | equal(u,empty_set)
    | equal(u,singleton(v)) ),
    file('SEU160+3.p',unknown),
    [] ).

cnf(11,plain,
    ~ equal(skc4,empty_set),
    inference(mrr,[status(thm)],[6,5]),
    [iquote('0:MRR:6.1,5.1')] ).

cnf(12,plain,
    ~ equal(singleton(skc5),skc4),
    inference(mrr,[status(thm)],[8,7]),
    [iquote('0:MRR:8.1,7.1')] ).

cnf(13,plain,
    subset(skc4,singleton(skc5)),
    inference(mrr,[status(thm)],[9,11,12]),
    [iquote('0:MRR:9.1,9.2,11.0,12.0')] ).

cnf(15,plain,
    ( equal(singleton(skc5),skc4)
    | equal(skc4,empty_set) ),
    inference(res,[status(thm),theory(equality)],[13,10]),
    [iquote('0:Res:13.0,10.0')] ).

cnf(17,plain,
    $false,
    inference(mrr,[status(thm)],[15,12,11]),
    [iquote('0:MRR:15.0,15.1,12.0,11.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : SEU160+3 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n026.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sun Jun 19 08:06:25 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.44  
% 0.20/0.44  SPASS V 3.9 
% 0.20/0.44  SPASS beiseite: Proof found.
% 0.20/0.44  % SZS status Theorem
% 0.20/0.44  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.44  SPASS derived 3 clauses, backtracked 0 clauses, performed 0 splits and kept 11 clauses.
% 0.20/0.44  SPASS allocated 85067 KBytes.
% 0.20/0.44  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.44  		0:00:00.04 for the input.
% 0.20/0.44  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.44  		0:00:00.00 for inferences.
% 0.20/0.44  		0:00:00.00 for the backtracking.
% 0.20/0.44  		0:00:00.00 for the reduction.
% 0.20/0.44  
% 0.20/0.44  
% 0.20/0.44  Here is a proof with depth 1, length 11 :
% 0.20/0.44  % SZS output start Refutation
% See solution above
% 0.20/0.44  Formulae used in the proof : l4_zfmisc_1 t39_zfmisc_1
% 0.20/0.44  
%------------------------------------------------------------------------------