TSTP Solution File: SEU158+3 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU158+3 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:40:30 EDT 2023

% Result   : Theorem 3.59s 3.77s
% Output   : Proof 3.59s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU158+3 : TPTP v8.1.2. Released v3.2.0.
% 0.13/0.13  % Command    : duper %s
% 0.13/0.33  % Computer : n025.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % WCLimit    : 300
% 0.13/0.33  % DateTime   : Wed Aug 23 14:48:05 EDT 2023
% 0.13/0.33  % CPUTime    : 
% 3.59/3.77  SZS status Theorem for theBenchmark.p
% 3.59/3.77  SZS output start Proof for theBenchmark.p
% 3.59/3.77  Clause #4 (by assumption #[]): Eq (Not (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B))) True
% 3.59/3.77  Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B)) True
% 3.59/3.77  Clause #16 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset (singleton a) B) (in a B)) True
% 3.59/3.77  Clause #17 (by clausification #[16]): ∀ (a a_1 : Iota), Eq (Iff (subset (singleton a) a_1) (in a a_1)) True
% 3.59/3.77  Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) a_1) True) (Eq (in a a_1) False)
% 3.59/3.77  Clause #19 (by clausification #[17]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) a_1) False) (Eq (in a a_1) True)
% 3.59/3.77  Clause #20 (by clausification #[4]): Eq (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B)) False
% 3.59/3.77  Clause #21 (by clausification #[20]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Iff (subset (singleton (skS.0 2 a)) B) (in (skS.0 2 a) B))) True
% 3.59/3.77  Clause #22 (by clausification #[21]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset (singleton (skS.0 2 a)) B) (in (skS.0 2 a) B)) False
% 3.59/3.77  Clause #23 (by clausification #[22]): ∀ (a a_1 : Iota), Eq (Not (Iff (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (in (skS.0 2 a) (skS.0 3 a a_1)))) True
% 3.59/3.77  Clause #24 (by clausification #[23]): ∀ (a a_1 : Iota), Eq (Iff (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) (in (skS.0 2 a) (skS.0 3 a a_1))) False
% 3.59/3.77  Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota),
% 3.59/3.77    Or (Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False) (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) False)
% 3.59/3.77  Clause #26 (by clausification #[24]): ∀ (a a_1 : Iota),
% 3.59/3.77    Or (Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True) (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True)
% 3.59/3.77  Clause #34 (by superposition #[26, 19]): ∀ (a a_1 : Iota),
% 3.59/3.77    Or (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True) (Or (Eq True False) (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True))
% 3.59/3.77  Clause #36 (by clausification #[34]): ∀ (a a_1 : Iota), Or (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True) (Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True)
% 3.59/3.77  Clause #37 (by eliminate duplicate literals #[36]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) True
% 3.59/3.77  Clause #38 (by backward demodulation #[37, 25]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False) (Eq True False)
% 3.59/3.77  Clause #41 (by superposition #[37, 18]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True) (Eq True False)
% 3.59/3.77  Clause #43 (by clausification #[38]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False
% 3.59/3.77  Clause #44 (by clausification #[41]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True
% 3.59/3.77  Clause #45 (by superposition #[44, 43]): Eq True False
% 3.59/3.77  Clause #47 (by clausification #[45]): False
% 3.59/3.77  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------