TSTP Solution File: SEU152+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU152+1 : TPTP v8.1.2. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:40:28 EDT 2023
% Result : Theorem 3.41s 3.66s
% Output : Proof 3.41s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SEU152+1 : TPTP v8.1.2. Released v3.3.0.
% 0.13/0.14 % Command : duper %s
% 0.14/0.36 % Computer : n031.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 300
% 0.14/0.36 % DateTime : Wed Aug 23 20:41:50 EDT 2023
% 0.14/0.36 % CPUTime :
% 3.41/3.66 SZS status Theorem for theBenchmark.p
% 3.41/3.66 SZS output start Proof for theBenchmark.p
% 3.41/3.66 Clause #4 (by assumption #[]): Eq (Not (∀ (A B : Iota), in A B → Eq (set_union2 (singleton A) B) B)) True
% 3.41/3.66 Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B)) True
% 3.41/3.66 Clause #7 (by assumption #[]): Eq (∀ (A B : Iota), subset A B → Eq (set_union2 A B) B) True
% 3.41/3.66 Clause #17 (by clausification #[7]): ∀ (a : Iota), Eq (∀ (B : Iota), subset a B → Eq (set_union2 a B) B) True
% 3.41/3.66 Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota), Eq (subset a a_1 → Eq (set_union2 a a_1) a_1) True
% 3.41/3.66 Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (Eq (set_union2 a a_1) a_1) True)
% 3.41/3.66 Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (set_union2 a a_1) a_1)
% 3.41/3.66 Clause #25 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset (singleton a) B) (in a B)) True
% 3.41/3.66 Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Eq (Iff (subset (singleton a) a_1) (in a a_1)) True
% 3.41/3.66 Clause #27 (by clausification #[26]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) a_1) True) (Eq (in a a_1) False)
% 3.41/3.66 Clause #34 (by clausification #[4]): Eq (∀ (A B : Iota), in A B → Eq (set_union2 (singleton A) B) B) False
% 3.41/3.66 Clause #35 (by clausification #[34]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), in (skS.0 0 a) B → Eq (set_union2 (singleton (skS.0 0 a)) B) B)) True
% 3.41/3.66 Clause #36 (by clausification #[35]): ∀ (a : Iota), Eq (∀ (B : Iota), in (skS.0 0 a) B → Eq (set_union2 (singleton (skS.0 0 a)) B) B) False
% 3.41/3.66 Clause #37 (by clausification #[36]): ∀ (a a_1 : Iota),
% 3.41/3.66 Eq (Not (in (skS.0 0 a) (skS.0 1 a a_1) → Eq (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1)))
% 3.41/3.66 True
% 3.41/3.66 Clause #38 (by clausification #[37]): ∀ (a a_1 : Iota),
% 3.41/3.66 Eq (in (skS.0 0 a) (skS.0 1 a a_1) → Eq (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1)) False
% 3.41/3.66 Clause #39 (by clausification #[38]): ∀ (a a_1 : Iota), Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.41/3.66 Clause #40 (by clausification #[38]): ∀ (a a_1 : Iota), Eq (Eq (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1)) False
% 3.41/3.66 Clause #42 (by superposition #[39, 27]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) True) (Eq True False)
% 3.41/3.66 Clause #45 (by clausification #[42]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) True
% 3.41/3.66 Clause #47 (by superposition #[45, 20]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1))
% 3.41/3.66 Clause #48 (by clausification #[47]): ∀ (a a_1 : Iota), Eq (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1)
% 3.41/3.66 Clause #49 (by clausification #[40]): ∀ (a a_1 : Iota), Ne (set_union2 (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (skS.0 1 a a_1)
% 3.41/3.66 Clause #50 (by forward demodulation #[49, 48]): ∀ (a a_1 : Iota), Ne (skS.0 1 a a_1) (skS.0 1 a a_1)
% 3.41/3.66 Clause #51 (by eliminate resolved literals #[50]): False
% 3.41/3.66 SZS output end Proof for theBenchmark.p
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