TSTP Solution File: SEU150+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SEU150+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:27:10 EDT 2022

% Result   : Theorem 0.20s 0.38s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SEU150+1 : TPTP v8.1.0. Released v3.3.0.
% 0.04/0.13  % Command  : sos-script %s
% 0.13/0.33  % Computer : n028.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Sun Jun 19 11:54:00 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.13/0.35  ----- Otter 3.2, August 2001 -----
% 0.13/0.35  The process was started by sandbox2 on n028.cluster.edu,
% 0.13/0.35  Sun Jun 19 11:54:00 2022
% 0.13/0.35  The command was "./sos".  The process ID is 28778.
% 0.13/0.35  
% 0.13/0.35  set(prolog_style_variables).
% 0.13/0.35  set(auto).
% 0.13/0.35     dependent: set(auto1).
% 0.13/0.35     dependent: set(process_input).
% 0.13/0.35     dependent: clear(print_kept).
% 0.13/0.35     dependent: clear(print_new_demod).
% 0.13/0.35     dependent: clear(print_back_demod).
% 0.13/0.35     dependent: clear(print_back_sub).
% 0.13/0.35     dependent: set(control_memory).
% 0.13/0.35     dependent: assign(max_mem, 12000).
% 0.13/0.35     dependent: assign(pick_given_ratio, 4).
% 0.13/0.35     dependent: assign(stats_level, 1).
% 0.13/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.35     dependent: assign(sos_limit, 5000).
% 0.13/0.35     dependent: assign(max_weight, 60).
% 0.13/0.35  clear(print_given).
% 0.13/0.35  
% 0.13/0.35  formula_list(usable).
% 0.13/0.35  
% 0.13/0.35  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=2.
% 0.13/0.35  
% 0.13/0.35  This is a Horn set with equality.  The strategy will be
% 0.13/0.35  Knuth-Bendix and hyper_res, with positive clauses in
% 0.13/0.35  sos and nonpositive clauses in usable.
% 0.13/0.35  
% 0.13/0.35     dependent: set(knuth_bendix).
% 0.13/0.35     dependent: set(para_from).
% 0.13/0.35     dependent: set(para_into).
% 0.13/0.35     dependent: clear(para_from_right).
% 0.13/0.35     dependent: clear(para_into_right).
% 0.13/0.35     dependent: set(para_from_vars).
% 0.13/0.35     dependent: set(eq_units_both_ways).
% 0.13/0.35     dependent: set(dynamic_demod_all).
% 0.13/0.35     dependent: set(dynamic_demod).
% 0.13/0.35     dependent: set(order_eq).
% 0.13/0.35     dependent: set(back_demod).
% 0.13/0.35     dependent: set(lrpo).
% 0.13/0.35     dependent: set(hyper_res).
% 0.13/0.35     dependent: clear(order_hyper).
% 0.13/0.35  
% 0.13/0.35  ------------> process usable:
% 0.13/0.35  
% 0.13/0.35  ------------> process sos:
% 0.13/0.35    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] {-} unordered_pair(A,B)=unordered_pair(B,A).
% 0.13/0.35    Following clause subsumed by 6 during input processing: 0 [copy,6,flip.1] {-} A=A.
% 0.13/0.35  
% 0.13/0.35  ======= end of input processing =======
% 0.20/0.38  
% 0.20/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.38  
% 0.20/0.38  Stopped by limit on number of solutions
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  -------------- Softie stats --------------
% 0.20/0.38  
% 0.20/0.38  UPDATE_STOP: 300
% 0.20/0.38  SFINDER_TIME_LIMIT: 2
% 0.20/0.38  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.38  number of clauses in intial UL: 2
% 0.20/0.38  number of clauses initially in problem: 6
% 0.20/0.38  percentage of clauses intially in UL: 33
% 0.20/0.38  percentage of distinct symbols occuring in initial UL: 83
% 0.20/0.38  percent of all initial clauses that are short: 100
% 0.20/0.38  absolute distinct symbol count: 6
% 0.20/0.38     distinct predicate count: 1
% 0.20/0.38     distinct function count: 2
% 0.20/0.38     distinct constant count: 3
% 0.20/0.38  
% 0.20/0.38  ---------- no more Softie stats ----------
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  =========== start of search ===========
% 0.20/0.38  
% 0.20/0.38  -------- PROOF -------- 
% 0.20/0.38  % SZS status Theorem
% 0.20/0.38  % SZS output start Refutation
% 0.20/0.38  
% 0.20/0.38  ----> UNIT CONFLICT at   0.00 sec ----> 17 [binary,15.1,2.1] {+} $F.
% 0.20/0.38  
% 0.20/0.38  Length of proof is 3.  Level of proof is 3.
% 0.20/0.38  
% 0.20/0.38  ---------------- PROOF ----------------
% 0.20/0.38  % SZS status Theorem
% 0.20/0.38  % SZS output start Refutation
% 0.20/0.38  
% 0.20/0.38  1 [] {+} singleton(A)!=unordered_pair(B,C)|A=B.
% 0.20/0.38  2 [] {+} $c2!=$c1.
% 0.20/0.38  3 [] {+} unordered_pair(A,B)=unordered_pair(B,A).
% 0.20/0.38  4 [] {-} singleton($c3)=unordered_pair($c2,$c1).
% 0.20/0.38  9,8 [hyper,4,1] {+} $c3=$c2.
% 0.20/0.38  12 [para_from,4.1.1,1.1.1,demod,9] {-} unordered_pair($c2,$c1)!=unordered_pair(A,B)|$c2=A.
% 0.20/0.38  15 [hyper,12,3] {-} $c2=$c1.
% 0.20/0.38  17 [binary,15.1,2.1] {+} $F.
% 0.20/0.38  
% 0.20/0.38  % SZS output end Refutation
% 0.20/0.38  ------------ end of proof -------------
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  Search stopped by max_proofs option.
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  Search stopped by max_proofs option.
% 0.20/0.38  
% 0.20/0.38  ============ end of search ============
% 0.20/0.38  
% 0.20/0.38  ----------- soft-scott stats ----------
% 0.20/0.38  
% 0.20/0.38  true clauses given           1      (25.0%)
% 0.20/0.38  false clauses given          3
% 0.20/0.38  
% 0.20/0.38        FALSE     TRUE
% 0.20/0.38     3  0         2
% 0.20/0.38    13  1         2
% 0.20/0.38  tot:  1         4      (80.0% true)
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.38  
% 0.20/0.38  That finishes the proof of the theorem.
% 0.20/0.38  
% 0.20/0.38  Process 28778 finished Sun Jun 19 11:54:00 2022
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