TSTP Solution File: SEU150+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SEU150+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Jul 19 07:10:56 EDT 2022

% Result   : Theorem 0.67s 1.05s
% Output   : Refutation 0.67s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.11  % Problem  : SEU150+1 : TPTP v8.1.0. Released v3.3.0.
% 0.09/0.11  % Command  : bliksem %s
% 0.12/0.32  % Computer : n021.cluster.edu
% 0.12/0.32  % Model    : x86_64 x86_64
% 0.12/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % Memory   : 8042.1875MB
% 0.12/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit : 300
% 0.12/0.32  % DateTime : Sun Jun 19 11:39:17 EDT 2022
% 0.12/0.32  % CPUTime  : 
% 0.67/1.05  *** allocated 10000 integers for termspace/termends
% 0.67/1.05  *** allocated 10000 integers for clauses
% 0.67/1.05  *** allocated 10000 integers for justifications
% 0.67/1.05  Bliksem 1.12
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Automatic Strategy Selection
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Clauses:
% 0.67/1.05  
% 0.67/1.05  { unordered_pair( X, Y ) = unordered_pair( Y, X ) }.
% 0.67/1.05  { && }.
% 0.67/1.05  { && }.
% 0.67/1.05  { ! singleton( X ) = unordered_pair( Y, Z ), X = Y }.
% 0.67/1.05  { singleton( skol3 ) = unordered_pair( skol1, skol2 ) }.
% 0.67/1.05  { ! skol1 = skol2 }.
% 0.67/1.05  
% 0.67/1.05  percentage equality = 0.833333, percentage horn = 1.000000
% 0.67/1.05  This is a pure equality problem
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Options Used:
% 0.67/1.05  
% 0.67/1.05  useres =            1
% 0.67/1.05  useparamod =        1
% 0.67/1.05  useeqrefl =         1
% 0.67/1.05  useeqfact =         1
% 0.67/1.05  usefactor =         1
% 0.67/1.05  usesimpsplitting =  0
% 0.67/1.05  usesimpdemod =      5
% 0.67/1.05  usesimpres =        3
% 0.67/1.05  
% 0.67/1.05  resimpinuse      =  1000
% 0.67/1.05  resimpclauses =     20000
% 0.67/1.05  substype =          eqrewr
% 0.67/1.05  backwardsubs =      1
% 0.67/1.05  selectoldest =      5
% 0.67/1.05  
% 0.67/1.05  litorderings [0] =  split
% 0.67/1.05  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.67/1.05  
% 0.67/1.05  termordering =      kbo
% 0.67/1.05  
% 0.67/1.05  litapriori =        0
% 0.67/1.05  termapriori =       1
% 0.67/1.05  litaposteriori =    0
% 0.67/1.05  termaposteriori =   0
% 0.67/1.05  demodaposteriori =  0
% 0.67/1.05  ordereqreflfact =   0
% 0.67/1.05  
% 0.67/1.05  litselect =         negord
% 0.67/1.05  
% 0.67/1.05  maxweight =         15
% 0.67/1.05  maxdepth =          30000
% 0.67/1.05  maxlength =         115
% 0.67/1.05  maxnrvars =         195
% 0.67/1.05  excuselevel =       1
% 0.67/1.05  increasemaxweight = 1
% 0.67/1.05  
% 0.67/1.05  maxselected =       10000000
% 0.67/1.05  maxnrclauses =      10000000
% 0.67/1.05  
% 0.67/1.05  showgenerated =    0
% 0.67/1.05  showkept =         0
% 0.67/1.05  showselected =     0
% 0.67/1.05  showdeleted =      0
% 0.67/1.05  showresimp =       1
% 0.67/1.05  showstatus =       2000
% 0.67/1.05  
% 0.67/1.05  prologoutput =     0
% 0.67/1.05  nrgoals =          5000000
% 0.67/1.05  totalproof =       1
% 0.67/1.05  
% 0.67/1.05  Symbols occurring in the translation:
% 0.67/1.05  
% 0.67/1.05  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.67/1.05  .  [1, 2]      (w:1, o:18, a:1, s:1, b:0), 
% 0.67/1.05  &&  [3, 0]      (w:1, o:4, a:1, s:1, b:0), 
% 0.67/1.05  !  [4, 1]      (w:0, o:12, a:1, s:1, b:0), 
% 0.67/1.05  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.67/1.05  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.67/1.05  unordered_pair  [37, 2]      (w:1, o:42, a:1, s:1, b:0), 
% 0.67/1.05  singleton  [39, 1]      (w:1, o:17, a:1, s:1, b:0), 
% 0.67/1.05  skol1  [40, 0]      (w:1, o:9, a:1, s:1, b:1), 
% 0.67/1.05  skol2  [41, 0]      (w:1, o:10, a:1, s:1, b:1), 
% 0.67/1.05  skol3  [42, 0]      (w:1, o:11, a:1, s:1, b:1).
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Starting Search:
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Bliksems!, er is een bewijs:
% 0.67/1.05  % SZS status Theorem
% 0.67/1.05  % SZS output start Refutation
% 0.67/1.05  
% 0.67/1.05  (0) {G0,W7,D3,L1,V2,M1} I { unordered_pair( X, Y ) = unordered_pair( Y, X )
% 0.67/1.05     }.
% 0.67/1.05  (2) {G0,W9,D3,L2,V3,M2} I { ! singleton( X ) = unordered_pair( Y, Z ), X = 
% 0.67/1.05    Y }.
% 0.67/1.05  (3) {G0,W6,D3,L1,V0,M1} I { unordered_pair( skol1, skol2 ) ==> singleton( 
% 0.67/1.05    skol3 ) }.
% 0.67/1.05  (4) {G0,W3,D2,L1,V0,M1} I { ! skol2 ==> skol1 }.
% 0.67/1.05  (5) {G1,W6,D3,L1,V0,M1} P(0,3) { unordered_pair( skol2, skol1 ) ==> 
% 0.67/1.05    singleton( skol3 ) }.
% 0.67/1.05  (11) {G2,W8,D3,L2,V1,M2} P(5,2) { ! singleton( X ) = singleton( skol3 ), X 
% 0.67/1.05    = skol2 }.
% 0.67/1.05  (19) {G1,W8,D3,L2,V1,M2} P(3,2) { ! singleton( X ) = singleton( skol3 ), X 
% 0.67/1.05    = skol1 }.
% 0.67/1.05  (28) {G2,W3,D2,L1,V0,M1} Q(19) { skol3 ==> skol1 }.
% 0.67/1.05  (29) {G3,W3,D2,L1,V0,M1} Q(11);d(28) { skol2 ==> skol1 }.
% 0.67/1.05  (32) {G4,W0,D0,L0,V0,M0} S(29);r(4) {  }.
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  % SZS output end Refutation
% 0.67/1.05  found a proof!
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Unprocessed initial clauses:
% 0.67/1.05  
% 0.67/1.05  (34) {G0,W7,D3,L1,V2,M1}  { unordered_pair( X, Y ) = unordered_pair( Y, X )
% 0.67/1.05     }.
% 0.67/1.05  (35) {G0,W1,D1,L1,V0,M1}  { && }.
% 0.67/1.05  (36) {G0,W1,D1,L1,V0,M1}  { && }.
% 0.67/1.05  (37) {G0,W9,D3,L2,V3,M2}  { ! singleton( X ) = unordered_pair( Y, Z ), X = 
% 0.67/1.05    Y }.
% 0.67/1.05  (38) {G0,W6,D3,L1,V0,M1}  { singleton( skol3 ) = unordered_pair( skol1, 
% 0.67/1.05    skol2 ) }.
% 0.67/1.05  (39) {G0,W3,D2,L1,V0,M1}  { ! skol1 = skol2 }.
% 0.67/1.05  
% 0.67/1.05  
% 0.67/1.05  Total Proof:
% 0.67/1.05  
% 0.67/1.05  subsumption: (0) {G0,W7,D3,L1,V2,M1} I { unordered_pair( X, Y ) = 
% 0.67/1.05    unordered_pair( Y, X ) }.
% 0.67/1.05  parent0: (34) {G0,W7,D3,L1,V2,M1}  { unordered_pair( X, Y ) = 
% 0.67/1.05    unordered_pair( Y, X ) }.
% 0.67/1.05  substitution0:
% 0.67/1.05     X := X
% 0.67/1.05     Y := Y
% 0.67/1.05  end
% 0.67/1.05  permutation0:
% 0.67/1.05     0 ==> 0
% 0.67/1.05  end
% 0.67/1.05  
% 0.67/1.05  subsumption: (2) {G0,W9,D3,L2,V3,M2} I { ! singleton( X ) = unordered_pair
% 0.67/1.05    ( Y, Z ), X = Y }.
% 0.67/1.05  parent0: (37) {G0,W9,D3,L2,V3,M2}  { ! singleton( X ) = unordered_pair( Y, 
% 0.67/1.05    Z ), X = Y }.
% 0.67/1.05  substitution0:
% 0.67/1.05     X := X
% 0.67/1.05     Y := Y
% 0.67/1.05     Z := Z
% 0.67/1.05  end
% 0.67/1.05  permutation0:
% 0.67/1.05     0 ==> 0
% 0.67/1.05     1 ==> 1
% 0.67/1.05  end
% 0.67/1.05  
% 0.67/1.05  eqswap: (46) {G0,W6,D3,L1,V0,M1}  { unordered_pair( skol1, skol2 ) = 
% 0.67/1.05    singleton( skol3 ) }.
% 0.67/1.05  parent0[0]: (38) {G0,W6,D3,L1,V0,M1}  { singleton( skol3 ) = unordered_pair
% 0.67/1.05    ( skol1, skol2 ) }.
% 0.67/1.05  substitution0:
% 0.67/1.05  end
% 0.67/1.05  
% 0.67/1.05  subsumptioCputime limit exceeded (core dumped)
%------------------------------------------------------------------------------