TSTP Solution File: SEU139+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEU139+1 : TPTP v8.1.2. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:40:23 EDT 2023

% Result   : Theorem 3.88s 4.05s
% Output   : Proof 3.88s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU139+1 : TPTP v8.1.2. Released v3.3.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n014.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Wed Aug 23 16:44:49 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.88/4.05  SZS status Theorem for theBenchmark.p
% 3.88/4.05  SZS output start Proof for theBenchmark.p
% 3.88/4.05  Clause #0 (by assumption #[]): Eq (∀ (A B : Iota), proper_subset A B → Not (proper_subset B A)) True
% 3.88/4.05  Clause #2 (by assumption #[]): Eq (∀ (A B : Iota), Iff (proper_subset A B) (And (subset A B) (Ne A B))) True
% 3.88/4.05  Clause #3 (by assumption #[]): Eq (∀ (A : Iota), Iota → Not (proper_subset A A)) True
% 3.88/4.05  Clause #5 (by assumption #[]): Eq (Not (∀ (A B : Iota), Not (And (subset A B) (proper_subset B A)))) True
% 3.88/4.05  Clause #8 (by clausification #[3]): ∀ (a : Iota), Eq (Iota → Not (proper_subset a a)) True
% 3.88/4.05  Clause #9 (by clausification #[8]): ∀ (a : Iota), Iota → Eq (Not (proper_subset a a)) True
% 3.88/4.05  Clause #10 (by clausification #[9]): ∀ (a : Iota), Eq (proper_subset a a) False
% 3.88/4.05  Clause #11 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (B : Iota), proper_subset a B → Not (proper_subset B a)) True
% 3.88/4.05  Clause #12 (by clausification #[11]): ∀ (a a_1 : Iota), Eq (proper_subset a a_1 → Not (proper_subset a_1 a)) True
% 3.88/4.05  Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Or (Eq (proper_subset a a_1) False) (Eq (Not (proper_subset a_1 a)) True)
% 3.88/4.05  Clause #14 (by clausification #[13]): ∀ (a a_1 : Iota), Or (Eq (proper_subset a a_1) False) (Eq (proper_subset a_1 a) False)
% 3.88/4.05  Clause #15 (by clausification #[5]): Eq (∀ (A B : Iota), Not (And (subset A B) (proper_subset B A))) False
% 3.88/4.05  Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Not (And (subset (skS.0 0 a) B) (proper_subset B (skS.0 0 a))))) True
% 3.88/4.05  Clause #17 (by clausification #[16]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (And (subset (skS.0 0 a) B) (proper_subset B (skS.0 0 a)))) False
% 3.88/4.05  Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota),
% 3.88/4.05    Eq (Not (Not (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (proper_subset (skS.0 1 a a_1) (skS.0 0 a))))) True
% 3.88/4.05  Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Eq (Not (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (proper_subset (skS.0 1 a a_1) (skS.0 0 a)))) False
% 3.88/4.05  Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Eq (And (subset (skS.0 0 a) (skS.0 1 a a_1)) (proper_subset (skS.0 1 a a_1) (skS.0 0 a))) True
% 3.88/4.05  Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota), Eq (proper_subset (skS.0 1 a a_1) (skS.0 0 a)) True
% 3.88/4.05  Clause #22 (by clausification #[20]): ∀ (a a_1 : Iota), Eq (subset (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.88/4.05  Clause #23 (by superposition #[21, 14]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (proper_subset (skS.0 0 a) (skS.0 1 a a_1)) False)
% 3.88/4.05  Clause #31 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (proper_subset a B) (And (subset a B) (Ne a B))) True
% 3.88/4.05  Clause #32 (by clausification #[31]): ∀ (a a_1 : Iota), Eq (Iff (proper_subset a a_1) (And (subset a a_1) (Ne a a_1))) True
% 3.88/4.05  Clause #33 (by clausification #[32]): ∀ (a a_1 : Iota), Or (Eq (proper_subset a a_1) True) (Eq (And (subset a a_1) (Ne a a_1)) False)
% 3.88/4.05  Clause #35 (by clausification #[33]): ∀ (a a_1 : Iota), Or (Eq (proper_subset a a_1) True) (Or (Eq (subset a a_1) False) (Eq (Ne a a_1) False))
% 3.88/4.05  Clause #36 (by clausification #[35]): ∀ (a a_1 : Iota), Or (Eq (proper_subset a a_1) True) (Or (Eq (subset a a_1) False) (Eq a a_1))
% 3.88/4.05  Clause #48 (by superposition #[22, 36]): ∀ (a a_1 : Iota),
% 3.88/4.05    Or (Eq (proper_subset (skS.0 0 a) (skS.0 1 a a_1)) True) (Or (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq False True))
% 3.88/4.05  Clause #53 (by clausification #[23]): ∀ (a a_1 : Iota), Eq (proper_subset (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.88/4.05  Clause #54 (by clausification #[48]): ∀ (a a_1 : Iota), Or (Eq (proper_subset (skS.0 0 a) (skS.0 1 a a_1)) True) (Eq (skS.0 0 a) (skS.0 1 a a_1))
% 3.88/4.05  Clause #55 (by superposition #[54, 53]): ∀ (a a_1 : Iota), Or (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq True False)
% 3.88/4.05  Clause #58 (by clausification #[55]): ∀ (a a_1 : Iota), Eq (skS.0 0 a) (skS.0 1 a a_1)
% 3.88/4.05  Clause #59 (by backward demodulation #[58, 21]): ∀ (a : Iota), Eq (proper_subset (skS.0 0 a) (skS.0 0 a)) True
% 3.88/4.05  Clause #65 (by superposition #[59, 10]): Eq True False
% 3.88/4.05  Clause #68 (by clausification #[65]): False
% 3.88/4.05  SZS output end Proof for theBenchmark.p
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