TSTP Solution File: SEU137+2 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SEU137+2 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:34:14 EDT 2022

% Result   : Theorem 0.15s 0.41s
% Output   : Refutation 0.15s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.10  % Problem  : SEU137+2 : TPTP v8.1.0. Released v3.3.0.
% 0.06/0.10  % Command  : run_spass %d %s
% 0.11/0.30  % Computer : n032.cluster.edu
% 0.11/0.30  % Model    : x86_64 x86_64
% 0.11/0.30  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.30  % Memory   : 8042.1875MB
% 0.11/0.30  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.30  % CPULimit : 300
% 0.11/0.30  % WCLimit  : 600
% 0.11/0.30  % DateTime : Mon Jun 20 09:07:33 EDT 2022
% 0.11/0.30  % CPUTime  : 
% 0.15/0.41  
% 0.15/0.41  SPASS V 3.9 
% 0.15/0.41  SPASS beiseite: Proof found.
% 0.15/0.41  % SZS status Theorem
% 0.15/0.41  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.15/0.41  SPASS derived 21 clauses, backtracked 0 clauses, performed 0 splits and kept 72 clauses.
% 0.15/0.41  SPASS allocated 98630 KBytes.
% 0.15/0.41  SPASS spent	0:00:00.10 on the problem.
% 0.15/0.41  		0:00:00.03 for the input.
% 0.15/0.41  		0:00:00.05 for the FLOTTER CNF translation.
% 0.15/0.41  		0:00:00.00 for inferences.
% 0.15/0.41  		0:00:00.00 for the backtracking.
% 0.15/0.41  		0:00:00.00 for the reduction.
% 0.15/0.41  
% 0.15/0.41  
% 0.15/0.41  Here is a proof with depth 1, length 7 :
% 0.15/0.41  % SZS output start Refutation
% 0.15/0.41  3[0:Inp] ||  -> subset(skc4,skc5)*r.
% 0.15/0.41  27[0:Inp] || equal(set_union2(skc4,set_difference(skc5,skc4)),skc5)** -> .
% 0.15/0.41  38[0:Inp] || subset(u,v) -> equal(set_union2(u,v),v)**.
% 0.15/0.41  42[0:Inp] ||  -> equal(set_union2(u,set_difference(v,u)),set_union2(u,v))**.
% 0.15/0.41  75[0:Rew:42.0,27.0] || equal(set_union2(skc4,skc5),skc5)** -> .
% 0.15/0.41  96[0:Res:3.0,38.0] ||  -> equal(set_union2(skc4,skc5),skc5)**.
% 0.15/0.41  101[0:MRR:96.0,75.0] ||  -> .
% 0.15/0.41  % SZS output end Refutation
% 0.15/0.41  Formulae used in the proof : t45_xboole_1 t12_xboole_1 t39_xboole_1
% 0.15/0.41  
%------------------------------------------------------------------------------