TSTP Solution File: SEU134+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU134+1 : TPTP v8.1.2. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:40:21 EDT 2023
% Result : Theorem 3.46s 3.67s
% Output : Proof 3.46s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU134+1 : TPTP v8.1.2. Released v3.3.0.
% 0.00/0.13 % Command : duper %s
% 0.14/0.35 % Computer : n025.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Thu Aug 24 01:25:06 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.46/3.67 SZS status Theorem for theBenchmark.p
% 3.46/3.67 SZS output start Proof for theBenchmark.p
% 3.46/3.67 Clause #11 (by assumption #[]): Eq (Not (∀ (A B : Iota), Iff (Eq (set_difference A B) empty_set) (subset A B))) True
% 3.46/3.67 Clause #12 (by assumption #[]): Eq (∀ (A B : Iota), Iff (Eq (set_difference A B) empty_set) (subset A B)) True
% 3.46/3.67 Clause #38 (by clausification #[12]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (Eq (set_difference a B) empty_set) (subset a B)) True
% 3.46/3.67 Clause #39 (by clausification #[38]): ∀ (a a_1 : Iota), Eq (Iff (Eq (set_difference a a_1) empty_set) (subset a a_1)) True
% 3.46/3.67 Clause #40 (by clausification #[39]): ∀ (a a_1 : Iota), Or (Eq (Eq (set_difference a a_1) empty_set) True) (Eq (subset a a_1) False)
% 3.46/3.67 Clause #41 (by clausification #[39]): ∀ (a a_1 : Iota), Or (Eq (Eq (set_difference a a_1) empty_set) False) (Eq (subset a a_1) True)
% 3.46/3.67 Clause #42 (by clausification #[40]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) False) (Eq (set_difference a a_1) empty_set)
% 3.46/3.67 Clause #45 (by clausification #[41]): ∀ (a a_1 : Iota), Or (Eq (subset a a_1) True) (Ne (set_difference a a_1) empty_set)
% 3.46/3.67 Clause #60 (by clausification #[11]): Eq (∀ (A B : Iota), Iff (Eq (set_difference A B) empty_set) (subset A B)) False
% 3.46/3.67 Clause #61 (by clausification #[60]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Iff (Eq (set_difference (skS.0 2 a) B) empty_set) (subset (skS.0 2 a) B))) True
% 3.46/3.67 Clause #62 (by clausification #[61]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (Eq (set_difference (skS.0 2 a) B) empty_set) (subset (skS.0 2 a) B)) False
% 3.46/3.67 Clause #63 (by clausification #[62]): ∀ (a a_1 : Iota),
% 3.46/3.67 Eq (Not (Iff (Eq (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set) (subset (skS.0 2 a) (skS.0 3 a a_1)))) True
% 3.46/3.67 Clause #64 (by clausification #[63]): ∀ (a a_1 : Iota),
% 3.46/3.67 Eq (Iff (Eq (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set) (subset (skS.0 2 a) (skS.0 3 a a_1))) False
% 3.46/3.67 Clause #65 (by clausification #[64]): ∀ (a a_1 : Iota),
% 3.46/3.67 Or (Eq (Eq (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set) False)
% 3.46/3.67 (Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) False)
% 3.46/3.67 Clause #66 (by clausification #[64]): ∀ (a a_1 : Iota),
% 3.46/3.67 Or (Eq (Eq (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set) True)
% 3.46/3.67 (Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) True)
% 3.46/3.67 Clause #67 (by clausification #[65]): ∀ (a a_1 : Iota),
% 3.46/3.67 Or (Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) False) (Ne (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set)
% 3.46/3.67 Clause #68 (by forward contextual literal cutting #[67, 42]): ∀ (a a_1 : Iota), Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) False
% 3.46/3.67 Clause #69 (by clausification #[66]): ∀ (a a_1 : Iota),
% 3.46/3.67 Or (Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) True) (Eq (set_difference (skS.0 2 a) (skS.0 3 a a_1)) empty_set)
% 3.46/3.67 Clause #70 (by forward contextual literal cutting #[69, 45]): ∀ (a a_1 : Iota), Eq (subset (skS.0 2 a) (skS.0 3 a a_1)) True
% 3.46/3.67 Clause #71 (by superposition #[70, 68]): Eq True False
% 3.46/3.67 Clause #73 (by clausification #[71]): False
% 3.46/3.67 SZS output end Proof for theBenchmark.p
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