TSTP Solution File: SEU130+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SEU130+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:14:51 EDT 2022

% Result   : Theorem 1.94s 2.11s
% Output   : Refutation 1.94s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   7 unt;   2 nHn;   9 RR)
%            Number of literals    :   22 (   7 equ;   8 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-3 aty)
%            Number of variables   :   14 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(5,axiom,
    ( ~ subset(A,B)
    | ~ in(C,A)
    | in(C,B) ),
    file('SEU130+1.p',unknown),
    [] ).

cnf(10,axiom,
    ( A = set_intersection2(B,C)
    | ~ in(dollar_f2(B,C,A),A)
    | ~ in(dollar_f2(B,C,A),B)
    | ~ in(dollar_f2(B,C,A),C) ),
    file('SEU130+1.p',unknown),
    [] ).

cnf(12,axiom,
    set_intersection2(dollar_c4,dollar_c3) != dollar_c4,
    file('SEU130+1.p',unknown),
    [] ).

cnf(19,plain,
    ( set_intersection2(A,B) = A
    | ~ in(dollar_f2(A,B,A),A)
    | ~ in(dollar_f2(A,B,A),B) ),
    inference(flip,[status(thm),theory(equality)],[inference(factor,[status(thm)],[10])]),
    [iquote('factor,10.2.3,flip.1')] ).

cnf(24,axiom,
    A = A,
    file('SEU130+1.p',unknown),
    [] ).

cnf(27,axiom,
    ( A = set_intersection2(B,C)
    | in(dollar_f2(B,C,A),A)
    | in(dollar_f2(B,C,A),B) ),
    file('SEU130+1.p',unknown),
    [] ).

cnf(35,axiom,
    subset(dollar_c4,dollar_c3),
    file('SEU130+1.p',unknown),
    [] ).

cnf(38,plain,
    ( set_intersection2(A,B) = A
    | in(dollar_f2(A,B,A),A) ),
    inference(flip,[status(thm),theory(equality)],[inference(factor,[status(thm)],[27])]),
    [iquote('factor,27.2.3,flip.1')] ).

cnf(467,plain,
    in(dollar_f2(dollar_c4,dollar_c3,dollar_c4),dollar_c4),
    inference(unit_del,[status(thm)],[inference(para_from,[status(thm),theory(equality)],[38,12]),24]),
    [iquote('para_from,38.1.1,12.1.1,unit_del,24')] ).

cnf(827,plain,
    in(dollar_f2(dollar_c4,dollar_c3,dollar_c4),dollar_c3),
    inference(hyper,[status(thm)],[467,5,35]),
    [iquote('hyper,467,5,35')] ).

cnf(1133,plain,
    set_intersection2(dollar_c4,dollar_c3) = dollar_c4,
    inference(hyper,[status(thm)],[827,19,467]),
    [iquote('hyper,827,19,467')] ).

cnf(1135,plain,
    $false,
    inference(binary,[status(thm)],[1133,12]),
    [iquote('binary,1133.1,12.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem  : SEU130+1 : TPTP v8.1.0. Released v3.3.0.
% 0.12/0.13  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n008.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 07:59:08 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.75/1.93  ----- Otter 3.3f, August 2004 -----
% 1.75/1.93  The process was started by sandbox2 on n008.cluster.edu,
% 1.75/1.93  Wed Jul 27 07:59:08 2022
% 1.75/1.93  The command was "./otter".  The process ID is 31624.
% 1.75/1.93  
% 1.75/1.93  set(prolog_style_variables).
% 1.75/1.93  set(auto).
% 1.75/1.93     dependent: set(auto1).
% 1.75/1.93     dependent: set(process_input).
% 1.75/1.93     dependent: clear(print_kept).
% 1.75/1.93     dependent: clear(print_new_demod).
% 1.75/1.93     dependent: clear(print_back_demod).
% 1.75/1.93     dependent: clear(print_back_sub).
% 1.75/1.93     dependent: set(control_memory).
% 1.75/1.93     dependent: assign(max_mem, 12000).
% 1.75/1.93     dependent: assign(pick_given_ratio, 4).
% 1.75/1.93     dependent: assign(stats_level, 1).
% 1.75/1.93     dependent: assign(max_seconds, 10800).
% 1.75/1.93  clear(print_given).
% 1.75/1.93  
% 1.75/1.93  formula_list(usable).
% 1.75/1.93  all A (A=A).
% 1.75/1.93  all A B (in(A,B)-> -in(B,A)).
% 1.75/1.93  all A B (set_intersection2(A,B)=set_intersection2(B,A)).
% 1.75/1.93  all A B (A=B<->subset(A,B)&subset(B,A)).
% 1.75/1.93  all A B (subset(A,B)<-> (all C (in(C,A)->in(C,B)))).
% 1.75/1.93  all A B C (C=set_intersection2(A,B)<-> (all D (in(D,C)<->in(D,A)&in(D,B)))).
% 1.75/1.93  $T.
% 1.75/1.93  $T.
% 1.75/1.93  empty(empty_set).
% 1.75/1.93  all A B (set_intersection2(A,A)=A).
% 1.75/1.93  exists A empty(A).
% 1.75/1.93  exists A (-empty(A)).
% 1.75/1.93  all A B subset(A,A).
% 1.75/1.93  all A B subset(set_intersection2(A,B),A).
% 1.75/1.93  -(all A B (subset(A,B)->set_intersection2(A,B)=A)).
% 1.75/1.93  all A (set_intersection2(A,empty_set)=empty_set).
% 1.75/1.93  all A (empty(A)->A=empty_set).
% 1.75/1.93  all A B (-(in(A,B)&empty(B))).
% 1.75/1.93  all A B (-(empty(A)&A!=B&empty(B))).
% 1.75/1.93  end_of_list.
% 1.75/1.93  
% 1.75/1.93  -------> usable clausifies to:
% 1.75/1.93  
% 1.75/1.93  list(usable).
% 1.75/1.93  0 [] A=A.
% 1.75/1.93  0 [] -in(A,B)| -in(B,A).
% 1.75/1.93  0 [] set_intersection2(A,B)=set_intersection2(B,A).
% 1.75/1.93  0 [] A!=B|subset(A,B).
% 1.75/1.93  0 [] A!=B|subset(B,A).
% 1.75/1.93  0 [] A=B| -subset(A,B)| -subset(B,A).
% 1.75/1.93  0 [] -subset(A,B)| -in(C,A)|in(C,B).
% 1.75/1.93  0 [] subset(A,B)|in($f1(A,B),A).
% 1.75/1.93  0 [] subset(A,B)| -in($f1(A,B),B).
% 1.75/1.93  0 [] C!=set_intersection2(A,B)| -in(D,C)|in(D,A).
% 1.75/1.93  0 [] C!=set_intersection2(A,B)| -in(D,C)|in(D,B).
% 1.75/1.93  0 [] C!=set_intersection2(A,B)|in(D,C)| -in(D,A)| -in(D,B).
% 1.75/1.93  0 [] C=set_intersection2(A,B)|in($f2(A,B,C),C)|in($f2(A,B,C),A).
% 1.75/1.93  0 [] C=set_intersection2(A,B)|in($f2(A,B,C),C)|in($f2(A,B,C),B).
% 1.75/1.93  0 [] C=set_intersection2(A,B)| -in($f2(A,B,C),C)| -in($f2(A,B,C),A)| -in($f2(A,B,C),B).
% 1.75/1.93  0 [] $T.
% 1.75/1.93  0 [] $T.
% 1.75/1.93  0 [] empty(empty_set).
% 1.75/1.93  0 [] set_intersection2(A,A)=A.
% 1.75/1.93  0 [] empty($c1).
% 1.75/1.93  0 [] -empty($c2).
% 1.75/1.93  0 [] subset(A,A).
% 1.75/1.93  0 [] subset(set_intersection2(A,B),A).
% 1.75/1.93  0 [] subset($c4,$c3).
% 1.75/1.93  0 [] set_intersection2($c4,$c3)!=$c4.
% 1.75/1.93  0 [] set_intersection2(A,empty_set)=empty_set.
% 1.75/1.93  0 [] -empty(A)|A=empty_set.
% 1.75/1.93  0 [] -in(A,B)| -empty(B).
% 1.75/1.93  0 [] -empty(A)|A=B| -empty(B).
% 1.75/1.93  end_of_list.
% 1.75/1.93  
% 1.75/1.93  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 1.75/1.93  
% 1.75/1.93  This ia a non-Horn set with equality.  The strategy will be
% 1.75/1.93  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.75/1.93  deletion, with positive clauses in sos and nonpositive
% 1.75/1.93  clauses in usable.
% 1.75/1.93  
% 1.75/1.93     dependent: set(knuth_bendix).
% 1.75/1.93     dependent: set(anl_eq).
% 1.75/1.93     dependent: set(para_from).
% 1.75/1.93     dependent: set(para_into).
% 1.75/1.93     dependent: clear(para_from_right).
% 1.75/1.93     dependent: clear(para_into_right).
% 1.75/1.93     dependent: set(para_from_vars).
% 1.75/1.93     dependent: set(eq_units_both_ways).
% 1.75/1.93     dependent: set(dynamic_demod_all).
% 1.75/1.93     dependent: set(dynamic_demod).
% 1.75/1.93     dependent: set(order_eq).
% 1.75/1.93     dependent: set(back_demod).
% 1.75/1.93     dependent: set(lrpo).
% 1.75/1.93     dependent: set(hyper_res).
% 1.75/1.93     dependent: set(unit_deletion).
% 1.75/1.93     dependent: set(factor).
% 1.75/1.93  
% 1.75/1.93  ------------> process usable:
% 1.75/1.93  ** KEPT (pick-wt=6): 1 [] -in(A,B)| -in(B,A).
% 1.75/1.93  ** KEPT (pick-wt=6): 2 [] A!=B|subset(A,B).
% 1.75/1.93  ** KEPT (pick-wt=6): 3 [] A!=B|subset(B,A).
% 1.75/1.93  ** KEPT (pick-wt=9): 4 [] A=B| -subset(A,B)| -subset(B,A).
% 1.75/1.93  ** KEPT (pick-wt=9): 5 [] -subset(A,B)| -in(C,A)|in(C,B).
% 1.75/1.93  ** KEPT (pick-wt=8): 6 [] subset(A,B)| -in($f1(A,B),B).
% 1.75/1.93  ** KEPT (pick-wt=11): 7 [] A!=set_intersection2(B,C)| -in(D,A)|in(D,B).
% 1.75/1.93  ** KEPT (pick-wt=11): 8 [] A!=set_intersection2(B,C)| -in(D,A)|in(D,C).
% 1.75/1.93  ** KEPT (pick-wt=14): 9 [] A!=set_intersection2(B,C)|in(D,A)| -in(D,B)| -in(D,C).
% 1.75/1.93  ** KEPT (pick-wt=23): 10 [] A=set_intersection2(B,C)| -in($f2(B,C,A),A)| -in($f2(B,C,A),B)| -in($f2(B,C,A),C).
% 1.75/1.93  ** KEPT (pick-wt=2): 11 [] -empty($c2).
% 1.75/1.93  ** KEPT (pick-wt=5): 12 [] set_intersection2($c4,$c3)!=$c4.
% 1.75/1.93  ** KEPT (pick-wt=5): 13 [] -empty(A)|A=empty_set.
% 1.75/1.93  ** KEPT (pick-wt=5): 14 [] -in(A,B)| -empty(B).
% 1.75/1.93  ** KEPT (pick-wt=7): 15 [] -empty(A)|A=B| -empty(B).
% 1.75/1.93  
% 1.75/1.93  ------------> process sos:
% 1.94/2.11  ** KEPT (pick-wt=3): 24 [] A=A.
% 1.94/2.11  ** KEPT (pick-wt=7): 25 [] set_intersection2(A,B)=set_intersection2(B,A).
% 1.94/2.11  ** KEPT (pick-wt=8): 26 [] subset(A,B)|in($f1(A,B),A).
% 1.94/2.11  ** KEPT (pick-wt=17): 27 [] A=set_intersection2(B,C)|in($f2(B,C,A),A)|in($f2(B,C,A),B).
% 1.94/2.11  ** KEPT (pick-wt=17): 28 [] A=set_intersection2(B,C)|in($f2(B,C,A),A)|in($f2(B,C,A),C).
% 1.94/2.11  ** KEPT (pick-wt=2): 29 [] empty(empty_set).
% 1.94/2.11  ** KEPT (pick-wt=5): 30 [] set_intersection2(A,A)=A.
% 1.94/2.11  ---> New Demodulator: 31 [new_demod,30] set_intersection2(A,A)=A.
% 1.94/2.11  ** KEPT (pick-wt=2): 32 [] empty($c1).
% 1.94/2.11  ** KEPT (pick-wt=3): 33 [] subset(A,A).
% 1.94/2.11  ** KEPT (pick-wt=5): 34 [] subset(set_intersection2(A,B),A).
% 1.94/2.11  ** KEPT (pick-wt=3): 35 [] subset($c4,$c3).
% 1.94/2.11  ** KEPT (pick-wt=5): 36 [] set_intersection2(A,empty_set)=empty_set.
% 1.94/2.11  ---> New Demodulator: 37 [new_demod,36] set_intersection2(A,empty_set)=empty_set.
% 1.94/2.11    Following clause subsumed by 24 during input processing: 0 [copy,24,flip.1] A=A.
% 1.94/2.11  24 back subsumes 22.
% 1.94/2.11  24 back subsumes 17.
% 1.94/2.11    Following clause subsumed by 25 during input processing: 0 [copy,25,flip.1] set_intersection2(A,B)=set_intersection2(B,A).
% 1.94/2.11  >>>> Starting back demodulation with 31.
% 1.94/2.11      >> back demodulating 23 with 31.
% 1.94/2.11      >> back demodulating 21 with 31.
% 1.94/2.11      >> back demodulating 18 with 31.
% 1.94/2.11  >>>> Starting back demodulation with 37.
% 1.94/2.11  
% 1.94/2.11  ======= end of input processing =======
% 1.94/2.11  
% 1.94/2.11  =========== start of search ===========
% 1.94/2.11  
% 1.94/2.11  -------- PROOF -------- 
% 1.94/2.11  
% 1.94/2.11  ----> UNIT CONFLICT at   0.18 sec ----> 1135 [binary,1133.1,12.1] $F.
% 1.94/2.11  
% 1.94/2.11  Length of proof is 5.  Level of proof is 4.
% 1.94/2.11  
% 1.94/2.11  ---------------- PROOF ----------------
% 1.94/2.11  % SZS status Theorem
% 1.94/2.11  % SZS output start Refutation
% See solution above
% 1.94/2.11  ------------ end of proof -------------
% 1.94/2.11  
% 1.94/2.11  
% 1.94/2.11  Search stopped by max_proofs option.
% 1.94/2.11  
% 1.94/2.11  
% 1.94/2.11  Search stopped by max_proofs option.
% 1.94/2.11  
% 1.94/2.11  ============ end of search ============
% 1.94/2.11  
% 1.94/2.11  -------------- statistics -------------
% 1.94/2.11  clauses given                 53
% 1.94/2.11  clauses generated           3522
% 1.94/2.11  clauses kept                1128
% 1.94/2.11  clauses forward subsumed    2418
% 1.94/2.11  clauses back subsumed         99
% 1.94/2.11  Kbytes malloced             2929
% 1.94/2.11  
% 1.94/2.11  ----------- times (seconds) -----------
% 1.94/2.11  user CPU time          0.19          (0 hr, 0 min, 0 sec)
% 1.94/2.11  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.94/2.11  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.94/2.11  
% 1.94/2.11  That finishes the proof of the theorem.
% 1.94/2.11  
% 1.94/2.11  Process 31624 finished Wed Jul 27 07:59:10 2022
% 1.94/2.11  Otter interrupted
% 1.94/2.11  PROOF FOUND
%------------------------------------------------------------------------------