TSTP Solution File: SEU126+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SEU126+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:26:57 EDT 2022

% Result   : Theorem 0.55s 0.73s
% Output   : Refutation 0.55s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.14/0.14  % Problem  : SEU126+1 : TPTP v8.1.0. Released v3.3.0.
% 0.14/0.15  % Command  : sos-script %s
% 0.16/0.37  % Computer : n015.cluster.edu
% 0.16/0.37  % Model    : x86_64 x86_64
% 0.16/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37  % Memory   : 8042.1875MB
% 0.16/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37  % CPULimit : 300
% 0.16/0.37  % WCLimit  : 600
% 0.16/0.37  % DateTime : Sun Jun 19 23:08:45 EDT 2022
% 0.16/0.37  % CPUTime  : 
% 0.16/0.39  ----- Otter 3.2, August 2001 -----
% 0.16/0.39  The process was started by sandbox2 on n015.cluster.edu,
% 0.16/0.39  Sun Jun 19 23:08:45 2022
% 0.16/0.39  The command was "./sos".  The process ID is 6329.
% 0.16/0.39  
% 0.16/0.39  set(prolog_style_variables).
% 0.16/0.39  set(auto).
% 0.16/0.39     dependent: set(auto1).
% 0.16/0.39     dependent: set(process_input).
% 0.16/0.39     dependent: clear(print_kept).
% 0.16/0.39     dependent: clear(print_new_demod).
% 0.16/0.39     dependent: clear(print_back_demod).
% 0.16/0.39     dependent: clear(print_back_sub).
% 0.16/0.39     dependent: set(control_memory).
% 0.16/0.39     dependent: assign(max_mem, 12000).
% 0.16/0.39     dependent: assign(pick_given_ratio, 4).
% 0.16/0.39     dependent: assign(stats_level, 1).
% 0.16/0.39     dependent: assign(pick_semantic_ratio, 3).
% 0.16/0.39     dependent: assign(sos_limit, 5000).
% 0.16/0.39     dependent: assign(max_weight, 60).
% 0.16/0.39  clear(print_given).
% 0.16/0.39  
% 0.16/0.39  formula_list(usable).
% 0.16/0.39  
% 0.16/0.39  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 0.16/0.39  
% 0.16/0.39  This ia a non-Horn set with equality.  The strategy will be
% 0.16/0.39  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.16/0.39  unit deletion, with positive clauses in sos and nonpositive
% 0.16/0.39  clauses in usable.
% 0.16/0.39  
% 0.16/0.39     dependent: set(knuth_bendix).
% 0.16/0.39     dependent: set(para_from).
% 0.16/0.39     dependent: set(para_into).
% 0.16/0.39     dependent: clear(para_from_right).
% 0.16/0.39     dependent: clear(para_into_right).
% 0.16/0.39     dependent: set(para_from_vars).
% 0.16/0.39     dependent: set(eq_units_both_ways).
% 0.16/0.39     dependent: set(dynamic_demod_all).
% 0.16/0.39     dependent: set(dynamic_demod).
% 0.16/0.39     dependent: set(order_eq).
% 0.16/0.39     dependent: set(back_demod).
% 0.16/0.39     dependent: set(lrpo).
% 0.16/0.39     dependent: set(hyper_res).
% 0.16/0.39     dependent: set(unit_deletion).
% 0.16/0.39     dependent: set(factor).
% 0.16/0.39  
% 0.16/0.39  ------------> process usable:
% 0.16/0.39  
% 0.16/0.39  ------------> process sos:
% 0.16/0.39    Following clause subsumed by 25 during input processing: 0 [copy,25,flip.1] {-} set_union2(A,B)=set_union2(B,A).
% 0.16/0.39    Following clause subsumed by 36 during input processing: 0 [copy,36,flip.1] {-} A=A.
% 0.16/0.39  36 back subsumes 24.
% 0.16/0.39  36 back subsumes 20.
% 0.16/0.39  
% 0.16/0.39  ======= end of input processing =======
% 0.16/0.42  
% 0.16/0.42  Model 1 (0.00 seconds, 0 Inserts)
% 0.16/0.42  
% 0.16/0.42  Stopped by limit on number of solutions
% 0.16/0.42  
% 0.16/0.42  
% 0.16/0.42  -------------- Softie stats --------------
% 0.16/0.42  
% 0.16/0.42  UPDATE_STOP: 300
% 0.16/0.42  SFINDER_TIME_LIMIT: 2
% 0.16/0.42  SHORT_CLAUSE_CUTOFF: 4
% 0.16/0.42  number of clauses in intial UL: 21
% 0.16/0.42  number of clauses initially in problem: 37
% 0.16/0.42  percentage of clauses intially in UL: 56
% 0.16/0.42  percentage of distinct symbols occuring in initial UL: 91
% 0.16/0.42  percent of all initial clauses that are short: 100
% 0.16/0.42  absolute distinct symbol count: 12
% 0.16/0.42     distinct predicate count: 4
% 0.16/0.42     distinct function count: 3
% 0.16/0.42     distinct constant count: 5
% 0.16/0.42  
% 0.16/0.42  ---------- no more Softie stats ----------
% 0.16/0.42  
% 0.16/0.42  
% 0.16/0.42  
% 0.16/0.42  =========== start of search ===========
% 0.55/0.73  
% 0.55/0.73  -------- PROOF -------- 
% 0.55/0.73  % SZS status Theorem
% 0.55/0.73  % SZS output start Refutation
% 0.55/0.73  
% 0.55/0.73  Model 2 (0.00 seconds, 0 Inserts)
% 0.55/0.73  
% 0.55/0.73  Stopped by limit on number of solutions
% 0.55/0.73  
% 0.55/0.73  Stopped by limit on insertions
% 0.55/0.73  
% 0.55/0.73  Model 3 [ 1 1 353 ] (0.00 seconds, 250000 Inserts)
% 0.55/0.73  
% 0.55/0.73  Stopped by limit on insertions
% 0.55/0.73  
% 0.55/0.73  Model 4 [ 1 0 570 ] (0.00 seconds, 250000 Inserts)
% 0.55/0.73  
% 0.55/0.73  Stopped by limit on insertions
% 0.55/0.73  
% 0.55/0.73  ----> UNIT CONFLICT at   0.32 sec ----> 322 [binary,320.1,15.1] {-} $F.
% 0.55/0.73  
% 0.55/0.73  Length of proof is 5.  Level of proof is 4.
% 0.55/0.73  
% 0.55/0.73  ---------------- PROOF ----------------
% 0.55/0.73  % SZS status Theorem
% 0.55/0.73  % SZS output start Refutation
% 0.55/0.73  
% 0.55/0.73  9 [] {+} A=set_union2(B,C)| -in($f1(B,C,A),A)| -in($f1(B,C,A),C).
% 0.55/0.73  10 [] {+} -subset(A,B)| -in(C,A)|in(C,B).
% 0.55/0.73  15 [] {+} set_union2($c4,$c3)!=$c3.
% 0.55/0.73  23 [factor,9.2.3,flip.1] {+} set_union2(A,B)=B| -in($f1(A,B,B),B).
% 0.55/0.73  26 [] {-} A=set_union2(B,C)|in($f1(B,C,A),A)|in($f1(B,C,A),B)|in($f1(B,C,A),C).
% 0.55/0.73  33 [] {+} subset($c4,$c3).
% 0.55/0.73  94 [hyper,26,10,33] {-} A=set_union2($c4,B)|in($f1($c4,B,A),A)|in($f1($c4,B,A),B)|in($f1($c4,B,A),$c3).
% 0.55/0.73  124 [factor,94.2.3,flip.1] {-} set_union2($c4,A)=A|in($f1($c4,A,A),A)|in($f1($c4,A,A),$c3).
% 0.55/0.73  164 [factor,124.2.3,unit_del,15] {-} in($f1($c4,$c3,$c3),$c3).
% 0.55/0.73  320 [hyper,164,23] {-} set_union2($c4,$c3)=$c3.
% 0.55/0.73  322 [binary,320.1,15.1] {-} $F.
% 0.55/0.73  
% 0.55/0.73  % SZS output end Refutation
% 0.55/0.73  ------------ end of proof -------------
% 0.55/0.73  
% 0.55/0.73  
% 0.55/0.73  Search stopped by max_proofs option.
% 0.55/0.73  
% 0.55/0.73  
% 0.55/0.73  Search stopped by max_proofs option.
% 0.55/0.73  
% 0.55/0.73  ============ end of search ============
% 0.55/0.73  
% 0.55/0.73  ----------- soft-scott stats ----------
% 0.55/0.73  
% 0.55/0.73  true clauses given           2      (28.6%)
% 0.55/0.73  false clauses given          5
% 0.55/0.73  
% 0.55/0.73        FALSE     TRUE
% 0.55/0.73     3  0         3
% 0.55/0.73     5  0         10
% 0.55/0.73     6  1         1
% 0.55/0.73     7  0         3
% 0.55/0.73     8  0         3
% 0.55/0.73     9  4         3
% 0.55/0.73    10  0         1
% 0.55/0.73    11  4         5
% 0.55/0.73    12  0         1
% 0.55/0.73    13  0         1
% 0.55/0.73    14  3         1
% 0.55/0.73    15  4         2
% 0.55/0.73    16  1         7
% 0.55/0.73    17  23        3
% 0.55/0.73    19  4         5
% 0.55/0.73    20  1         0
% 0.55/0.73    21  2         9
% 0.55/0.73    22  11        3
% 0.55/0.73    23  14        0
% 0.55/0.73    24  3         0
% 0.55/0.73    25  19        3
% 0.55/0.73    26  2         2
% 0.55/0.73    27  1         4
% 0.55/0.73    28  3         0
% 0.55/0.73    29  2         3
% 0.55/0.73    30  0         4
% 0.55/0.73    31  17        0
% 0.55/0.73    32  9         2
% 0.55/0.73    33  2         0
% 0.55/0.73    34  5         1
% 0.55/0.73    35  8         4
% 0.55/0.73    37  5         1
% 0.55/0.73    39  3         0
% 0.55/0.73    40  7         5
% 0.55/0.73    41  3         0
% 0.55/0.73    43  6         0
% 0.55/0.73    44  3         0
% 0.55/0.73    46  9         9
% 0.55/0.73    52  9         0
% 0.55/0.73  tot:  188       99      (34.5% true)
% 0.55/0.73  
% 0.55/0.73  
% 0.55/0.73  Model 4 [ 1 -8 570 ] (0.00 seconds, 250000 Inserts)
% 0.55/0.73  
% 0.55/0.73  That finishes the proof of the theorem.
% 0.55/0.73  
% 0.55/0.73  Process 6329 finished Sun Jun 19 23:08:45 2022
%------------------------------------------------------------------------------