TSTP Solution File: SEU117+1 by SPASS---3.9
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SEU117+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 14:34:03 EDT 2022
% Result : Theorem 0.18s 0.44s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 9
% Syntax : Number of clauses : 16 ( 10 unt; 2 nHn; 16 RR)
% Number of literals : 26 ( 0 equ; 11 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 9 ( 8 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 5 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(13,axiom,
cup_closed(finite_subsets(u)),
file('SEU117+1.p',unknown),
[] ).
cnf(14,axiom,
diff_closed(finite_subsets(u)),
file('SEU117+1.p',unknown),
[] ).
cnf(15,axiom,
preboolean(finite_subsets(u)),
file('SEU117+1.p',unknown),
[] ).
cnf(29,axiom,
element(skc7,finite_subsets(skc6)),
file('SEU117+1.p',unknown),
[] ).
cnf(32,axiom,
~ empty(finite_subsets(u)),
file('SEU117+1.p',unknown),
[] ).
cnf(34,axiom,
~ element(skc7,powerset(skc6)),
file('SEU117+1.p',unknown),
[] ).
cnf(55,axiom,
( ~ subset(u,v)
| element(u,powerset(v)) ),
file('SEU117+1.p',unknown),
[] ).
cnf(56,axiom,
( ~ element(u,v)
| empty(v)
| in(u,v) ),
file('SEU117+1.p',unknown),
[] ).
cnf(62,axiom,
( ~ preboolean(u)
| ~ in(v,u)
| ~ equal(u,finite_subsets(w))
| subset(v,w) ),
file('SEU117+1.p',unknown),
[] ).
cnf(67,plain,
( in(skc7,finite_subsets(skc6))
| empty(finite_subsets(skc6)) ),
inference(res,[status(thm),theory(equality)],[29,56]),
[iquote('0:Res:29.0,56.0')] ).
cnf(70,plain,
~ subset(skc7,skc6),
inference(res,[status(thm),theory(equality)],[55,34]),
[iquote('0:Res:55.1,34.0')] ).
cnf(72,plain,
in(skc7,finite_subsets(skc6)),
inference(mrr,[status(thm)],[67,32]),
[iquote('0:MRR:67.1,32.0')] ).
cnf(148,plain,
( ~ preboolean(finite_subsets(u))
| ~ in(v,finite_subsets(u))
| subset(v,u) ),
inference(eqr,[status(thm),theory(equality)],[62]),
[iquote('0:EqR:62.2')] ).
cnf(149,plain,
( ~ in(u,finite_subsets(v))
| subset(u,v) ),
inference(ssi,[status(thm)],[148,14,13,15]),
[iquote('0:SSi:148.0,14.0,13.0,15.0')] ).
cnf(150,plain,
subset(skc7,skc6),
inference(res,[status(thm),theory(equality)],[72,149]),
[iquote('0:Res:72.0,149.0')] ).
cnf(152,plain,
$false,
inference(mrr,[status(thm)],[150,70]),
[iquote('0:MRR:150.0,70.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : SEU117+1 : TPTP v8.1.0. Released v3.2.0.
% 0.12/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n017.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Sun Jun 19 04:33:13 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.44
% 0.18/0.44 SPASS V 3.9
% 0.18/0.44 SPASS beiseite: Proof found.
% 0.18/0.44 % SZS status Theorem
% 0.18/0.44 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.44 SPASS derived 81 clauses, backtracked 0 clauses, performed 0 splits and kept 118 clauses.
% 0.18/0.44 SPASS allocated 97862 KBytes.
% 0.18/0.44 SPASS spent 0:00:00.10 on the problem.
% 0.18/0.44 0:00:00.03 for the input.
% 0.18/0.44 0:00:00.03 for the FLOTTER CNF translation.
% 0.18/0.44 0:00:00.00 for inferences.
% 0.18/0.44 0:00:00.00 for the backtracking.
% 0.18/0.44 0:00:00.00 for the reduction.
% 0.18/0.44
% 0.18/0.44
% 0.18/0.44 Here is a proof with depth 2, length 16 :
% 0.18/0.44 % SZS output start Refutation
% See solution above
% 0.18/0.44 Formulae used in the proof : fc2_finsub_1 t32_finsub_1 t3_subset t2_subset d5_finsub_1 antisymmetry_r2_hidden
% 0.18/0.44
%------------------------------------------------------------------------------