TSTP Solution File: SEU045+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SEU045+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 14:33:42 EDT 2022
% Result : Theorem 0.22s 0.50s
% Output : Refutation 0.22s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 7
% Syntax : Number of clauses : 13 ( 8 unt; 0 nHn; 13 RR)
% Number of literals : 28 ( 0 equ; 18 neg)
% Maximal clause size : 7 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 10 ( 10 usr; 7 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
relation(skc11),
file('SEU045+1.p',unknown),
[] ).
cnf(2,axiom,
function(skc11),
file('SEU045+1.p',unknown),
[] ).
cnf(33,axiom,
in(skc12,relation_dom(relation_rng_restriction(skc13,skc11))),
file('SEU045+1.p',unknown),
[] ).
cnf(38,axiom,
( ~ relation(u)
| relation(relation_rng_restriction(v,u)) ),
file('SEU045+1.p',unknown),
[] ).
cnf(47,axiom,
~ equal(apply(relation_rng_restriction(skc13,skc11),skc12),apply(skc11,skc12)),
file('SEU045+1.p',unknown),
[] ).
cnf(49,axiom,
( ~ relation(u)
| ~ function(u)
| function(relation_rng_restriction(v,u)) ),
file('SEU045+1.p',unknown),
[] ).
cnf(55,axiom,
( ~ relation(u)
| ~ function(u)
| ~ relation(v)
| ~ function(v)
| ~ in(w,relation_dom(u))
| ~ equal(u,relation_rng_restriction(x,v))
| equal(apply(u,w),apply(v,w)) ),
file('SEU045+1.p',unknown),
[] ).
cnf(74,plain,
( ~ relation(skc11)
| function(relation_rng_restriction(u,skc11)) ),
inference(res,[status(thm),theory(equality)],[2,49]),
[iquote('0:Res:2.0,49.0')] ).
cnf(97,plain,
relation(relation_rng_restriction(u,skc11)),
inference(res,[status(thm),theory(equality)],[1,38]),
[iquote('0:Res:1.0,38.0')] ).
cnf(119,plain,
( ~ function(skc11)
| ~ relation(skc11)
| ~ function(relation_rng_restriction(skc13,skc11))
| ~ relation(relation_rng_restriction(skc13,skc11))
| ~ in(skc12,relation_dom(relation_rng_restriction(skc13,skc11)))
| ~ equal(relation_rng_restriction(skc13,skc11),relation_rng_restriction(u,skc11)) ),
inference(res,[status(thm),theory(equality)],[55,47]),
[iquote('0:Res:55.6,47.0')] ).
cnf(122,plain,
function(relation_rng_restriction(u,skc11)),
inference(mrr,[status(thm)],[74,1]),
[iquote('0:MRR:74.0,1.0')] ).
cnf(134,plain,
~ equal(relation_rng_restriction(skc13,skc11),relation_rng_restriction(u,skc11)),
inference(mrr,[status(thm)],[119,2,1,122,97,33]),
[iquote('0:MRR:119.0,119.1,119.2,119.3,119.4,2.0,1.0,122.0,97.0,33.0')] ).
cnf(193,plain,
$false,
inference(eqr,[status(thm),theory(equality)],[134]),
[iquote('0:EqR:134.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14 % Problem : SEU045+1 : TPTP v8.1.0. Released v3.2.0.
% 0.08/0.14 % Command : run_spass %d %s
% 0.14/0.36 % Computer : n016.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 600
% 0.14/0.36 % DateTime : Sun Jun 19 20:55:09 EDT 2022
% 0.14/0.36 % CPUTime :
% 0.22/0.50
% 0.22/0.50 SPASS V 3.9
% 0.22/0.50 SPASS beiseite: Proof found.
% 0.22/0.50 % SZS status Theorem
% 0.22/0.50 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.22/0.50 SPASS derived 101 clauses, backtracked 0 clauses, performed 3 splits and kept 113 clauses.
% 0.22/0.50 SPASS allocated 98080 KBytes.
% 0.22/0.50 SPASS spent 0:00:00.13 on the problem.
% 0.22/0.50 0:00:00.03 for the input.
% 0.22/0.50 0:00:00.06 for the FLOTTER CNF translation.
% 0.22/0.50 0:00:00.00 for inferences.
% 0.22/0.50 0:00:00.00 for the backtracking.
% 0.22/0.50 0:00:00.01 for the reduction.
% 0.22/0.50
% 0.22/0.50
% 0.22/0.50 Here is a proof with depth 2, length 13 :
% 0.22/0.50 % SZS output start Refutation
% See solution above
% 0.22/0.50 Formulae used in the proof : t87_funct_1 dt_k8_relat_1 fc5_funct_1 t85_funct_1
% 0.22/0.50
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