TSTP Solution File: SET978+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SET978+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:30:11 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   10 (   5 unt;   1 nHn;  10 RR)
%            Number of literals    :   15 (   0 equ;   9 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    3 (   2 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   12 (  12 usr;  10 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    ~ equal(skc9,skc8),
    file('SET978+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( equal(u,v)
    | disjoint(singleton(u),singleton(v)) ),
    file('SET978+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ disjoint(u,v)
    | disjoint(cartesian_product2(u,w),cartesian_product2(v,x)) ),
    file('SET978+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ disjoint(u,v)
    | disjoint(cartesian_product2(w,u),cartesian_product2(x,v)) ),
    file('SET978+1.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ disjoint(cartesian_product2(skc12,singleton(skc8)),cartesian_product2(skc13,singleton(skc9)))
    | ~ disjoint(cartesian_product2(singleton(skc8),skc10),cartesian_product2(singleton(skc9),skc11)) ),
    file('SET978+1.p',unknown),
    [] ).

cnf(10,plain,
    disjoint(singleton(skc8),singleton(skc9)),
    inference(res,[status(thm),theory(equality)],[5,3]),
    [iquote('0:Res:5.0,3.0')] ).

cnf(17,plain,
    ( ~ disjoint(singleton(skc8),singleton(skc9))
    | ~ disjoint(cartesian_product2(skc12,singleton(skc8)),cartesian_product2(skc13,singleton(skc9))) ),
    inference(res,[status(thm),theory(equality)],[6,8]),
    [iquote('0:Res:6.1,8.1')] ).

cnf(18,plain,
    ~ disjoint(cartesian_product2(skc12,singleton(skc8)),cartesian_product2(skc13,singleton(skc9))),
    inference(mrr,[status(thm)],[17,10]),
    [iquote('0:MRR:17.0,10.0')] ).

cnf(19,plain,
    ~ disjoint(singleton(skc8),singleton(skc9)),
    inference(res,[status(thm),theory(equality)],[7,18]),
    [iquote('0:Res:7.1,18.0')] ).

cnf(21,plain,
    $false,
    inference(mrr,[status(thm)],[19,10]),
    [iquote('0:MRR:19.0,10.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : SET978+1 : TPTP v8.1.0. Released v3.2.0.
% 0.07/0.14  % Command  : run_spass %d %s
% 0.13/0.35  % Computer : n017.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Sat Jul  9 15:24:17 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 11 clauses, backtracked 0 clauses, performed 0 splits and kept 16 clauses.
% 0.20/0.45  SPASS allocated 85099 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 2, length 10 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : t131_zfmisc_1 t17_zfmisc_1 t127_zfmisc_1
% 0.20/0.45  
%------------------------------------------------------------------------------