TSTP Solution File: SET942+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SET942+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:22:01 EDT 2022

% Result   : Theorem 0.50s 0.70s
% Output   : Refutation 0.50s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SET942+1 : TPTP v8.1.0. Released v3.2.0.
% 0.03/0.12  % Command  : sos-script %s
% 0.13/0.33  % Computer : n014.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Sun Jul 10 20:21:20 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.13/0.35  ----- Otter 3.2, August 2001 -----
% 0.13/0.35  The process was started by sandbox2 on n014.cluster.edu,
% 0.13/0.35  Sun Jul 10 20:21:20 2022
% 0.13/0.35  The command was "./sos".  The process ID is 27880.
% 0.13/0.35  
% 0.13/0.35  set(prolog_style_variables).
% 0.13/0.35  set(auto).
% 0.13/0.35     dependent: set(auto1).
% 0.13/0.35     dependent: set(process_input).
% 0.13/0.35     dependent: clear(print_kept).
% 0.13/0.35     dependent: clear(print_new_demod).
% 0.13/0.35     dependent: clear(print_back_demod).
% 0.13/0.35     dependent: clear(print_back_sub).
% 0.13/0.35     dependent: set(control_memory).
% 0.13/0.35     dependent: assign(max_mem, 12000).
% 0.13/0.35     dependent: assign(pick_given_ratio, 4).
% 0.13/0.35     dependent: assign(stats_level, 1).
% 0.13/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.35     dependent: assign(sos_limit, 5000).
% 0.13/0.35     dependent: assign(max_weight, 60).
% 0.13/0.35  clear(print_given).
% 0.13/0.35  
% 0.13/0.35  formula_list(usable).
% 0.13/0.35  
% 0.13/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=4.
% 0.13/0.35  
% 0.13/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.35  clauses in usable.
% 0.13/0.35  
% 0.13/0.35     dependent: set(knuth_bendix).
% 0.13/0.35     dependent: set(para_from).
% 0.13/0.35     dependent: set(para_into).
% 0.13/0.35     dependent: clear(para_from_right).
% 0.13/0.35     dependent: clear(para_into_right).
% 0.13/0.35     dependent: set(para_from_vars).
% 0.13/0.35     dependent: set(eq_units_both_ways).
% 0.13/0.35     dependent: set(dynamic_demod_all).
% 0.13/0.35     dependent: set(dynamic_demod).
% 0.13/0.35     dependent: set(order_eq).
% 0.13/0.35     dependent: set(back_demod).
% 0.13/0.35     dependent: set(lrpo).
% 0.13/0.35     dependent: set(hyper_res).
% 0.13/0.35     dependent: set(unit_deletion).
% 0.13/0.35     dependent: set(factor).
% 0.13/0.35  
% 0.13/0.35  ------------> process usable:
% 0.13/0.35  
% 0.13/0.35  ------------> process sos:
% 0.13/0.35    Following clause subsumed by 18 during input processing: 0 [copy,18,flip.1] {-} A=A.
% 0.13/0.35  
% 0.13/0.35  ======= end of input processing =======
% 0.20/0.39  
% 0.20/0.39  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.39  
% 0.20/0.39  Stopped by limit on number of solutions
% 0.20/0.39  
% 0.20/0.39  
% 0.20/0.39  -------------- Softie stats --------------
% 0.20/0.39  
% 0.20/0.39  UPDATE_STOP: 300
% 0.20/0.39  SFINDER_TIME_LIMIT: 2
% 0.20/0.39  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.39  number of clauses in intial UL: 11
% 0.20/0.39  number of clauses initially in problem: 18
% 0.20/0.39  percentage of clauses intially in UL: 61
% 0.20/0.39  percentage of distinct symbols occuring in initial UL: 84
% 0.20/0.39  percent of all initial clauses that are short: 100
% 0.20/0.39  absolute distinct symbol count: 13
% 0.20/0.39     distinct predicate count: 4
% 0.20/0.39     distinct function count: 5
% 0.20/0.39     distinct constant count: 4
% 0.20/0.39  
% 0.20/0.39  ---------- no more Softie stats ----------
% 0.20/0.39  
% 0.20/0.39  
% 0.20/0.39  
% 0.20/0.39  Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.39  
% 0.20/0.39  Stopped by limit on number of solutions
% 0.20/0.39  
% 0.20/0.39  =========== start of search ===========
% 0.50/0.70  
% 0.50/0.70  -------- PROOF -------- 
% 0.50/0.70  % SZS status Theorem
% 0.50/0.70  % SZS output start Refutation
% 0.50/0.70  
% 0.50/0.70  Stopped by limit on insertions
% 0.50/0.70  
% 0.50/0.70  Model 3 [ 1 0 1199 ] (0.00 seconds, 250000 Inserts)
% 0.50/0.70  
% 0.50/0.70  Model 4 [ 1 1 2004 ] (0.00 seconds, 8413 Inserts)
% 0.50/0.70  
% 0.50/0.70  Stopped by limit on insertions
% 0.50/0.70  
% 0.50/0.70  Model 5 [ 2 1 523 ] (0.00 seconds, 250000 Inserts)
% 0.50/0.70  
% 0.50/0.70  ----> UNIT CONFLICT at   0.33 sec ----> 882 [binary,881.1,9.1] {-} $F.
% 0.50/0.70  
% 0.50/0.70  Length of proof is 6.  Level of proof is 5.
% 0.50/0.70  
% 0.50/0.70  ---------------- PROOF ----------------
% 0.50/0.70  % SZS status Theorem
% 0.50/0.70  % SZS output start Refutation
% 0.50/0.70  
% 0.50/0.70  2 [] {+} -subset(A,B)| -in(C,A)|in(C,B).
% 0.50/0.70  3 [] {+} subset(A,B)| -in($f1(A,B),B).
% 0.50/0.70  4 [] {+} A!=union(B)| -in(C,A)|in(C,$f2(B,A,C)).
% 0.50/0.70  5 [] {+} A!=union(B)| -in(C,A)|in($f2(B,A,C),B).
% 0.50/0.70  6 [] {+} A!=union(B)|in(C,A)| -in(C,D)| -in(D,B).
% 0.50/0.70  9 [] {+} -subset(union($c4),union($c3)).
% 0.50/0.70  12 [] {+} subset(A,B)|in($f1(A,B),A).
% 0.50/0.70  17 [] {+} subset($c4,$c3).
% 0.50/0.70  18 [] {+} A=A.
% 0.50/0.70  19 [hyper,12,9] {-} in($f1(union($c4),union($c3)),union($c4)).
% 0.50/0.70  70 [hyper,19,5,18] {-} in($f2($c4,union($c4),$f1(union($c4),union($c3))),$c4).
% 0.50/0.70  71 [hyper,19,4,18] {-} in($f1(union($c4),union($c3)),$f2($c4,union($c4),$f1(union($c4),union($c3)))).
% 0.50/0.70  96 [hyper,70,2,17] {+} in($f2($c4,union($c4),$f1(union($c4),union($c3))),$c3).
% 0.50/0.70  814 [hyper,71,6,18,96] {-} in($f1(union($c4),union($c3)),union($c3)).
% 0.50/0.70  881 [hyper,814,3] {-} subset(union($c4),union($c3)).
% 0.50/0.70  882 [binary,881.1,9.1] {-} $F.
% 0.50/0.70  
% 0.50/0.70  % SZS output end Refutation
% 0.50/0.70  ------------ end of proof -------------
% 0.50/0.70  
% 0.50/0.70  
% 0.50/0.70  Search stopped by max_proofs option.
% 0.50/0.70  
% 0.50/0.70  
% 0.50/0.70  Search stopped by max_proofs option.
% 0.50/0.70  
% 0.50/0.70  ============ end of search ============
% 0.50/0.70  
% 0.50/0.70  ----------- soft-scott stats ----------
% 0.50/0.70  
% 0.50/0.70  true clauses given           7      (29.2%)
% 0.50/0.70  false clauses given         17
% 0.50/0.70  
% 0.50/0.70        FALSE     TRUE
% 0.50/0.70    12  0         1
% 0.50/0.70    13  0         1
% 0.50/0.70    14  0         4
% 0.50/0.70    15  1         1
% 0.50/0.70    16  4         3
% 0.50/0.70    17  3         5
% 0.50/0.70    18  2         4
% 0.50/0.70    19  6         6
% 0.50/0.70    20  5         18
% 0.50/0.70    21  9         9
% 0.50/0.70    22  11        25
% 0.50/0.70    23  5         26
% 0.50/0.70    24  23        39
% 0.50/0.70    25  20        52
% 0.50/0.70    26  16        24
% 0.50/0.70    27  39        39
% 0.50/0.70    28  18        39
% 0.50/0.70    29  1         40
% 0.50/0.70    30  24        32
% 0.50/0.70    31  9         24
% 0.50/0.70    32  9         17
% 0.50/0.70    33  4         13
% 0.50/0.70    34  10        17
% 0.50/0.70    35  6         9
% 0.50/0.70    36  8         13
% 0.50/0.70    37  4         7
% 0.50/0.70    38  1         3
% 0.50/0.70    39  3         15
% 0.50/0.70    40  4         6
% 0.50/0.70    41  2         5
% 0.50/0.70    42  1         5
% 0.50/0.70    43  0         4
% 0.50/0.70    44  0         7
% 0.50/0.70    45  1         14
% 0.50/0.70    46  1         6
% 0.50/0.70    47  1         3
% 0.50/0.70    48  2         6
% 0.50/0.70    49  2         3
% 0.50/0.70    50  0         2
% 0.50/0.70    51  0         9
% 0.50/0.70    52  1         2
% 0.50/0.70    53  0         3
% 0.50/0.70    54  0         2
% 0.50/0.70    56  0         2
% 0.50/0.70    58  0         1
% 0.50/0.70    60  1         0
% 0.50/0.70  tot:  257       566      (68.8% true)
% 0.50/0.70  
% 0.50/0.70  
% 0.50/0.70  Model 5 [ 2 1 523 ] (0.00 seconds, 250000 Inserts)
% 0.50/0.70  
% 0.50/0.70  That finishes the proof of the theorem.
% 0.50/0.70  
% 0.50/0.70  Process 27880 finished Sun Jul 10 20:21:20 2022
%------------------------------------------------------------------------------