TSTP Solution File: SET904+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET904+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:14:29 EDT 2022

% Result   : Theorem 1.67s 1.89s
% Output   : Refutation 1.67s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    5 (   4 unt;   0 nHn;   5 RR)
%            Number of literals    :    6 (   0 equ;   2 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :    2 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(5,axiom,
    ~ in(dollar_c4,dollar_c3),
    file('SET904+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ subset(set_union2(singleton(A),B),B)
    | in(A,B) ),
    file('SET904+1.p',unknown),
    [] ).

cnf(13,axiom,
    subset(set_union2(singleton(dollar_c4),dollar_c3),dollar_c3),
    file('SET904+1.p',unknown),
    [] ).

cnf(15,plain,
    in(dollar_c4,dollar_c3),
    inference(hyper,[status(thm)],[13,6]),
    [iquote('hyper,13,6')] ).

cnf(16,plain,
    $false,
    inference(binary,[status(thm)],[15,5]),
    [iquote('binary,15.1,5.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : SET904+1 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.11/0.33  % Computer : n027.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit : 300
% 0.11/0.33  % WCLimit  : 300
% 0.11/0.33  % DateTime : Wed Jul 27 10:51:21 EDT 2022
% 0.11/0.33  % CPUTime  : 
% 1.67/1.89  ----- Otter 3.3f, August 2004 -----
% 1.67/1.89  The process was started by sandbox on n027.cluster.edu,
% 1.67/1.89  Wed Jul 27 10:51:22 2022
% 1.67/1.89  The command was "./otter".  The process ID is 24046.
% 1.67/1.89  
% 1.67/1.89  set(prolog_style_variables).
% 1.67/1.89  set(auto).
% 1.67/1.89     dependent: set(auto1).
% 1.67/1.89     dependent: set(process_input).
% 1.67/1.89     dependent: clear(print_kept).
% 1.67/1.89     dependent: clear(print_new_demod).
% 1.67/1.89     dependent: clear(print_back_demod).
% 1.67/1.89     dependent: clear(print_back_sub).
% 1.67/1.89     dependent: set(control_memory).
% 1.67/1.89     dependent: assign(max_mem, 12000).
% 1.67/1.89     dependent: assign(pick_given_ratio, 4).
% 1.67/1.89     dependent: assign(stats_level, 1).
% 1.67/1.89     dependent: assign(max_seconds, 10800).
% 1.67/1.89  clear(print_given).
% 1.67/1.89  
% 1.67/1.89  formula_list(usable).
% 1.67/1.89  all A (A=A).
% 1.67/1.89  all A B (-empty(A)-> -empty(set_union2(A,B))).
% 1.67/1.89  all A B (-empty(A)-> -empty(set_union2(B,A))).
% 1.67/1.89  all A B (set_union2(A,B)=set_union2(B,A)).
% 1.67/1.89  all A B (set_union2(A,A)=A).
% 1.67/1.89  all A B subset(A,A).
% 1.67/1.89  all A B (in(A,B)-> -in(B,A)).
% 1.67/1.89  exists A empty(A).
% 1.67/1.89  exists A (-empty(A)).
% 1.67/1.89  -(all A B (subset(set_union2(singleton(A),B),B)->in(A,B))).
% 1.67/1.89  all A B (subset(set_union2(singleton(A),B),B)->in(A,B)).
% 1.67/1.89  end_of_list.
% 1.67/1.89  
% 1.67/1.89  -------> usable clausifies to:
% 1.67/1.89  
% 1.67/1.89  list(usable).
% 1.67/1.89  0 [] A=A.
% 1.67/1.89  0 [] empty(A)| -empty(set_union2(A,B)).
% 1.67/1.89  0 [] empty(A)| -empty(set_union2(B,A)).
% 1.67/1.89  0 [] set_union2(A,B)=set_union2(B,A).
% 1.67/1.89  0 [] set_union2(A,A)=A.
% 1.67/1.89  0 [] subset(A,A).
% 1.67/1.89  0 [] -in(A,B)| -in(B,A).
% 1.67/1.89  0 [] empty($c1).
% 1.67/1.89  0 [] -empty($c2).
% 1.67/1.89  0 [] subset(set_union2(singleton($c4),$c3),$c3).
% 1.67/1.89  0 [] -in($c4,$c3).
% 1.67/1.89  0 [] -subset(set_union2(singleton(A),B),B)|in(A,B).
% 1.67/1.89  end_of_list.
% 1.67/1.89  
% 1.67/1.89  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=2.
% 1.67/1.89  
% 1.67/1.89  This is a Horn set with equality.  The strategy will be
% 1.67/1.89  Knuth-Bendix and hyper_res, with positive clauses in
% 1.67/1.89  sos and nonpositive clauses in usable.
% 1.67/1.89  
% 1.67/1.89     dependent: set(knuth_bendix).
% 1.67/1.89     dependent: set(anl_eq).
% 1.67/1.89     dependent: set(para_from).
% 1.67/1.89     dependent: set(para_into).
% 1.67/1.89     dependent: clear(para_from_right).
% 1.67/1.89     dependent: clear(para_into_right).
% 1.67/1.89     dependent: set(para_from_vars).
% 1.67/1.89     dependent: set(eq_units_both_ways).
% 1.67/1.89     dependent: set(dynamic_demod_all).
% 1.67/1.89     dependent: set(dynamic_demod).
% 1.67/1.89     dependent: set(order_eq).
% 1.67/1.89     dependent: set(back_demod).
% 1.67/1.89     dependent: set(lrpo).
% 1.67/1.89     dependent: set(hyper_res).
% 1.67/1.89     dependent: clear(order_hyper).
% 1.67/1.89  
% 1.67/1.89  ------------> process usable:
% 1.67/1.89  ** KEPT (pick-wt=6): 1 [] empty(A)| -empty(set_union2(A,B)).
% 1.67/1.89  ** KEPT (pick-wt=6): 2 [] empty(A)| -empty(set_union2(B,A)).
% 1.67/1.89  ** KEPT (pick-wt=6): 3 [] -in(A,B)| -in(B,A).
% 1.67/1.89  ** KEPT (pick-wt=2): 4 [] -empty($c2).
% 1.67/1.89  ** KEPT (pick-wt=3): 5 [] -in($c4,$c3).
% 1.67/1.89  ** KEPT (pick-wt=9): 6 [] -subset(set_union2(singleton(A),B),B)|in(A,B).
% 1.67/1.89  
% 1.67/1.89  ------------> process sos:
% 1.67/1.89  ** KEPT (pick-wt=3): 7 [] A=A.
% 1.67/1.89  ** KEPT (pick-wt=7): 8 [] set_union2(A,B)=set_union2(B,A).
% 1.67/1.89  ** KEPT (pick-wt=5): 9 [] set_union2(A,A)=A.
% 1.67/1.89  ---> New Demodulator: 10 [new_demod,9] set_union2(A,A)=A.
% 1.67/1.89  ** KEPT (pick-wt=3): 11 [] subset(A,A).
% 1.67/1.89  ** KEPT (pick-wt=2): 12 [] empty($c1).
% 1.67/1.89  ** KEPT (pick-wt=6): 13 [] subset(set_union2(singleton($c4),$c3),$c3).
% 1.67/1.89    Following clause subsumed by 7 during input processing: 0 [copy,7,flip.1] A=A.
% 1.67/1.89    Following clause subsumed by 8 during input processing: 0 [copy,8,flip.1] set_union2(A,B)=set_union2(B,A).
% 1.67/1.89  >>>> Starting back demodulation with 10.
% 1.67/1.89  
% 1.67/1.89  ======= end of input processing =======
% 1.67/1.89  
% 1.67/1.89  =========== start of search ===========
% 1.67/1.89  
% 1.67/1.89  -------- PROOF -------- 
% 1.67/1.89  
% 1.67/1.89  ----> UNIT CONFLICT at   0.00 sec ----> 16 [binary,15.1,5.1] $F.
% 1.67/1.89  
% 1.67/1.89  Length of proof is 1.  Level of proof is 1.
% 1.67/1.89  
% 1.67/1.89  ---------------- PROOF ----------------
% 1.67/1.89  % SZS status Theorem
% 1.67/1.89  % SZS output start Refutation
% See solution above
% 1.67/1.89  ------------ end of proof -------------
% 1.67/1.89  
% 1.67/1.89  
% 1.67/1.89  Search stopped by max_proofs option.
% 1.67/1.89  
% 1.67/1.89  
% 1.67/1.89  Search stopped by max_proofs option.
% 1.67/1.89  
% 1.67/1.89  ============ end of search ============
% 1.67/1.89  
% 1.67/1.89  -------------- statistics -------------
% 1.67/1.89  clauses given                  5
% 1.67/1.89  clauses generated              6
% 1.67/1.89  clauses kept                  14
% 1.67/1.89  clauses forward subsumed       4
% 1.67/1.89  clauses back subsumed          0
% 1.67/1.89  Kbytes malloced              976
% 1.67/1.89  
% 1.67/1.89  ----------- times (seconds) -----------
% 1.67/1.89  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.89  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.67/1.89  
% 1.67/1.89  That finishes the proof of the theorem.
% 1.67/1.89  
% 1.67/1.89  Process 24046 finished Wed Jul 27 10:51:23 2022
% 1.67/1.89  Otter interrupted
% 1.67/1.89  PROOF FOUND
%------------------------------------------------------------------------------