TSTP Solution File: SET900+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 05:21:40 EDT 2022

% Result   : Theorem 0.18s 0.38s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% 0.07/0.13  % Command  : sos-script %s
% 0.12/0.34  % Computer : n012.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Sun Jul 10 00:53:58 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox on n012.cluster.edu,
% 0.12/0.35  Sun Jul 10 00:53:58 2022
% 0.12/0.35  The command was "./sos".  The process ID is 11678.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  formula_list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 0.12/0.35  
% 0.12/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.12/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35  clauses in usable.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35     dependent: set(hyper_res).
% 0.12/0.35     dependent: set(unit_deletion).
% 0.12/0.35     dependent: set(factor).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 13 during input processing: 0 [copy,13,flip.1] {-} A=A.
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.18/0.38  
% 0.18/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.18/0.38  
% 0.18/0.38  Stopped by limit on number of solutions
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  -------------- Softie stats --------------
% 0.18/0.38  
% 0.18/0.38  UPDATE_STOP: 300
% 0.18/0.38  SFINDER_TIME_LIMIT: 2
% 0.18/0.38  SHORT_CLAUSE_CUTOFF: 4
% 0.18/0.38  number of clauses in intial UL: 7
% 0.18/0.38  number of clauses initially in problem: 11
% 0.18/0.38  percentage of clauses intially in UL: 63
% 0.18/0.38  percentage of distinct symbols occuring in initial UL: 90
% 0.18/0.38  percent of all initial clauses that are short: 100
% 0.18/0.38  absolute distinct symbol count: 10
% 0.18/0.38     distinct predicate count: 3
% 0.18/0.38     distinct function count: 2
% 0.18/0.38     distinct constant count: 5
% 0.18/0.38  
% 0.18/0.38  ---------- no more Softie stats ----------
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  =========== start of search ===========
% 0.18/0.38  
% 0.18/0.38  -------- PROOF -------- 
% 0.18/0.38  % SZS status Theorem
% 0.18/0.38  % SZS output start Refutation
% 0.18/0.38  
% 0.18/0.38  -----> EMPTY CLAUSE at   0.01 sec ----> 32 [hyper,15,8,unit_del,4,4,6] {-} $F.
% 0.18/0.38  
% 0.18/0.38  Length of proof is 3.  Level of proof is 2.
% 0.18/0.38  
% 0.18/0.38  ---------------- PROOF ----------------
% 0.18/0.38  % SZS status Theorem
% 0.18/0.38  % SZS output start Refutation
% 0.18/0.38  
% 0.18/0.38  3 [] {-} $c4!=singleton($c3).
% 0.18/0.38  4 [copy,3,flip.1] {+} singleton($c3)!=$c4.
% 0.18/0.38  5 [] {-} $c4!=empty_set.
% 0.18/0.38  6 [copy,5,flip.1] {+} empty_set!=$c4.
% 0.18/0.38  7 [] {+} -in(A,$c4)|A=$c3.
% 0.18/0.38  8 [] {+} A=singleton(B)|A=empty_set|$f1(A,B)!=B.
% 0.18/0.38  12 [] {-} A=singleton(B)|A=empty_set|in($f1(A,B),A).
% 0.18/0.38  15 [hyper,12,7,unit_del,6,flip.1] {-} singleton(A)=$c4|$f1($c4,A)=$c3.
% 0.18/0.38  32 [hyper,15,8,unit_del,4,4,6] {-} $F.
% 0.18/0.38  
% 0.18/0.38  % SZS output end Refutation
% 0.18/0.38  ------------ end of proof -------------
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  Search stopped by max_proofs option.
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  Search stopped by max_proofs option.
% 0.18/0.38  
% 0.18/0.38  ============ end of search ============
% 0.18/0.38  
% 0.18/0.38  ----------- soft-scott stats ----------
% 0.18/0.38  
% 0.18/0.38  true clauses given           1      (33.3%)
% 0.18/0.38  false clauses given          2
% 0.18/0.38  
% 0.18/0.38        FALSE     TRUE
% 0.18/0.38     2  0         1
% 0.18/0.38     3  0         1
% 0.18/0.38     5  0         1
% 0.18/0.38     9  1         0
% 0.18/0.38    11  1         0
% 0.18/0.38    12  1         0
% 0.18/0.38    13  0         2
% 0.18/0.38    15  1         2
% 0.18/0.38    23  0         2
% 0.18/0.38    25  2         2
% 0.18/0.38  tot:  6         11      (64.7% true)
% 0.18/0.38  
% 0.18/0.38  
% 0.18/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.18/0.38  
% 0.18/0.38  That finishes the proof of the theorem.
% 0.18/0.38  
% 0.18/0.38  Process 11678 finished Sun Jul 10 00:53:58 2022
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