TSTP Solution File: SET900+1 by Metis---2.4
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%------------------------------------------------------------------------------
% File : Metis---2.4
% Problem : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp:raw
% Command : metis --show proof --show saturation %s
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Tue Jul 19 03:38:12 EDT 2022
% Result : Theorem 0.13s 0.35s
% Output : CNFRefutation 0.13s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 2
% Syntax : Number of formulae : 9 ( 2 unt; 0 def)
% Number of atoms : 30 ( 21 equ)
% Maximal formula atoms : 4 ( 3 avg)
% Number of connectives : 47 ( 26 ~; 5 |; 14 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 10 ( 7 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 2 ( 2 usr; 1 con; 0-1 aty)
% Number of variables : 21 ( 0 sgn 17 !; 4 ?)
% Comments :
%------------------------------------------------------------------------------
fof(t41_zfmisc_1,conjecture,
! [A,B] :
~ ( A != singleton(B)
& A != empty_set
& ! [C] :
~ ( in(C,A)
& C != B ) ) ).
fof(l45_zfmisc_1,axiom,
! [A,B] :
~ ( A != singleton(B)
& A != empty_set
& ! [C] :
~ ( in(C,A)
& C != B ) ) ).
fof(subgoal_0,plain,
! [A,B] :
( ( A != singleton(B)
& A != empty_set )
=> ~ ! [C] :
~ ( in(C,A)
& C != B ) ),
inference(strip,[],[t41_zfmisc_1]) ).
fof(negate_0_0,plain,
~ ! [A,B] :
( ( A != singleton(B)
& A != empty_set )
=> ~ ! [C] :
~ ( in(C,A)
& C != B ) ),
inference(negate,[],[subgoal_0]) ).
fof(normalize_0_0,plain,
? [A,B] :
( A != empty_set
& A != singleton(B)
& ! [C] :
( ~ in(C,A)
| C = B ) ),
inference(canonicalize,[],[negate_0_0]) ).
fof(normalize_0_1,plain,
! [A,B] :
( A = empty_set
| A = singleton(B)
| ? [C] :
( C != B
& in(C,A) ) ),
inference(canonicalize,[],[l45_zfmisc_1]) ).
fof(normalize_0_2,plain,
! [A,B] :
( A = empty_set
| A = singleton(B)
| ? [C] :
( C != B
& in(C,A) ) ),
inference(specialize,[],[normalize_0_1]) ).
fof(normalize_0_3,plain,
$false,
inference(simplify,[],[normalize_0_0,normalize_0_2]) ).
cnf(refute_0_0,plain,
$false,
inference(canonicalize,[],[normalize_0_3]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : SET900+1 : TPTP v8.1.0. Released v3.2.0.
% 0.11/0.13 % Command : metis --show proof --show saturation %s
% 0.13/0.34 % Computer : n004.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Sun Jul 10 00:50:22 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.34 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.13/0.35 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.13/0.35
% 0.13/0.35 % SZS output start CNFRefutation for /export/starexec/sandbox2/benchmark/theBenchmark.p
% See solution above
% 0.13/0.35
%------------------------------------------------------------------------------